How do I remove http, https and slash from user input in php

Example user input

http://domain.com/
http://domain.com/topic/
http://domain.com/topic/cars/
http://www.domain.com/topic/questions/

I want a php function to make the output like

domain.com
domain.com/topic/
domain.com/topic/cars/
www.domain.com/topic/questions/

Let me know :)

ereg_replace is now deprecated, so it is better to use:

$url = preg_replace("(^https?://)", "", $url );

This removes either http:// or https://

You should use an array of "disallowed" terms and use strpos and str_replace to dynamically remove them from the passed-in URL:

function remove_http($url) {
   $disallowed = array('http://', 'https://');
   foreach($disallowed as $d) {
      if(strpos($url, $d) === 0) {
         return str_replace($d, '', $url);
      }
   }
   return $url;
}

I'd suggest using the tools PHP gave you, have a look at parse_url.

<?php
$url = 'http://username:password@hostname/path?arg=value#anchor';

print_r(parse_url($url));

echo parse_url($url, PHP_URL_PATH);
?>

The above example will output:

Array
(
    [scheme] => http
    [host] => hostname
    [user] => username
    [pass] => password
    [path] => /path
    [query] => arg=value
    [fragment] => anchor
)
/path

It sounds like you're after at least host + path (add others as needed, e.g. query):

$parsed = parse_url('http://www.domain.com/topic/questions/');

echo $parsed['host'], $parsed['path'];

    > www.domain.com/topic/questions/

Cheers

Create an array:

$remove = array("http://","https://");

and replace with empty string:

str_replace($remove,"",$url);

it would look something like this:

function removeProtocol($url){
    $remove = array("http://","https://");
    return str_replace($remove,"",$url);
}

Str_replace will return a string if your haystack (input) is a string and you replace your needle(s) in the array with a string. It's nice so you can avoid all the extra looping.

You can remove both https and http in one line using ereg_replace:

$url = ereg_replace("(https?)://", "", $url);

Wow. I came here from google expecting to find a one liner to copy and paste!

You don't need a function to do this because one already exists. Just do:

echo explode("//", "https://anyurl.any.tld/any/directory/structure", 2)[1];

In this example, explode() will return an array of:

["https:", "anyurl.any.tld/any/directory/structure"]

And we want the 2nd element. This will handle http, https, ftp, or pretty much any URI, without needing regex.

https://www.php.net/manual/en/function.explode.php

If you want a function:

function removeProtocols($uri) { return explode("//", $uri, 2)[1]; }

EDIT: See user comment from Harry Lewis... this is my favourite way to do this now.

You could use the parse url Functionality of PHP. This will work for all Protocols, even ftp:// or https://

Eiter get the Protocol Component and substr it from the Url, or just concatenate the other Parts back together ...

http://php.net/manual/de/function.parse-url.php

<?php
// user input
$url = 'http://www.example.com/category/website/wordpress/wordpress-security/';
$url0 = 'http://www.example.com/';
$url1 = 'http://www.example.com/category/';
$url2 = 'http://www.example.com/category/website/';
$url3 = 'http://www.example.com/category/website/wordpress/';

// print_r(parse_url($url));
// echo parse_url($url, PHP_URL_PATH);

$removeprotocols = array('http://', 'https://');

echo '<br>' . str_replace($removeprotocols,"",$url0);
echo '<br>' . str_replace($removeprotocols,"",$url1);
echo '<br>' . str_replace($removeprotocols,"",$url2);
echo '<br>' . str_replace($removeprotocols,"",$url3);

?>

if its the first characters in the string you can use substr(0,8) , and it will remove the first 8th character if its not use the "str_replace()" function http://php.net/manual/en/function.str-replace.php

Found this http://refactormycode.com/codes/598-remove-http-from-url-string

function remove_http($url = '')
{
	if ($url == 'http://' OR $url == 'https://')
	{
		return $url;
	}
	$matches = substr($url, 0, 7);
	if ($matches=='http://') 
	{
		$url = substr($url, 7);		
	}
	else
	{
		$matches = substr($url, 0, 8);
		if ($matches=='https://') 
		$url = substr($url, 8);
	}
	return $url;
}