You are looking for `-H` option in gnu grep.

    find . -name &#39;*bills*&#39; -exec grep -H &quot;put&quot; {} \;

### Here is the explanation
        -H, --with-filename
	      Print the filename for each match.

Now that the question is clearer, you can just do this in one [tag:grep]

    grep -R --include &quot;*bills*&quot; &quot;put&quot; .

With relevant flags

       -R, -r, --recursive
              Read  all  files  under  each  directory,  recursively;  this is
              equivalent to the -d recurse option.
       --include=GLOB
              Search only files whose base name matches GLOB  (using  wildcard
              matching as described under --exclude).




Or maybe even easier

```
grep -R put **/*bills*
```

The `**` glob syntax means &quot;any depth of directories&quot;.  It will work in Zsh, and I think recent versions of Bash too. 

    grep -l &quot;$SEARCH_TEXT&quot; $(find &quot;$SEARCH_DIR&quot; -name &quot;$TARGET_FILE_NAME&quot;)

 
I have: 

 - a function: `def find_str(s, char)`

 

 - and a string: `&quot;Happy Birthday&quot;`,

I essentially want to input `&quot;py&quot;` and return `3` but I keep getting `2` to return instead. 

**Code:** 

    def find_str(s, char):
    	index = 0    	    
        if char in s:
            char = char[0]
    	    for ch in s:
                if ch in s:
                    index += 1
    		    if ch == char:
                    return index
    					
        else:
    	    return -1
    		
    print(find_str(&quot;Happy birthday&quot;, &quot;py&quot;))

Not sure what&#39;s wrong!

Python: Find a substring in a string and returning the index of the substring

I was looking for a way to run an external process from python script and print its stdout messages during the execution.  
The code below works, but prints no stdout output during runtime. When it exits I am getting the following error:

&gt;  sys.stdout.write(nextline) TypeError:must be str,not bytes

    p = subprocess.Popen([&quot;demo.exe&quot;],stdout = subprocess.PIPE, stderr= subprocess.PIPE)	
    # Poll process for new output until finished
    while True:
        nextline = p.stdout.readline()
        if nextline == &#39;&#39; and p.poll() != None:
            break
        sys.stdout.write(nextline)
        sys.stdout.flush()

    output = p.communicate()[0]
    exitCode = p.returncode


I am using python 3.3.2

Python 3 TypeError: must be str, not bytes with sys.stdout.write()

I am trying to find a command or create a Linux script that can do this two comands and list the otuput

    find . -name &#39;*bills*&#39; -print

this prints all the files

    ./may/batch_bills_123.log
    ./april/batch_bills_456.log
    ..

from this result I want to do a grep for a word I do this manually right now


    grep &#39;put&#39; ./may/batch_bill_123.log 

and get

    sftp &gt; put oldnet_1234.lst

I would hope to get the file name and its match.

    ./may/batch_bills_123.log   sftp &gt; put oldnet_1234.lst
    ..
    ..
    and so on... 

any ideas?

Linux find and grep command together

I am trying to find a command or create a Linux script that can do this two comands and list the otuput
<pre><code class="hljs language-arduino">find . -name '*bills*' -print
</code></pre>
this prints all the files
<pre><code class="hljs language-bash">./may/batch_bills_123.log
./april/batch_bills_456.log
..
</code></pre>
from this result I want to do a grep for a word I do this manually right now
<pre><code class="hljs language-bash">grep 'put' ./may/batch_bill_123.log 
</code></pre>
and get
<pre><code class="hljs language-arduino">sftp > put oldnet_1234.lst
</code></pre>
I would hope to get the file name and its match.
<pre><code class="hljs language-bash">./may/batch_bills_123.log sftp > put oldnet_1234.lst
..
..
and so on... 
</code></pre>
any ideas?

I am using bash to to POST to a website that requires that I be logged in first. So I need to send the request with login cookie. So I tried logging in and keeping the cookies, but it doesn&#39;t work because the site uses javascript to hash the password in a really weird fashion, so instead I&#39;m going to just take my login cookies for the site from Chrome. How do get the cookies from Chrome and format them for Curl?

I&#39;m trying to do this: 
 
&lt;!-- language: bash --&gt;

    curl --request POST -d &quot;a=X&amp;b=Y&quot; -b &quot;what goes here?&quot; &quot;site.com/a.php&quot;

How do I copy cookies from Chrome?

I want to recursively iterate through a directory and change the extension of all files of a certain extension, say `.t1` to `.t2`. What is the bash command for doing this?

Recursively change file extensions in Bash

I&#39;m writing a shell script and need to check that a terminal app has been installed. I want to use a TRY/CATCH command to do this unless there is a neater way.

Is there a TRY CATCH command in Bash

For a given folder, how can I delete all broken links within it?

I found [this answer](https://stackoverflow.com/questions/3637952/deleting-a-broken-link-unix) that shows how to delete one broken link, but I can&#39;t put that together in only one line. Is there a one-liner for this?

A broken symbolic is a link that points to  a file/folder that doesn&#39;t exists any longer.

Delete all broken symbolic links with a line?

I&#39;m trying to replace `/./` or `/././` or `/./././` to `/` only in bash script. I&#39;ve managed to create regex for sed but it doesn&#39;t work.

    variable=&quot;something/./././&quot;
    variable=$(echo $variable | sed &quot;s/\/(\.\/)+/\//g&quot;)
    echo $variable # this should output &quot;something/&quot;

When I tried to replace only `/./` substring it worked with regex in sed `\/\.\/`. Does sed regex requires more flags to use multiplication of substring with `+` or `*`?

sed plus sign doesn&#39;t work

Example:

    a43
    test1
    abc
    cvb
    bnm
    test2
    kfo


I need all lines between test1 and test2. Normal grep does not work in this case. Do you have any propositions?

Bash, grep between two lines with specified string

I&#39;ve got a grep script that searches through a directory recursively.

    grep -n -R -e &#39;search term&#39; -e &#39;second search term&#39; ./ 


However the results I get are the following. Notice there are found matches in JPGs but no actual result. 

    Binary file ./jpg/00015928.jpg matches
    Binary file ./jpg/00015296.jpg matches
    Binary file ./jpg/00020072.jpg matches

Is there any way to see the result in the output like a normal grep search? 



Grep &#39;binary file matches&#39;. How to get normal grep output?

I have bunch of files sitting in folders like

    data\A\A\A\json1.json
    data\A\A\A\json2.json
    data\A\A\B\json1.json
    ...
    data\Z\Z\Z\json_x.json

I want to cat all the jsons into one single file?


Recursively cat all the files into single file

When using `grep` in linux, the result often contains a lot of &quot;binary file XXX matches&quot;, which I do not care about. How to suppress this part of the results, or how to exclude binary files in grep?

How to suppress binary file matching results in grep

I need to check if the recipient username is in file */etc/passwd* which contains all the users in my class, but I have tried a few different combinations of *if* statements and *[grep][1]* without success. The best I could come up with is below, but I don&#39;t think it&#39;s working properly.

My logic behind it is that if the *grep* is null, the user is invalid.

    send_email()
    {
      message=
      address=
      attachment=
      validuser=1
      until [ &quot;$validuser&quot; = &quot;0&quot; ]
        do
        echo &quot;Enter the email address: &quot;
        read address
        if [ -z grep $address /etc/passwd ]
          then
        validuser=0
        else
            validuser=1
        fi
        echo -n &quot;Enter the subject of the message: &quot;
        read message
        echo &quot;&quot;
        echo &quot;Enter the file you want to attach: &quot;
        read attachment
        mail -s &quot;$message&quot; &quot;$address&quot;&lt;&quot;$attachment&quot;
        done
        press_enter
    }

  [1]: https://en.wikipedia.org/wiki/Grep




How can I check if &#39;grep&#39; doesn&#39;t have any output?

I am trying to open a CSV file but for some reason python cannot locate it.

Here is my code (it&#39;s just a simple code but I cannot solve the problem):

    import csv

    with open(&#39;address.csv&#39;,&#39;r&#39;) as f:
        reader = csv.reader(f)
        for row in reader:
            print row

FileNotFoundError: [Errno 2] No such file or directory

If I have a list of filenames in a text file that I want to exclude when I run `find`, how can I do that? For example, I want to do something like:

    find /dir -name &quot;*.gz&quot; -exclude_from skip_files

and get all the .gz files in /dir except for the files listed in skip_files. But find has no `-exclude_from` flag. How can I skip all the files in `skip_files`?

Exclude list of files from find

CentOS. Need to find files modified in last 30 days to see if any of them have been infected with malware.

I tried this:

    root@server [/home/someuser/public_html/]# find . -mtime +30
     -exec ls -l {} &gt; last30days.txt \;

But instead of the last 30 days, it seems to have found everything. 22,000 files.

Get all files modified in last 30 days in a directory

I am trying to save the result from `find` as arrays.
Here is my code:

    #!/bin/bash
    
    echo &quot;input : &quot;
    read input
    
    echo &quot;searching file with this pattern &#39;${input}&#39; under present directory&quot;
    array=`find . -name ${input}`
    
    len=${#array[*]}
    echo &quot;found : ${len}&quot;
    
    i=0
    
    while [ $i -lt $len ]
    do
    echo ${array[$i]}
    let i++
    done

I get 2 .txt files under current directory.
So I expect &#39;2&#39; as result of `${len}`. However, it prints 1.
The reason is that it takes all result of `find` as one elements.
How can I fix this?

P.S  
I found several solutions on StackOverFlow about a similar problem. However, they are a little bit different so I can&#39;t apply in my case. I need to store the results in a variable before the loop. Thanks again.



How can I store the &quot;find&quot; command results as an array in Bash

Ideally, I would be able to use a program like 

    find [file or directory name]

to report the paths with matching filenames/directories. Unfortunately this seems to only check the current directory, not the entire folder.

I&#39;ve also tried locate and which, but none find the file, even though I know its on the computer somewhere.

Content Type	Original Author	Original Content on Stackoverflow
Question	user3307574	View Question on Stackoverflow
Solution 1 - Bash	BMW	View Answer on Stackoverflow
Solution 2 - Bash	Reinstate Monica Please	View Answer on Stackoverflow
Solution 3 - Bash	Dalin	View Answer on Stackoverflow
Solution 4 - Bash	F. P. Freely	View Answer on Stackoverflow

Linux find and grep command together

Bash Problem Overview

Bash Solutions

Solution 1 - Bash

Here is the explanation

Solution 2 - Bash

Solution 3 - Bash

Solution 4 - Bash

Python 3 TypeError: must be str, not bytes with sys.stdout.write()

Python: Find a substring in a string and returning the index of the substring

Attributions