You&#39;re looking for:

     + opts(legend.key = theme_blank())

You can see lots of examples of all sorts of this stuff in `?opts`. I couldn&#39;t remember off the top of my head which one it was, so I just tried a few until I got it right.

**Note**: Since version 0.9.2 `opts` has been [replaced](http://docs.ggplot2.org/current/theme.html) by `theme`:

    + theme(legend.key = element_blank())

I need to make rate option in my android app.

I found this [link][1] 

but I&#39;m not sure that want I search. I want to just provide ability for users to rate my app on Google Play.

  [1]: http://www.androidsnippets.com/prompt-engaged-users-to-rate-your-app-in-the-android-market-appirater



Rate Google Play application directly in app

I have `d1=&quot;11&quot;` and `d2=&quot;07&quot;`. I want to convert `d1` and `d2` to integers and perform `d1-d2`. How do I do this in UNIX?

`d1 - d2` currently returns `&quot;11-07&quot;` as result for me.

How to convert string to integer in UNIX

Consider the example plot below.  I&#39;d like to make the little boxes around each of the symbols in the legend go away.  How an I do this?

     ggplot(mtcars, aes(wt, mpg, shape=factor(cyl))) + geom_point() + theme_bw()


![](http://i.imgur.com/f3y7P.png)

ggplot2 avoid boxes around legend symbols

Consider the example plot below. I'd like to make the little boxes around each of the symbols in the legend go away. How an I do this?
<pre><code class="hljs language-scss"> ggplot(mtcars, aes(wt, mpg, shape=factor(cyl))) + geom_point() + theme_bw()
</code></pre>
<img src="http://i.imgur.com/f3y7P.png" alt="">

I was finally able to work out the code for [my scraping][1]. It seemed to be working fine and then all of a sudden when I ran it again, I got the following error message:

    Error in url[i] = paste(&quot;http://en.wikipedia.org/wiki/&quot;, gsub(&quot; &quot;, &quot;_&quot;,  : 
      object of type &#39;closure&#39; is not subsettable

I am not sure why as I changed nothing in my code.

Please advise.


    library(XML)
    library(plyr)
    
    names &lt;- c(&quot;George Clooney&quot;, &quot;Kevin Costner&quot;, &quot;George Bush&quot;, &quot;Amar Shanghavi&quot;)
    
    for(i in 1:length(names)) {
    	url[i] = paste(&#39;http://en.wikipedia.org/wiki/&#39;, gsub(&quot; &quot;,&quot;_&quot;, names[i]) , sep=&quot;&quot;)
    	
        # some parsing code
    }


  [1]: https://stackoverflow.com/q/11295618/1468366

Error in &lt;my code&gt; : object of type &#39;closure&#39; is not subsettable

I have a function that returns two values in a list. Both values need to be added to a data.table in two new columns. Evaluation of the function is costly, so I would like to avoid having to compute the function twice. Here&#39;s the example:

    library(data.table)
    example(data.table)
    DT
       x y  v
    1: a 1 42
    2: a 3 42
    3: a 6 42
    4: b 1  4
    5: b 3  5
    6: b 6  6
    7: c 1  7
    8: c 3  8
    9: c 6  9

Here&#39;s an example of my function. Remember I said it&#39;s costly compute, on top of that there is no way to deduce one return value from the other given values (as in the example below):

    myfun &lt;- function (y, v) 
    {
    ret1 = y + v
    ret2 = y - v
    return(list(r1 = ret1, r2 = ret2))
    }

Here&#39;s my way to add two columns in one statement. That one needs to call myfun twice, however:

    DT[,new1:=myfun(y,v)$r1][,new2:=myfun(y,v)$r2]

       x y  v new1 new2
    1: a 1 42   43  -41
    2: a 3 42   45  -39
    3: a 6 42   48  -36
    4: b 1  4    5   -3
    5: b 3  5    8   -2
    6: b 6  6   12    0
    7: c 1  7    8   -6
    8: c 3  8   11   -5
    9: c 6  9   15   -3

Any suggestions on how to do this? I could save `r2` in a separate environment each time I call myfun, I just need a way to add two columns by reference at a time. 

Add multiple columns to R data.table in one function call?

I&#39;m generating plots for some data, but the number of ticks is too small, I need more *precision* on the reading.

Is there some way to increase the number of axis ticks in ggplot2?

I know I can tell ggplot to use a vector as axis ticks, but what I want is to increase the number of ticks, for all data. In other words, I want the tick number to be calculated from the data.

Possibly ggplot do this internally with some algorithm, but I couldn&#39;t find how it does it, to change according to what I want.



Increase number of axis ticks

**Background**

In Germany, there are 16 federal states, ten of which belonged to West Germany, six of which belonged to East Germany. In some respects, for example mortality rates of certain cancers, there are persistent differences between the ten former western states and the six former eastern ones. There are also differences among the states within the respective groups.

To show the differences among the states, it can make a certain amount of sense to plot data, for example age-standardized breast cancer mortality by year, from each state. A plot with 16 lines is not always a good choice, and I don&#39;t want to open up a discussion about that. Sometimes the powers that be say that&#39;s how it has to be.

**The problem**

Differentiating among 16 lines on a plot can be difficult. To do so, I usually use a combination of colors from the `RColorBrewer` package (the first ten colors of `Set3` plus the first six colors of that palette again, corresponding to the ten former west and six former east states) and line types (one line type for east, one for west). Using the `lattice` package, a plot of age-standardized breast cancer mortality rates from 1998-2010 by state could look like this:

![xyplot that works][1]

**The question**

I would like to do a similar plot using `ggplot`, but I haven&#39;t figured out how to combine the colors and the line types in the legend. So far, I&#39;ve gotten this far:

![unsatisfactory ggplot][2]

If it is possible to combine colors and line types in `ggplot` legends, how does one go about doing it?

Here&#39;s the code to create the data frame and the plots:

    mort3 &lt;- structure(list(State = structure(c(8L, 9L, 11L, 12L, 4L, 2L, 
    6L, 13L, 3L, 5L, 7L, 10L, 14L, 15L, 1L, 16L, 8L, 9L, 11L, 12L, 
    4L, 2L, 6L, 13L, 3L, 5L, 7L, 10L, 14L, 15L, 1L, 16L, 8L, 9L, 
    11L, 12L, 4L, 2L, 6L, 13L, 3L, 5L, 7L, 10L, 14L, 15L, 1L, 16L, 
    8L, 9L, 11L, 12L, 4L, 2L, 6L, 13L, 3L, 5L, 7L, 10L, 14L, 15L, 
    1L, 16L, 8L, 9L, 11L, 12L, 4L, 2L, 6L, 13L, 3L, 5L, 7L, 10L, 
    14L, 15L, 1L, 16L, 8L, 9L, 11L, 12L, 4L, 2L, 6L, 13L, 3L, 5L, 
    7L, 10L, 14L, 15L, 1L, 16L, 8L, 9L, 11L, 12L, 4L, 2L, 6L, 13L, 
    3L, 5L, 7L, 10L, 14L, 15L, 1L, 16L, 8L, 9L, 11L, 12L, 4L, 2L, 
    6L, 13L, 3L, 5L, 7L, 10L, 14L, 15L, 1L, 16L, 8L, 9L, 11L, 12L, 
    4L, 2L, 6L, 13L, 3L, 5L, 7L, 10L, 14L, 15L, 1L, 16L, 8L, 9L, 
    11L, 12L, 4L, 2L, 6L, 13L, 3L, 5L, 7L, 10L, 14L, 15L, 1L, 16L, 
    8L, 9L, 11L, 12L, 4L, 2L, 6L, 13L, 3L, 5L, 7L, 10L, 14L, 15L, 
    1L, 16L, 8L, 9L, 11L, 12L, 4L, 2L, 6L, 13L, 3L, 5L, 7L, 10L, 
    14L, 15L, 1L, 16L, 8L, 9L, 11L, 12L, 4L, 2L, 6L, 13L, 3L, 5L, 
    7L, 10L, 14L, 15L, 1L, 16L), class = &quot;factor&quot;, .Label = c(&quot;SH&quot;, 
    &quot;HH&quot;, &quot;NI&quot;, &quot;HB&quot;, &quot;NW&quot;, &quot;HE&quot;, &quot;RP&quot;, &quot;BW&quot;, &quot;BY&quot;, &quot;SL&quot;, &quot;BE&quot;, &quot;BB&quot;, 
    &quot;MV&quot;, &quot;SN&quot;, &quot;ST&quot;, &quot;TH&quot;)), BCmort = c(16.5, 16.6, 15, 14.4, 13.5, 
    17.1, 15.8, 16.3, 18.3, 16.8, 17, 18.1, 13.1, 15.1, 18.8, 13.1, 
    16.4, 16.1, 15.8, 12.8, 16.3, 19.2, 16.8, 13, 17.9, 17, 19.4, 
    19.4, 13.1, 13.8, 18.1, 13.8, 15.9, 17.3, 17.5, 13.7, 17.4, 17.5, 
    16.7, 15.5, 18.1, 18, 20.1, 19.1, 11.8, 14.6, 18.2, 13.4, 16.8, 
    17.5, 15.6, 14.1, 13.9, 18.2, 17.1, 15.2, 18.1, 16.6, 19.3, 18.6, 
    13.1, 14.6, 19.6, 12.4, 16.6, 17.8, 17.5, 14.3, 20.5, 19.2, 19, 
    12.6, 19.5, 17.8, 19.2, 21, 14.4, 13.4, 19.8, 14, 17.5, 18.9, 
    16.4, 14.7, 17.7, 20.1, 18.5, 14.5, 19.1, 19.2, 20.1, 19.7, 14.2, 
    16.2, 17.9, 12.6, 18, 18.7, 17.7, 16.5, 16.6, 20.3, 18.1, 15.2, 
    19, 20, 19.8, 21.3, 13.8, 14.8, 20.4, 14.8, 18.2, 18.7, 16.9, 
    16.2, 20.2, 20.4, 18.5, 14, 20.2, 18.7, 20.3, 17.7, 14.4, 14.5, 
    21.7, 13.7, 18.3, 19.7, 17.8, 16.5, 20.2, 21.7, 18.8, 16.7, 20.4, 
    20, 19.6, 22.9, 15.2, 14.9, 21.7, 14.6, 18.3, 19.7, 17, 16.7, 
    22.9, 16.2, 19.6, 15.9, 20.3, 19.9, 18.9, 21.8, 14.9, 18, 21.4, 
    16.1, 19.6, 19.2, 19.1, 16.7, 20, 18.2, 20.5, 15.5, 20.5, 21.1, 
    21.3, 23.8, 15.8, 15.3, 21.3, 15.7, 19.6, 20.3, 19.2, 17.4, 18.1, 
    23.1, 20.6, 16.2, 21.5, 20.3, 21.4, 20.8, 16.1, 15.8, 22.1, 14.5, 
    20, 20.2, 19, 18.7, 23.1, 21.8, 19.4, 17.4, 20.9, 20.5, 20.4, 
    23.2, 16.3, 17.6, 23.1, 16.5), year = c(2010, 2010, 2010, 2010, 
    2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 2010, 
    2010, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 2009, 
    2009, 2009, 2009, 2009, 2009, 2009, 2008, 2008, 2008, 2008, 2008, 
    2008, 2008, 2008, 2008, 2008, 2008, 2008, 2008, 2008, 2008, 2008, 
    2007, 2007, 2007, 2007, 2007, 2007, 2007, 2007, 2007, 2007, 2007, 
    2007, 2007, 2007, 2007, 2007, 2006, 2006, 2006, 2006, 2006, 2006, 
    2006, 2006, 2006, 2006, 2006, 2006, 2006, 2006, 2006, 2006, 2005, 
    2005, 2005, 2005, 2005, 2005, 2005, 2005, 2005, 2005, 2005, 2005, 
    2005, 2005, 2005, 2005, 2004, 2004, 2004, 2004, 2004, 2004, 2004, 
    2004, 2004, 2004, 2004, 2004, 2004, 2004, 2004, 2004, 2003, 2003, 
    2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 2003, 
    2003, 2003, 2003, 2002, 2002, 2002, 2002, 2002, 2002, 2002, 2002, 
    2002, 2002, 2002, 2002, 2002, 2002, 2002, 2002, 2001, 2001, 2001, 
    2001, 2001, 2001, 2001, 2001, 2001, 2001, 2001, 2001, 2001, 2001, 
    2001, 2001, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 2000, 
    2000, 2000, 2000, 2000, 2000, 2000, 2000, 1999, 1999, 1999, 1999, 
    1999, 1999, 1999, 1999, 1999, 1999, 1999, 1999, 1999, 1999, 1999, 
    1999, 1998, 1998, 1998, 1998, 1998, 1998, 1998, 1998, 1998, 1998, 
    1998, 1998, 1998, 1998, 1998, 1998), eastWest = structure(c(1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L, 1L, 
    1L, 2L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 1L, 2L), .Label = c(&quot;west&quot;, 
    &quot;east&quot;), class = &quot;factor&quot;)), .Names = c(&quot;State&quot;, &quot;BCmort&quot;, &quot;year&quot;, 
    &quot;eastWest&quot;), class = &quot;data.frame&quot;, row.names = c(NA, -208L))
    
    colVec&lt;-c(brewer.pal(10,&quot;Set3&quot;),brewer.pal(6,&quot;Set3&quot;))
    ltyVec&lt;-rep(c(&quot;solid&quot;,&quot;dashed&quot;),c(10,6))
    
    ggplot(mort3, aes(x = year, y = BCmort, col = State, lty = eastWest)) +
      geom_line(lwd = 1) +
      scale_linetype_manual(values = c(west = &quot;solid&quot;, east = &quot;dashed&quot;)) +
      scale_color_manual(values = c(brewer.pal(10, &quot;Set3&quot;), brewer.pal(6, &quot;Set3&quot;))) +
      opts(title = &quot;BC mortality&quot;)
    
    xyplot(BCmort ~ year, data = mort3, groups = State, lty = ltyVec,
      type = &quot;l&quot;, col = colVec, lwd = 2,
      key = list(lines = list(lty = ltyVec, col = colVec, lwd = 2),
      text = list(levels(mort3$State)), columns = 1,
      space = &quot;right&quot;, title = &quot;State&quot;), grid = TRUE, main = &quot;BC mortality&quot;)

  [1]: http://i.stack.imgur.com/KRXyD.png
  [2]: http://i.stack.imgur.com/EjCfb.png


Controlling line color and line type in ggplot legend

I often have numeric values for faceting.
I wish to provide sufficient information to interpret these faceting values in a supplemental title, similar to the axis titles.
The labeller options repeat much unnecessary text and are unusable for longer variable titles.

Any suggestions?

The default:

    test&lt;-data.frame(x=1:20, y=21:40, facet.a=rep(c(1,2),10), facet.b=rep(c(1,2), each=20))
    qplot(data=test, x=x, y=y, facets=facet.b~facet.a)


![enter image description here][1]


What I would love:

![enter image description here][2]

The best I can do in ggplot:




    qplot(data=test, x=x, y=y)+facet_grid(facet.b~facet.a, labeller=label_both)

![enter image description here][3]


As indicated by @Hendy, similar to:
https://stackoverflow.com/questions/9096671/add-a-secondary-y-axis-to-ggplot2-plots-make-it-perfect


  [1]: http://i.stack.imgur.com/2VZA3.jpg
  [2]: http://i.stack.imgur.com/y11DK.jpg
  [3]: http://i.stack.imgur.com/OJvhj.jpg
  [4]: http://i.stack.imgur.com/R2EIG.jpg

How do you add a general label to facets in ggplot2?

Is there a way to change the spacing between legend items in ggplot2? I currently have

    legend.position =&quot;top&quot; 

which automatically produces a horizontal legend. However, the spacing of the items is very close together and I am wondering how to space them farther apart.


Is there a way to change the spacing between legend items in ggplot2?

Does anyone know how I can get control of the ordering of legends in ggplot2?

From what I can see the order appears related to the actual scale labels rather than the scale declaration order. Changing the scale titles alters the ordering. I&#39;ve made a small example using the diamond dataset to highlight this. I&#39;m trying to use ggplot2 for a series of plots and I want to make one variable appear on the right in them all. At present though this only happens in some of them, and I&#39;m at a loss on how to enforce my desired ordering whilst retaining the appropriate scale labels. 
    
    library(ggplot2)
    diamond.data &lt;- diamonds[sample(nrow(diamonds), 1000), ]
    plot &lt;- ggplot(diamond.data, aes(carat, price, colour = clarity, shape = cut)) +
      geom_point() + opts(legend.position = &quot;top&quot;, legend.box = &quot;horizontal&quot;)
    plot # the legend will appear shape then colour 
    plot + labs(colour = &quot;A&quot;, shape = &quot;B&quot;) # legend will be colour then shape
    plot + labs(colour = &quot;Clarity&quot;, shape = &quot;Cut&quot;) # legend will be shape then colour

Content Type	Original Author	Original Content on Stackoverflow
Question	cboettig	View Question on Stackoverflow
Solution 1 - R	joran	View Answer on Stackoverflow

ggplot2 avoid boxes around legend symbols

R Problem Overview

R Solutions

Solution 1 - R

How to convert string to integer in UNIX

Rate Google Play application directly in app

Attributions