Get data from JSON file with PHP


Php Problem Overview

I'm trying to get data from the following JSON file using PHP. I specifically want "temperatureMin" and "temperatureMax".

It's probably really simple, but I have no idea how to do this. I'm stuck on what to do after file_get_contents("file.json"). Some help would be greatly appreciated!

    "daily": {
        "summary": "No precipitation for the week; temperatures rising to 6° on Tuesday.",
        "icon": "clear-day",
        "data": [
                "time": 1383458400,
                "summary": "Mostly cloudy throughout the day.",
                "icon": "partly-cloudy-day",
                "sunriseTime": 1383491266,
                "sunsetTime": 1383523844,
                "temperatureMin": -3.46,
                "temperatureMinTime": 1383544800,
                "temperatureMax": -1.12,
                "temperatureMaxTime": 1383458400,

Php Solutions

Solution 1 - Php

Get the content of the JSON file using file_get_contents():

$str = file_get_contents('');

Now decode the JSON using json_decode():

$json = json_decode($str, true); // decode the JSON into an associative array

You have an associative array containing all the information. To figure out how to access the values you need, you can do the following:

echo '<pre>' . print_r($json, true) . '</pre>';

This will print out the contents of the array in a nice readable format. Note that the second parameter is set to true in order to let print_r() know that the output should be returned (rather than just printed to screen). Then, you access the elements you want, like so:

$temperatureMin = $json['daily']['data'][0]['temperatureMin'];
$temperatureMax = $json['daily']['data'][0]['temperatureMax'];

Or loop through the array however you wish:

foreach ($json['daily']['data'] as $field => $value) {
    // Use $field and $value here


Solution 2 - Php

Use json_decode to transform your JSON into a PHP array. Example:

$json = '{"a":"b"}';
$array = json_decode($json, true);
echo $array['a']; // b

Solution 3 - Php

$data = file_get_contents ("file.json");
        $json = json_decode($data, true);
        foreach ($json as $key => $value) {
            if (!is_array($value)) {
                echo $key . '=>' . $value . '<br/>';
            } else {
                foreach ($value as $key => $val) {
                    echo $key . '=>' . $val . '<br/>';


All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionHarold DunnView Question on Stackoverflow
Solution 1 - PhpAmal MuraliView Answer on Stackoverflow
Solution 2 - PhpGuilherme SehnView Answer on Stackoverflow
Solution 3 - PhpIndrajeet SinghView Answer on Stackoverflow