Correct way to check if a type is Nullable

In order to check if a Type ( propertyType ) is nullable, I'm using:

bool isNullable =  "Nullable`1".Equals(propertyType.Name)

Is there some way that avoid using magic strings ?

Absolutely - use Nullable.GetUnderlyingType:

if (Nullable.GetUnderlyingType(propertyType) != null)
{
    // It's nullable
}

Note that this uses the non-generic static class System.Nullable rather than the generic struct Nullable<T>.

Also note that that will check whether it represents a specific (closed) nullable value type... it won't work if you use it on a generic type, e.g.

public class Foo<T> where T : struct
{
    public Nullable<T> Bar { get; set; }
}

Type propertyType = typeof(Foo<>).GetProperty("Bar").PropertyType;
// propertyType is an *open* type...

Use the following code to determine whether a Type object represents a Nullable type. Remember that this code always returns false if the Type object was returned from a call to GetType.

if (type.IsGenericType && type.GetGenericTypeDefinition() == typeof(Nullable<>)) {…}

explained at the below MSDN link:

http://msdn.microsoft.com/en-us/library/ms366789.aspx

Moreover, there is a similar discussion at this SO QA:

How to check if an object is nullable?