Emulate ggplot2 default color palette

RGgplot2

R Problem Overview


What function can I use to emulate ggplot2's default color palette for a desired number of colors. For example, an input of 3 would produce a character vector of HEX colors with these colors: enter image description here

R Solutions


Solution 1 - R

It is just equally spaced hues around the color wheel, starting from 15:

gg_color_hue <- function(n) {
  hues = seq(15, 375, length = n + 1)
  hcl(h = hues, l = 65, c = 100)[1:n]
}

For example:

n = 4
cols = gg_color_hue(n)

dev.new(width = 4, height = 4)
plot(1:n, pch = 16, cex = 2, col = cols)

enter image description here

Solution 2 - R

This is the result from

library(scales)
show_col(hue_pal()(4))

Four color ggplot

show_col(hue_pal()(3))

Three color ggplot

Solution 3 - R

These answers are all very good, but I wanted to share another thing I discovered on stackoverflow that is really quite useful, here is the direct link

Basically, @DidzisElferts shows how you can get all the colours, coordinates, etc that ggplot uses to build a plot you created. Very nice!

p <- ggplot(mpg,aes(x=class,fill=class)) + geom_bar()
ggplot_build(p)$data
[[1]]
     fill  y count x ndensity ncount  density PANEL group ymin ymax xmin xmax
1 #F8766D  5     5 1        1      1 1.111111     1     1    0    5 0.55 1.45
2 #C49A00 47    47 2        1      1 1.111111     1     2    0   47 1.55 2.45
3 #53B400 41    41 3        1      1 1.111111     1     3    0   41 2.55 3.45
4 #00C094 11    11 4        1      1 1.111111     1     4    0   11 3.55 4.45
5 #00B6EB 33    33 5        1      1 1.111111     1     5    0   33 4.55 5.45
6 #A58AFF 35    35 6        1      1 1.111111     1     6    0   35 5.55 6.45
7 #FB61D7 62    62 7        1      1 1.111111     1     7    0   62 6.55 7.45

Solution 4 - R

From page 106 of the ggplot2 book by Hadley Wickham:

> The default colour scheme, scale_colour_hue picks evenly spaced hues > around the hcl colour wheel.

With a bit of reverse engineering you can construct this function:

ggplotColours <- function(n = 6, h = c(0, 360) + 15){
  if ((diff(h) %% 360) < 1) h[2] <- h[2] - 360/n
  hcl(h = (seq(h[1], h[2], length = n)), c = 100, l = 65)
}

Demonstrating this in barplot:

y <- 1:3
barplot(y, col = ggplotColours(n = 3))

enter image description here

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionSurajView Question on Stackoverflow
Solution 1 - RJohn ColbyView Answer on Stackoverflow
Solution 2 - RClimbs_lika_SpyderView Answer on Stackoverflow
Solution 3 - RJosh MorelView Answer on Stackoverflow
Solution 4 - RAndrieView Answer on Stackoverflow