file_get_contents when url doesn't exist

PhpFile Get-Contents

Php Problem Overview


I'm using file_get_contents() to access a URL.

file_get_contents('http://somenotrealurl.com/notrealpage');

If the URL is not real, it return this error message. How can I get it to error gracefully so that I know that the page doesn't exist and act accordingly without displaying this error message?

file_get_contents('http://somenotrealurl.com/notrealpage') 
[function.file-get-contents]: 
failed to open stream: HTTP request failed! HTTP/1.0 404 Not Found 
in myphppage.php on line 3

for example in zend you can say: if ($request->isSuccessful())

$client = New Zend_Http_Client();
$client->setUri('http://someurl.com/somepage');

$request = $client->request();

if ($request->isSuccessful()) {
 //do stuff with the result
}

Php Solutions


Solution 1 - Php

You need to check the HTTP response code:

function get_http_response_code($url) {
    $headers = get_headers($url);
    return substr($headers[0], 9, 3);
}
if(get_http_response_code('http://somenotrealurl.com/notrealpage') != "200"){
    echo "error";
}else{
    file_get_contents('http://somenotrealurl.com/notrealpage');
}

Solution 2 - Php

With such commands in PHP, you can prefix them with an @ to suppress such warnings.

@file_get_contents('http://somenotrealurl.com/notrealpage');

file_get_contents() returns FALSE if a failure occurs, so if you check the returned result against that then you can handle the failure

$pageDocument = @file_get_contents('http://somenotrealurl.com/notrealpage');

if ($pageDocument === false) {
    // Handle error
}

Solution 3 - Php

Each time you call file_get_contents with an http wrapper, a variable in local scope is created: $http_response_header

This variable contains all HTTP headers. This method is better over get_headers() function since only one request is executed.

Note: 2 different requests can end differently. For example, get_headers() will return 503 and file_get_contents() would return 200. And you would get proper output but would not use it due to 503 error in get_headers() call.

function getUrl($url) {
	$content = file_get_contents($url);
	// you can add some code to extract/parse response number from first header. 
    // For example from "HTTP/1.1 200 OK" string.
	return array(
			'headers' => $http_response_header,
			'content' => $content
		);
}

// Handle 40x and 50x errors
$response = getUrl("http://example.com/secret-message");
if ($response['content'] === FALSE)
	echo $response['headers'][0];   // HTTP/1.1 401 Unauthorized
else
    echo $response['content'];

This aproach also alows you to have track of few request headers stored in different variables since if you use file_get_contents() $http_response_header is overwritten in local scope.

Solution 4 - Php

While file_get_contents is very terse and convenient, I tend to favour the Curl library for better control. Here's an example.

function fetchUrl($uri) {
    $handle = curl_init();
    
    curl_setopt($handle, CURLOPT_URL, $uri);
    curl_setopt($handle, CURLOPT_POST, false);
    curl_setopt($handle, CURLOPT_BINARYTRANSFER, false);
    curl_setopt($handle, CURLOPT_HEADER, true);
    curl_setopt($handle, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($handle, CURLOPT_CONNECTTIMEOUT, 10);
    
    $response = curl_exec($handle);
    $hlength  = curl_getinfo($handle, CURLINFO_HEADER_SIZE);
    $httpCode = curl_getinfo($handle, CURLINFO_HTTP_CODE);
    $body     = substr($response, $hlength);
    
    // If HTTP response is not 200, throw exception
    if ($httpCode != 200) {
        throw new Exception($httpCode);
    }
    
    return $body;
}

$url = 'http://some.host.com/path/to/doc';

try {
    $response = fetchUrl($url);
} catch (Exception $e) {
    error_log('Fetch URL failed: ' . $e->getMessage() . ' for ' . $url);
}

Solution 5 - Php

Simple and functional (easy to use anywhere):

function file_contents_exist($url, $response_code = 200)
{
    $headers = get_headers($url);

    if (substr($headers[0], 9, 3) == $response_code)
    {
        return TRUE;
    }
    else
    {
        return FALSE;
    }
}

Example:

$file_path = 'http://www.google.com';

if(file_contents_exist($file_path))
{
    $file = file_get_contents($file_path);
}

Solution 6 - Php

To avoid double requests as commented by Orbling on the answer of ynh you could combine their answers. If you get a valid response in the first place, use that. If not find out what the problem was (if needed).

$urlToGet = 'http://somenotrealurl.com/notrealpage';
$pageDocument = @file_get_contents($urlToGet);
if ($pageDocument === false) {
     $headers = get_headers($urlToGet);
     $responseCode = substr($headers[0], 9, 3);
     // Handle errors based on response code
     if ($responseCode == '404') {
         //do something, page is missing
     }
     // Etc.
} else {
     // Use $pageDocument, echo or whatever you are doing
}

Solution 7 - Php

You may add 'ignore_errors' => true to options:

$options = array(
  'http' => array(
    'ignore_errors' => true,
    'header' => "Content-Type: application/json\r\n"
    )
);
$context  = stream_context_create($options);
$result = file_get_contents('http://example.com', false, $context);

In that case you will be able to read a response from the server.

Solution 8 - Php

$url = 'https://www.yourdomain.com';

Normal

function checkOnline($url) {
    $headers = get_headers($url);
    $code = substr($headers[0], 9, 3);
    if ($code == 200) {
        return true;
    }
    return false;
}

if (checkOnline($url)) {
    // URL is online, do something..
    $getURL = file_get_contents($url);     
} else {
    // URL is offline, throw an error..
}

Pro

if (substr(get_headers($url)[0], 9, 3) == 200) {
    // URL is online, do something..
}

Wtf level

(substr(get_headers($url)[0], 9, 3) == 200) ? echo 'Online' : echo 'Offline';

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionsamiView Question on Stackoverflow
Solution 1 - PhpynhView Answer on Stackoverflow
Solution 2 - PhpOrblingView Answer on Stackoverflow
Solution 3 - PhpGrzegorzView Answer on Stackoverflow
Solution 4 - Phpnikc.orgView Answer on Stackoverflow
Solution 5 - PhptfontView Answer on Stackoverflow
Solution 6 - PhpKuijkensView Answer on Stackoverflow
Solution 7 - PhpalniksView Answer on Stackoverflow
Solution 8 - PhpSixSenseView Answer on Stackoverflow