Flask - Calling python function on button OnClick event

JavascriptPythonHtmlFlaskRaspberry Pi

Javascript Problem Overview


I am new to python and Flask. I have a Flask Web App with a button. When I click on the button I would like to execute a python method not a Javascript method. How can I do this?

I have seen examples with python where it redirects me to a new page using a form tag like this

<form action="/newPage" method="post">

but I don't want it to redirect me to a new page. I just want it to execute the python method. I am making this for a Raspberry Pi robot car. When I press the forward button, I want it to run the method to Turn wheels forward.

Button HTML Code (index.html)

<button name="forwardBtn" onclick="move_forward()">Forward</button>

simple app.py Code - move_forward() method located here

#### App.py code

from flask import Flask, render_template, Response, request, redirect, url_for
app = Flask(__name__)

@app.route("/")
def index():
    return render_template('index.html');
    
def move_forward():
    #Moving forward code
    print("Moving Forward...")

I have seen similar questions to mine on Stackoverflow, but they don't seem to answer my question or I am unable to understand the answer. If someone could please provide me a simple way to call a Python method on button click event, it would be greatly appreciated.

Other Questions that I have looked at:

--https://stackoverflow.com/questions/30899484/python-flask-calling-functions-using-buttons

--https://stackoverflow.com/questions/40583347/calling-a-python-function-with-a-button

--https://stackoverflow.com/questions/21566649/flask-button-run-python-without-refreshing-page

Javascript Solutions


Solution 1 - Javascript

You can simply do this with help of AJAX... Here is a example which calls a python function which prints hello without redirecting or refreshing the page.

In app.py put below code segment.

#rendering the HTML page which has the button
@app.route('/json')
def json():
    return render_template('json.html')

#background process happening without any refreshing
@app.route('/background_process_test')
def background_process_test():
    print ("Hello")
    return ("nothing")

And your json.html page should look like below.

<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script type=text/javascript>
		$(function() {
		  $('a#test').on('click', function(e) {
            e.preventDefault()
			$.getJSON('/background_process_test',
                function(data) {
			  //do nothing
			});
			return false;
		  });
		});
</script>


//button
<div class='container'>
	<h3>Test</h3>
		<form>
			<a href=# id=test><button class='btn btn-default'>Test</button></a>
		</form>

</div>

Here when you press the button Test simple in the console you can see "Hello" is displaying without any refreshing.

Solution 2 - Javascript

It sounds like you want to use this web application as a remote control for your robot, and a core issue is that you won't want a page reload every time you perform an action, in which case, the last link you posted answers your problem.

I think you may be misunderstanding a few things about Flask. For one, you can't nest multiple functions in a single route. You're not making a set of functions available for a particular route, you're defining the one specific thing the server will do when that route is called.

With that in mind, you would be able to solve your problem with a page reload by changing your app.py to look more like this:

from flask import Flask, render_template, Response, request, redirect, url_for
app = Flask(__name__)

@app.route("/")
def index():
    return render_template('index.html')

@app.route("/forward/", methods=['POST'])
def move_forward():
    #Moving forward code
    forward_message = "Moving Forward..."
    return render_template('index.html', forward_message=forward_message);

Then in your html, use this:

<form action="/forward/" method="post">
    <button name="forwardBtn" type="submit">Forward</button>
</form>

...To execute your moving forward code. And include this:

{{ forward_message }} 

... where you want the moving forward message to appear on your template.

This will cause your page to reload, which is inevitable without using AJAX and Javascript.

Solution 3 - Javascript

Easiest solution

<button type="button" onclick="window.location.href='{{ url_for( 'move_forward') }}';">Forward</button>

Solution 4 - Javascript

index.html (index.html should be in templates folder)

<!doctype html>
<html>

<head>
    <title>The jQuery Example</title>
    
    <h2>jQuery-AJAX in FLASK. Execute function on button click</h2>  

    <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"> </script>
    <script type=text/javascript> $(function() { $("#mybutton").click(function (event) { $.getJSON('/SomeFunction', { },
    function(data) { }); return false; }); }); </script> 
</head>

<body>        
        <input type = "button" id = "mybutton" value = "Click Here" />
</body>    
    
</html>

test.py

from flask import Flask, jsonify, render_template, request
app = Flask(__name__)


@app.route('/')
def index():
    return render_template('index.html')
    
@app.route('/SomeFunction')
def SomeFunction():
    print('In SomeFunction')
    return "Nothing"



if __name__ == '__main__':
   app.run()

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionAmaanView Question on Stackoverflow
Solution 1 - JavascriptGihan GamageView Answer on Stackoverflow
Solution 2 - JavascriptLogan BertramView Answer on Stackoverflow
Solution 3 - JavascriptVinit BodhwaniView Answer on Stackoverflow
Solution 4 - Javascriptuser2371563View Answer on Stackoverflow