Express.js - How to check if headers have already been sent?

Javascriptnode.jsExpressResponse Headers

Javascript Problem Overview


I am writing a library which may set headers. I want to give a custom error message if headers have already been sent, instead of just letting it fail with the "Can't set headers after they are sent" message given by Node.js. So how to check if headers have already been sent?

Javascript Solutions


Solution 1 - Javascript

Node supports the res.headersSent these days, so you could/should use that. It is a read-only boolean indicating whether the headers have already been sent.

if(res.headersSent) { ... }

See http://nodejs.org/api/http.html#http_response_headerssent

Note: this is the preferred way of doing it, compared to the older Connect 'headerSent' property that Niko mentions.

Solution 2 - Javascript

EDIT: as of express 4.x, you need to use res.headersSent. Note also that you may want to use setTimeout before checking, as it isn't set to true immediately following a call to res.send(). [Source][1]

Simple: Connect's Response class provides a public property "headerSent".

res.headerSent is a boolean value that indicates whether the headers have already been sent to the client.

From the source code:

/**
   * Provide a public "header sent" flag
   * until node does.
   *
   * @return {Boolean}
   * @api public
   */

  res.__defineGetter__('headerSent', function(){
    return this._header;
  });

https://github.com/senchalabs/connect/blob/master/lib/patch.js#L22

[1]: https://github.com/expressjs/express/issues/2109 "Documentation refers to quot;res.headerSentquot;"

Solution 3 - Javascript

Others answers point to Node.js or Github websites.

Below is from Expressjs website: https://expressjs.com/en/api.html#res.headersSent

app.get('/', function (req, res) {
  console.log(res.headersSent); // false
  res.send('OK');
  console.log(res.headersSent); // true
});

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionpowerboyView Question on Stackoverflow
Solution 1 - JavascriptWillem MulderView Answer on Stackoverflow
Solution 2 - JavascriptNikoView Answer on Stackoverflow
Solution 3 - JavascriptManohar Reddy PoreddyView Answer on Stackoverflow