How do I print all POST results when a form is submitted?
PhpPostEchoPhp Problem Overview
I need to see all of the POST results that are submitted to the server for testing.
What would be an example of how I can create a new file to submit to that will echo out all of the fields which were submitted with that form?
It's dynamic, so some fields may have a name/ID of field1, field2, field3, etc.
Php Solutions
Solution 1 - Php
All the values are stored in the $_POST collection
<?php print_r($_POST); ?>
or if you want something fancier that is easier to read use a foreach loop to loop through the $_POST collection and print the values.
<table>
<?php
foreach ($_POST as $key => $value) {
echo "<tr>";
echo "<td>";
echo $key;
echo "</td>";
echo "<td>";
echo $value;
echo "</td>";
echo "</tr>";
}
?>
</table>
Solution 2 - Php
You could try var_dump:
var_dump($_POST)
Solution 3 - Php
Simply:
<?php
print_r($_POST);
//Or:
foreach ($_POST as $key => $value)
echo $key.'='.$value.'<br />';
?>
Solution 4 - Php
You may mean something like this:
<?php
$output = var_export($_POST, true);
error_log($output, 0, "/path/to/file.log");
?>
Solution 5 - Php
You could use something as simple as this
<?php
print_r($_POST);
?>
This would make it a bit more viewable:
<?php
echo str_replace(' ', ' ', nl2br(print_r($_POST, true)));
?>
Solution 6 - Php
You can definitely use var_dump, but you mentioned you are in front-end development. I am sure you would know this, but just as a reminder, use Firefox's Firebug or Chrome's / Internet Explorer's developers tool and check for the post. Post goes through hearders, and you should be able to check it from there too.
Solution 7 - Php
if (! function_exists('d'))
{
// Debugger
function d($var, $exit = 0)
{
// Only output on localhost
if ($_SERVER['HTTP_HOST'] != 'localhost')
{
return;
}
echo "\n[degug_output_BEGIN]<pre>\n";
echo var_export($var, 1);
echo "\n</pre>[degug_output_END]\n";
if ($exit)
exit;
}
}
// Call:
d($_POST);
Bonus: Check debug_backtrace() too add tracing to your debugging.