grep without showing path/file:line

LinuxUnixGrepFind

Linux Problem Overview

How do you grep and only return the matching line? i.e. The path/filename is omitted from the results.

In this case I want to look in all .bar files in the current directory, searching for the term FOO

find . -name '*.bar' -exec grep -Hn FOO {} \;

Linux Solutions

Solution 1 - Linux

No need to find. If you are just looking for a pattern within a specific directory, this should suffice:

grep -hn FOO /your/path/*.bar

Where -h is the parameter to hide the filename, as from man grep:

> -h, --no-filename > > Suppress the prefixing of file names on output. This is the default > when there is only one file (or only standard input) to search.

Note that you were using

> -H, --with-filename > > Print the file name for each match. This is the default when there is > more than one file to search.

Solution 2 - Linux

Just replace -H with -h. Check man grep for more details on options

find . -name '*.bar' -exec grep -hn FOO {} \;

Solution 3 - Linux

From the man page:

-h, --no-filename
    Suppress the prefixing of file names on output. This is the default when there
    is only one file (or only standard input) to search.
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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionAllan ThomasView Question on Stackoverflow
Solution 1 - LinuxfedorquiView Answer on Stackoverflow
Solution 2 - LinuxjkshahView Answer on Stackoverflow
Solution 3 - LinuxTC1View Answer on Stackoverflow