Get String in YYYYMMDD format from JS date object?
JavascriptDateDate FormattingJavascript Problem Overview
I'm trying to use JS to turn a date object into a string in YYYYMMDD format. Is there an easier way than concatenating Date.getYear(), Date.getMonth(), and Date.getDay()?
Javascript Solutions
Solution 1 - Javascript
Altered piece of code I often use:
Date.prototype.yyyymmdd = function() {
var mm = this.getMonth() + 1; // getMonth() is zero-based
var dd = this.getDate();
return [this.getFullYear(),
(mm>9 ? '' : '0') + mm,
(dd>9 ? '' : '0') + dd
].join('');
};
var date = new Date();
date.yyyymmdd();
Solution 2 - Javascript
I didn't like adding to the prototype. An alternative would be:
var rightNow = new Date();
var res = rightNow.toISOString().slice(0,10).replace(/-/g,"");
<!-- Next line is for code snippet output only -->
document.body.innerHTML += res;
Solution 3 - Javascript
You can use the toISOString function :
var today = new Date();
today.toISOString().substring(0, 10);
It will give you a "yyyy-mm-dd" format.
Solution 4 - Javascript
Moment.js could be your friend
var date = new Date();
var formattedDate = moment(date).format('YYYYMMDD');
Solution 5 - Javascript
new Date('Jun 5 2016').
toLocaleString('en-us', {year: 'numeric', month: '2-digit', day: '2-digit'}).
replace(/(\d+)\/(\d+)\/(\d+)/, '$3-$1-$2');
// => '2016-06-05'
Solution 6 - Javascript
This is a single line of code that you can use to create a YYYY-MM-DD string of today's date.
var d = new Date().toISOString().slice(0,10);
Solution 7 - Javascript
If you don't need a pure JS solution, you can use jQuery UI to do the job like this :
$.datepicker.formatDate('yymmdd', new Date());
I usually don't like to import too much libraries. But jQuery UI is so useful, you will probably use it somewhere else in your project.
Visit http://api.jqueryui.com/datepicker/ for more examples
Solution 8 - Javascript
I don't like modifying native objects, and I think multiplication is clearer than the string padding the accepted solution.
function yyyymmdd(dateIn) {
var yyyy = dateIn.getFullYear();
var mm = dateIn.getMonth() + 1; // getMonth() is zero-based
var dd = dateIn.getDate();
return String(10000 * yyyy + 100 * mm + dd); // Leading zeros for mm and dd
}
var today = new Date();
console.log(yyyymmdd(today));
Solution 9 - Javascript
In addition to o-o's answer I'd like to recommend separating logic operations from the return and put them as ternaries in the variables instead.
Also, use concat() to ensure safe concatenation of variables
Date.prototype.yyyymmdd = function() {
var yyyy = this.getFullYear();
var mm = this.getMonth() < 9 ? "0" + (this.getMonth() + 1) : (this.getMonth() + 1); // getMonth() is zero-based
var dd = this.getDate() < 10 ? "0" + this.getDate() : this.getDate();
return "".concat(yyyy).concat(mm).concat(dd);
};
Date.prototype.yyyymmddhhmm = function() {
var yyyymmdd = this.yyyymmdd();
var hh = this.getHours() < 10 ? "0" + this.getHours() : this.getHours();
var min = this.getMinutes() < 10 ? "0" + this.getMinutes() : this.getMinutes();
return "".concat(yyyymmdd).concat(hh).concat(min);
};
Date.prototype.yyyymmddhhmmss = function() {
var yyyymmddhhmm = this.yyyymmddhhmm();
var ss = this.getSeconds() < 10 ? "0" + this.getSeconds() : this.getSeconds();
return "".concat(yyyymmddhhmm).concat(ss);
};
var d = new Date();
document.getElementById("a").innerHTML = d.yyyymmdd();
document.getElementById("b").innerHTML = d.yyyymmddhhmm();
document.getElementById("c").innerHTML = d.yyyymmddhhmmss();
<div>
yyyymmdd: <span id="a"></span>
</div>
<div>
yyyymmddhhmm: <span id="b"></span>
</div>
<div>
yyyymmddhhmmss: <span id="c"></span>
</div>
Solution 10 - Javascript
Local time:
var date = new Date();
date = date.toJSON().slice(0, 10);
UTC time:
var date = new Date().toISOString();
date = date.substring(0, 10);
date will print 2020-06-15 today as i write this.
toISOString() method returns the date with the ISO standard which is YYYY-MM-DDTHH:mm:ss.sssZ
The code takes the first 10 characters that we need for a YYYY-MM-DD format.
If you want format without '-' use:
var date = new Date();
date = date.toJSON().slice(0, 10).split`-`.join``;
In .join`` you can add space, dots or whatever you'd like.
Solution 11 - Javascript
Plain JS (ES5) solution without any possible date jump issues caused by Date.toISOString() printing in UTC:
var now = new Date();
var todayUTC = new Date(Date.UTC(now.getFullYear(), now.getMonth(), now.getDate()));
return todayUTC.toISOString().slice(0, 10).replace(/-/g, '');
This in response to @weberste's comment on @Pierre Guilbert's answer.
Solution 12 - Javascript
// UTC/GMT 0
document.write('UTC/GMT 0: ' + (new Date()).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812013509
// Client local time
document.write('<br/>Local time: ' + (new Date(Date.now()-(new Date()).getTimezoneOffset() * 60000)).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812113509
Solution 13 - Javascript
Another way is to use toLocaleDateString with a locale that has a big-endian date format standard, such as Sweden, Lithuania, Hungary, South Korea, ...:
date.toLocaleDateString('se')
To remove the delimiters (-) is just a matter of replacing the non-digits:
console.log( new Date().toLocaleDateString('se').replace(/\D/g, '') );
This does not have the potential error you can get with UTC date formats: the UTC date may be one day off compared to the date in the local time zone.
Solution 14 - Javascript
var someDate = new Date();
var dateFormated = someDate.toISOString().substr(0,10);
console.log(dateFormated);
Solution 15 - Javascript
dateformat is a very used package.
How to use:
Download and install dateformat from NPM. Require it in your module:
const dateFormat = require('dateformat');
and then just format your stuff:
const myYYYYmmddDate = dateformat(new Date(), 'yyyy-mm-dd');
Solution 16 - Javascript
You can simply use This one line code to get date in year
var date = new Date().getFullYear() + "-" + (parseInt(new Date().getMonth()) + 1) + "-" + new Date().getDate();
Solution 17 - Javascript
Shortest
.toJSON().slice(0,10).split`-`.join``;
let d = new Date();
let s = d.toJSON().slice(0,10).split`-`.join``;
console.log(s);
Solution 18 - Javascript
This guy here => http://blog.stevenlevithan.com/archives/date-time-format wrote a format() function for the Javascript's Date object, so it can be used with familiar literal formats.
If you need full featured Date formatting in your app's Javascript, use it. Otherwise if what you want to do is a one off, then concatenating getYear(), getMonth(), getDay() is probably easiest.
Solution 19 - Javascript
Little bit simplified version for the most popular answer in this thread https://stackoverflow.com/a/3067896/5437379 :
function toYYYYMMDD(d) {
var yyyy = d.getFullYear().toString();
var mm = (d.getMonth() + 101).toString().slice(-2);
var dd = (d.getDate() + 100).toString().slice(-2);
return yyyy + mm + dd;
}
Solution 20 - Javascript
How about Day.js?
It's only 2KB, and you can also dayjs().format('YYYY-MM-DD').
Solution 21 - Javascript
Use padStart:
Date.prototype.yyyymmdd = function() {
return [
this.getFullYear(),
(this.getMonth()+1).toString().padStart(2, '0'), // getMonth() is zero-based
this.getDate().toString().padStart(2, '0')
].join('-');
};
Solution 22 - Javascript
Working from @o-o's answer this will give you back the string of the date according to a format string. You can easily add a 2 digit year regex for the year & milliseconds and the such if you need them.
Date.prototype.getFromFormat = function(format) {
var yyyy = this.getFullYear().toString();
format = format.replace(/yyyy/g, yyyy)
var mm = (this.getMonth()+1).toString();
format = format.replace(/mm/g, (mm[1]?mm:"0"+mm[0]));
var dd = this.getDate().toString();
format = format.replace(/dd/g, (dd[1]?dd:"0"+dd[0]));
var hh = this.getHours().toString();
format = format.replace(/hh/g, (hh[1]?hh:"0"+hh[0]));
var ii = this.getMinutes().toString();
format = format.replace(/ii/g, (ii[1]?ii:"0"+ii[0]));
var ss = this.getSeconds().toString();
format = format.replace(/ss/g, (ss[1]?ss:"0"+ss[0]));
return format;
};
d = new Date();
var date = d.getFromFormat('yyyy-mm-dd hh:ii:ss');
alert(date);
I don't know how efficient that is however, especially perf wise because it uses a lot of regex. It could probably use some work I do not master pure js.
NB: I've kept the predefined class definition but you might wanna put that in a function or a custom class as per best practices.
Solution 23 - Javascript
This code is fix to Pierre Guilbert's answer:
(it works even after 10000 years)
YYYYMMDD=new Date().toISOString().slice(0,new Date().toISOString().indexOf("T")).replace(/-/g,"")
Solution 24 - Javascript
Answering another for Simplicity & readability.
Also, editing existing predefined class members with new methods is not encouraged:
function getDateInYYYYMMDD() {
let currentDate = new Date();
// year
let yyyy = '' + currentDate.getFullYear();
// month
let mm = ('0' + (currentDate.getMonth() + 1)); // prepend 0 // +1 is because Jan is 0
mm = mm.substr(mm.length - 2); // take last 2 chars
// day
let dd = ('0' + currentDate.getDate()); // prepend 0
dd = dd.substr(dd.length - 2); // take last 2 chars
return yyyy + "" + mm + "" + dd;
}
var currentDateYYYYMMDD = getDateInYYYYMMDD();
console.log('currentDateYYYYMMDD: ' + currentDateYYYYMMDD);
Solution 25 - Javascript
[day,,month,,year]= Intl.DateTimeFormat(undefined, { year: 'numeric', month: '2-digit', day: '2-digit' }).formatToParts(new Date()),year.value+month.value+day.value
or
new Date().toJSON().slice(0,10).replace(/\/|-/g,'')
Solution 26 - Javascript
From ES6 onwards you can use template strings to make it a little shorter:
var now = new Date();
var todayString = `${now.getFullYear()}-${now.getMonth()}-${now.getDate()}`;
This solution does not zero pad. Look to the other good answers to see how to do that.
Solution 27 - Javascript
It seems that mootools provides Date().format(): https://mootools.net/more/docs/1.6.0/Types/Date
I'm not sure if it worth including just for this particular task though.
Solution 28 - Javascript
I usually use the code below when I need to do this.
var date = new Date($.now());
var dateString = (date.getFullYear() + '-'
+ ('0' + (date.getMonth() + 1)).slice(-2)
+ '-' + ('0' + (date.getDate())).slice(-2));
console.log(dateString); //Will print "2015-09-18" when this comment was written
To explain, .slice(-2) gives us the last two characters of the string.
So no matter what, we can add "0" to the day or month, and just ask for the last two since those are always the two we want.
So if the MyDate.getMonth() returns 9, it will be:
("0" + "9") // Giving us "09"
so adding .slice(-2) on that gives us the last two characters which is:
("0" + "9").slice(-2)
"09"
But if date.getMonth() returns 10, it will be:
("0" + "10") // Giving us "010"
so adding .slice(-2) gives us the last two characters, or:
("0" + "10").slice(-2)
"10"
Solution 29 - Javascript
If you don't mind including an additional (but small) library, Sugar.js provides lots of nice functionality for working with dates in JavaScript. To format a date, use the format function:
new Date().format("{yyyy}{MM}{dd}")
Solution 30 - Javascript
If using AngularJs (up to 1.5) you can use the date filter:
var formattedDate = $filter('date')(myDate, 'yyyyMMdd')
Solution 31 - Javascript
yyyymmdd=x=>(f=x=>(x<10&&'0')+x,x.getFullYear()+f(x.getMonth()+1)+f(x.getDate()));
alert(yyyymmdd(new Date));
Solution 32 - Javascript
date-shortcode to the rescue!
const dateShortcode = require('date-shortcode')
dateShortcode.parse('{YYYYMMDD}', new Date())
//=> '20180304'
Solution 33 - Javascript
A little variation for the accepted answer:
function getDate_yyyymmdd() {
const date = new Date();
const yyyy = date.getFullYear();
const mm = String(date.getMonth() + 1).padStart(2,'0');
const dd = String(date.getDate()).padStart(2,'0');
return `${yyyy}${mm}${dd}`
}
console.log(getDate_yyyymmdd())
Solution 34 - Javascript
Here is a more generic approach which allows both date and time components and is identically sortable as either number or string.
Based on the number order of Date ISO format, convert to a local timezone and remove non-digits. i.e.:
// monkey patch version
Date.prototype.IsoNum = function (n) {
var tzoffset = this.getTimezoneOffset() * 60000; //offset in milliseconds
var localISOTime = (new Date(this - tzoffset)).toISOString().slice(0,-1);
return localISOTime.replace(/[-T:\.Z]/g, '').substring(0,n || 20); // YYYYMMDD
}
Usage
var d = new Date();
// Tue Jul 28 2015 15:02:53 GMT+0200 (W. Europe Daylight Time)
console.log(d.IsoNum(8)); // "20150728"
console.log(d.IsoNum(12)); // "201507281502"
console.log(d.IsoNum()); // "20150728150253272"
Solution 35 - Javascript
Native Javascript:
new Date().toLocaleString('zu-ZA').slice(0,10).replace(/-/g,'');
Solution 36 - Javascript
Sure, you can build a specific function for each variation of date string representations. If you consider international date formats you wind up with dozens of specific functions with rediculous names and hard to distinguish.
There is no reasonable function that matches all formats, but there is a reasonable function composition that does:
const pipe2 = f => g => x =>
g(f(x));
const pipe3 = f => g => h => x =>
h(g(f(x)));
const invoke = (method, ...args) => o =>
o[method] (...args);
const padl = (c, n) => s =>
c.repeat(n)
.concat(s)
.slice(-n);
const inc = n => n + 1;
// generic format date function
const formatDate = stor => (...args) => date =>
args.map(f => f(date))
.join(stor);
// MAIN
const toYYYYMMDD = formatDate("") (
invoke("getFullYear"),
pipe3(invoke("getMonth")) (inc) (padl("0", 2)),
pipe2(invoke("getDate")) (padl("0", 2)));
console.log(toYYYYMMDD(new Date()));
Yes, this is a lot of code. But you can express literally every string date representation by simply changing the function arguments passed to the higher order function formatDate. Everything is explicit and declarative i.e., you can almost read what's happening.
Solution 37 - Javascript
A lot of answers here use the toisostring function. This function converts the time to zulu time before outputting, which may cause issues.
function datestring(time) {
return new Date(time.getTime() - time.getTimezoneOffset()*60000).toISOString().slice(0,10).replace(/-/g,"")
}
mydate = new Date("2018-05-03")
console.log(datestring(mydate))
The datestring function fixes the timezone issue, or even better you can avoid the whole issue by working in zulu time:
mydate = new Date("2018-05-03Z")
// mydate = new Date(Date.UTC(2018,5,3))
console.log(mydate.toISOString().slice(0,10).replace(/-/g,""))
Solution 38 - Javascript
Here is a little improvement to the answer from https://stackoverflow.com/users/318563/o-o
Date.prototype.ddmmyyyy = function(delimiter) {
var yyyy = this.getFullYear().toString();
var mm = (this.getMonth()+1).toString(); // getMonth() is zero-based
var dd = this.getDate().toString();
return (dd[1]?dd:"0"+dd[0]) + delimiter + (mm[1]?mm:"0"+mm[0]) + delimiter +yyyy ; // padding
};
Hope to be helpfull for anyone!
:)
Solution 39 - Javascript
Try this:
function showdate(){
var a = new Date();
var b = a.getFullYear();
var c = a.getMonth();
(++c < 10)? c = "0" + c : c;
var d = a.getDate();
(d < 10)? d = "0" + d : d;
var final = b + "-" + c + "-" + d;
return final;
}
document.getElementById("todays_date").innerHTML = showdate();
Solution 40 - Javascript
this post helped me to write this helper, so I share it in case some one is looking for this solution, it supports all variations of yyyy, mm, dd
Date.prototype.formattedDate = function (pattern) {
formattedDate = pattern.replace('yyyy', this.getFullYear().toString());
var mm = (this.getMonth() + 1).toString(); // getMonth() is zero-based
mm = mm.length > 1 ? mm : '0' + mm;
formattedDate = formattedDate.replace('mm', mm);
var dd = this.getDate().toString();
dd = dd.length > 1 ? dd : '0' + dd;
formattedDate = formattedDate.replace('dd', dd);
return formattedDate;
};
d = new Date();
pattern = 'yyyymmdd'; // 20150813
d.formattedDate(pattern);
pattern = 'yyyy-mm-dd';
d.formattedDate(pattern); // 2015-08-13
Solution 41 - Javascript
Date.js has a lot of helpful date parsing methods.
require("datejs")
(new Date()).toString("yyyyMMdd")
Solution 42 - Javascript
I try to write a simple library for manipulating JavaScript date object. You can try this.
var dateString = timeSolver.getString(date, "YYYYMMDD")
Libarary here: https://github.com/sean1093/timeSolver
Solution 43 - Javascript
Nice, and easy:
var date = new Date();
var yyyy = date.getFullYear();
var mm = date.getMonth() + 1; // getMonth() is zero-based
if (mm < 10) mm='0'+mm;
var dd = date.getDate();
if (dd < 10) dd='0'+dd;
/*date.yyyymmdd();*/
console.log('test - '+yyyy+'-'+mm+'-'+dd);
Solution 44 - Javascript
The @o-o solution doesn't work in my case. My solution is the following:
Date.prototype.yyyymmdd = function() {
var mm = this.getMonth() + 1; // getMonth() is zero-based
var dd = this.getDate();
var ret = [this.getFullYear(), (mm<10)?'0':'', mm, (dd<10)?'0':'', dd].join('');
return ret; // padding
};
Solution 45 - Javascript
To get the local date, in a YYYYMMDD format, im using:
var todayDate = (new Date()).toLocaleString('en-GB').slice(0,10).split("\/").reverse().join("");
Solution 46 - Javascript
You can create yourself function as below
function toString(o, regex) {
try {
if (!o) return '';
if (typeof o.getMonth === 'function' && !!regex) {
let splitChar = regex.indexOf('/') > -1 ? '/' : regex.indexOf('-') > -1 ? '-' : regex.indexOf('.') > -1 ? '.' : '';
let dateSeparate = regex.split(splitChar);
let result = '';
for (let item of dateSeparate) {
let val = '';
switch (item) {
case 'd':
val = o.getDate();
break;
case 'dd':
val = this.date2Char(o.getDate());
break;
case 'M':
val = o.getMonth() + 1;
break;
case 'MM':
val = this.date2Char(o.getMonth() + 1);
break;
case 'yyyy':
val = o.getFullYear();
break;
case 'yy':
val = this.date2Char(o.getFullYear());
break;
default:
break;
}
result += val + splitChar;
}
return result.substring(0, result.length - 1);
} else {
return o.toString();
}
} catch(ex) { return ''; }
}
function concatDateToString(args) {
if (!args.length) return '';
let result = '';
for (let i = 1; i < args.length; i++) {
result += args[i] + args[0];
}
return result.substring(0, result.length - 1);
}
function date2Char(d){
return this.rightString('0' + d);
}
function rightString(o) {
return o.substr(o.length - 2);
}
Used:
var a = new Date();
console.log('dd/MM/yyyy: ' + toString(a, 'dd/MM/yyyy'));
console.log('MM/dd/yyyy: ' + toString(a, 'MM/dd/yyyy'));
console.log('dd/MM/yy: ' + toString(a, 'dd/MM/yy'));
console.log('MM/dd/yy: ' + toString(a, 'MM/dd/yy'));
Solution 47 - Javascript
I hope this function will be useful
function formatDate(dDate,sMode){
var today = dDate;
var dd = today.getDate();
var mm = today.getMonth()+1; //January is 0!
var yyyy = today.getFullYear();
if(dd<10) {
dd = '0'+dd
}
if(mm<10) {
mm = '0'+mm
}
if (sMode+""==""){
sMode = "dd/mm/yyyy";
}
if (sMode == "yyyy-mm-dd"){
return yyyy + "-" + mm + "-" + dd + "";
}
if (sMode == "dd/mm/yyyy"){
return dd + "/" + mm + "/" + yyyy;
}
}
Solution 48 - Javascript
Here's a compact little function that's easy to read and avoids local variables, which can be time-sinks in JavaScript. I don't use prototypes to alter standard modules, because it pollutes the namespace and can lead to code that doesn't do what you think it should.
The main function has a stupid name, but it gets the idea across.
function dateToYYYYMMDDhhmmss(date) {
function pad(num) {
num = num + '';
return num.length < 2 ? '0' + num : num;
}
return date.getFullYear() + '/' +
pad(date.getMonth() + 1) + '/' +
pad(date.getDate()) + ' ' +
pad(date.getHours()) + ':' +
pad(date.getMinutes()) + ':' +
pad(date.getSeconds());
}
Solution 49 - Javascript
var dateDisplay = new Date( 2016-11-09 05:27:00 UTC );
dateDisplay = dateDisplay.toString()
var arr = (dateDisplay.split(' '))
var date_String = arr[0]+','+arr[1]+' '+arr[2]+' '+arr[3]+','+arr[4]
this will show string like Wed,Nov 09 2016,10:57:00
Solution 50 - Javascript
<pre>Date.prototype.getFromFormat = function(format) {
var yyyy = this.getFullYear().toString();
format = format.replace(/yyyy/g, yyyy)
var mm = (this.getMonth()+1).toString();
format = format.replace(/mm/g, (mm[1]?mm:"0"+mm[0]));
var dd = this.getDate().toString();
format = format.replace(/dd/g, (dd[1]?dd:"0"+dd[0]));
var hh = this.getHours().toString();
format = format.replace(/hh/g, (hh[1]?hh:"0"+hh[0]));
var ii = this.getMinutes().toString();
format = format.replace(/ii/g, (ii[1]?ii:"0"+ii[0]));
var ss = this.getSeconds().toString();
format = format.replace(/ss/g, (ss[1]?ss:"0"+ss[0]));
var ampm = (hh >= 12) ? "PM" : "AM";
format = format.replace(/ampm/g, (ampm[1]?ampm:"0"+ampm[0]));
return format;
};
var time_var = $('#899_TIME');
var myVar = setInterval(myTimer, 1000);
function myTimer() {
var d = new Date();
var date = d.getFromFormat('dd-mm-yyyy hh:ii:ss:ampm');
time_var.text(date);
} </pre>
use the code and get the output like **26-07-2017 12:29:34:PM**
check the below link for your reference
https://parthiban037.wordpress.com/2017/07/26/date-and-time-format-in-oracle-apex-using-javascript/
Solution 51 - Javascript
Why you don't use jQuery?
In your page just download/import the file:
<script src="dateFormat.min.js"></script>
And where you want to format the date:
$.format.date(aDate, 'yyyyMMdd');
You have more details/examples here: https://www.npmjs.com/package/jquery-dateformat