Elegant way to make all dirs in a path
PythonPathPython Problem Overview
Here are four paths:
p1=r'\foo\bar\foobar.txt'
p2=r'\foo\bar\foo\foo\foobar.txt'
p3=r'\foo\bar\foo\foo2\foobar.txt'
p4=r'\foo2\bar\foo\foo\foobar.txt'
The directories may or may not exist on a drive. What would be the most elegant way to create the directories in each path?
I was thinking about using os.path.split() in a loop, and checking for a dir with os.path.exists, but I don't know it there's a better approach.
Python Solutions
Solution 1 - Python
You are looking for os.makedirs() which does exactly what you need.
The documentation states:
> Recursive directory creation function. > Like mkdir(), but makes all > intermediate-level directories needed > to contain the leaf directory. Raises > an error exception if the leaf > directory already exists or cannot be > created.
Because it fails if the leaf directory already exists you'll want to test for existence before calling os.makedirs().
Solution 2 - Python
On Python 3.6+ you can do:
import pathlib
path = pathlib.Path(p4)
path.parent.mkdir(parents=True, exist_ok=True)
Solution 3 - Python
A simple way to build the paths in POSIX systems. Assume your path is something like: dirPath = '../foo/bar', where neither foo or bar exist:
path = ''
for d in dirPath.split('/'):
# handle instances of // in string
if not d: continue
path += d + '/'
if not os.path.isdir(path):
os.mkdir(path)