How to check, if a php string contains only english letters and digits?

In JS I used this code:

if(string.match(/[^A-Za-z0-9]+/))

but I don't know, how to do it in PHP.

Use preg_match().

if (!preg_match('/[^A-Za-z0-9]/', $string)) // '/[^a-z\d]/i' should also work.
{
  // string contains only english letters & digits
}

if(ctype_alnum($string)) {
    echo "String contains only letters and numbers.";
}
else {
    echo "String doesn't contain only letters and numbers.";
}

You can use preg_match() function for example.

if (preg_match('/[^A-Za-z0-9]+/', $str))
{
  // ok...
}

if you need to check if it is English or not. you could use below function. might help someone..

function is_english($str)
{
    if (strlen($str) != strlen(utf8_decode($str))) {
        return false;
    } else {
        return true;
    }
}

Have a look at this shortcut

if(!preg_match('/[^\W_ ] /',$string)) {

}

the class [^\W_] matches any letter or digit but not underscore . And note the ! symbol . It will save you from scanning entire user input .

if(preg_match('/[^A-Za-z0-9]+/', $str)) {
    // ...
}

if (preg_match('/^[\w\s?]+$/si', $string)) {
    // input text is just English or Numeric or space
}

if(preg_match('/^[A-Za-z0-9]+$/i', $string)){ // '/^[A-Z-a-z\d]+$/i' should work also
// $string constains both string and integer
}

The carrot was in the wrong place so it would have search for everything but what is inside the square brackets. When the carrot is outside it searches for what is in the square brackets.

PHP can compare a string to a regular expression using preg_match(regex, string) like this:

if (!preg_match('/[^A-Za-z0-9]+/', $string)) {
	// $string contains only English letters and digits
}

The following code will take care about special characters and spaces

$string = 'hi, how are you ?';
if (!preg_match('/[^A-Za-z0-9 #$%^&*()+=\-\[\]\';,.\/{}|":<>?~\\\\]+/', $string)) // '/[^a-z\d]/i' should also work.
{
    echo 'english';
}else
{
    echo 'non-english';
}