Proxies with Python 'Requests' module

Python Problem Overview

Just a short, simple one about the excellent Requests module for Python.

I can't seem to find in the documentation what the variable 'proxies' should contain. When I send it a dict with a standard "IP:PORT" value it rejected it asking for 2 values. So, I guess (because this doesn't seem to be covered in the docs) that the first value is the ip and the second the port?

The docs mention this only: > proxies – (optional) Dictionary mapping protocol to the URL of the proxy.

So I tried this... what should I be doing?

proxy = { ip: port}

and should I convert these to some type before putting them in the dict?

r = requests.get(url,headers=headers,proxies=proxy)

Python Solutions

Solution 1 - Python

The proxies' dict syntax is {"protocol": "scheme://ip:port", ...}. With it you can specify different (or the same) proxie(s) for requests using http, https, and ftp protocols:

http_proxy  = "http://10.10.1.10:3128"
https_proxy = "https://10.10.1.11:1080"
ftp_proxy   = "ftp://10.10.1.10:3128"

proxies = { 
              "http"  : http_proxy, 
              "https" : https_proxy, 
              "ftp"   : ftp_proxy
            }

r = requests.get(url, headers=headers, proxies=proxies)

Deduced from the requests documentation:

> Parameters:
> method – method for the new Request object.
> url – URL for the new Request object.
> ...
> proxies – (optional) Dictionary mapping protocol to the URL of the proxy.
> ...

On linux you can also do this via the HTTP_PROXY, HTTPS_PROXY, and FTP_PROXY environment variables:

export HTTP_PROXY=10.10.1.10:3128
export HTTPS_PROXY=10.10.1.11:1080
export FTP_PROXY=10.10.1.10:3128

On Windows:

set http_proxy=10.10.1.10:3128
set https_proxy=10.10.1.11:1080
set ftp_proxy=10.10.1.10:3128

Solution 2 - Python

You can refer to the proxy documentation here.

If you need to use a proxy, you can configure individual requests with the proxies argument to any request method:

import requests

proxies = {
  "http": "http://10.10.1.10:3128",
  "https": "https://10.10.1.10:1080",
}

requests.get("http://example.org", proxies=proxies)

To use HTTP Basic Auth with your proxy, use the http://user:[email protected]/ syntax:

proxies = {
    "http": "http://user:[email protected]:3128/"
}

Solution 3 - Python

I have found that urllib has some really good code to pick up the system's proxy settings and they happen to be in the correct form to use directly. You can use this like:

import urllib

...
r = requests.get('http://example.org', proxies=urllib.request.getproxies())

It works really well and urllib knows about getting Mac OS X and Windows settings as well.

Solution 4 - Python

The accepted answer was a good start for me, but I kept getting the following error:

AssertionError: Not supported proxy scheme None

Fix to this was to specify the http:// in the proxy url thus:

http_proxy  = "http://194.62.145.248:8080"
https_proxy  = "https://194.62.145.248:8080"
ftp_proxy   = "10.10.1.10:3128"

proxyDict = {
              "http"  : http_proxy,
              "https" : https_proxy,
              "ftp"   : ftp_proxy
            }

I'd be interested as to why the original works for some people but not me.

Edit: I see the main answer is now updated to reflect this :)

Solution 5 - Python

If you'd like to persisist cookies and session data, you'd best do it like this:

import requests

proxies = {
    'http': 'http://user:[email protected]:3128',
    'https': 'https://user:[email protected]:3128',
}

# Create the session and set the proxies.
s = requests.Session()
s.proxies = proxies

# Make the HTTP request through the session.
r = s.get('http://www.showmemyip.com/')

Solution 6 - Python

8 years late. But I like:

import os
import requests

os.environ['HTTP_PROXY'] = os.environ['http_proxy'] = 'http://http-connect-proxy:3128/'
os.environ['HTTPS_PROXY'] = os.environ['https_proxy'] = 'http://http-connect-proxy:3128/'
os.environ['NO_PROXY'] = os.environ['no_proxy'] = '127.0.0.1,localhost,.local'

r = requests.get('https://example.com')  # , verify=False

Solution 7 - Python

The documentation gives a very clear example of the proxies usage

import requests

proxies = {
  'http': 'http://10.10.1.10:3128',
  'https': 'http://10.10.1.10:1080',
}

requests.get('http://example.org', proxies=proxies)

What isn't documented, however, is the fact that you can even configure proxies for individual urls even if the schema is the same! This comes in handy when you want to use different proxies for different websites you wish to scrape.

proxies = {
  'http://example.org': 'http://10.10.1.10:3128',
  'http://something.test': 'http://10.10.1.10:1080',
}

requests.get('http://something.test/some/url', proxies=proxies)

Additionally, requests.get essentially uses the requests.Session under the hood, so if you need more control, use it directly

import requests

proxies = {
  'http': 'http://10.10.1.10:3128',
  'https': 'http://10.10.1.10:1080',
}
session = requests.Session()
session.proxies.update(proxies)

session.get('http://example.org')

I use it to set a fallback (a default proxy) that handles all traffic that doesn't match the schemas/urls specified in the dictionary

import requests

proxies = {
  'http': 'http://10.10.1.10:3128',
  'https': 'http://10.10.1.10:1080',
}
session = requests.Session()
session.proxies.setdefault('http', 'http://127.0.0.1:9009')
session.proxies.update(proxies)

session.get('http://example.org')

Solution 8 - Python

i just made a proxy graber and also can connect with same grabed proxy without any input here is :

#Import Modules

from termcolor import colored
from selenium import webdriver
import requests
import os
import sys
import time

#Proxy Grab

options = webdriver.ChromeOptions()
options.add_argument('headless')
driver = webdriver.Chrome(chrome_options=options)
driver.get("https://www.sslproxies.org/")
tbody = driver.find_element_by_tag_name("tbody")
cell = tbody.find_elements_by_tag_name("tr")
for column in cell:
    
        column = column.text.split(" ")
        print(colored(column[0]+":"+column[1],'yellow'))
driver.quit()
print("")

os.system('clear')
os.system('cls')

#Proxy Connection

print(colored('Getting Proxies from graber...','green'))
time.sleep(2)
os.system('clear')
os.system('cls')
proxy = {"http": "http://"+ column[0]+":"+column[1]}
url = 'https://mobile.facebook.com/login'
r = requests.get(url,  proxies=proxy)
print("")
print(colored('Connecting using proxy' ,'green'))
print("")
sts = r.status_code

Solution 9 - Python

here is my basic class in python for the requests module with some proxy configs and stopwatch !

import requests
import time
class BaseCheck():
    def __init__(self, url):
        self.http_proxy  = "http://user:pw@proxy:8080"
        self.https_proxy = "http://user:pw@proxy:8080"
        self.ftp_proxy   = "http://user:pw@proxy:8080"
        self.proxyDict = {
                      "http"  : self.http_proxy,
                      "https" : self.https_proxy,
                      "ftp"   : self.ftp_proxy
                    }
        self.url = url
        def makearr(tsteps):
            global stemps
            global steps
            stemps = {}
            for step in tsteps:
                stemps[step] = { 'start': 0, 'end': 0 }
            steps = tsteps
        makearr(['init','check'])
        def starttime(typ = ""):
            for stemp in stemps:
                if typ == "":
                    stemps[stemp]['start'] = time.time()
                else:
                    stemps[stemp][typ] = time.time()
        starttime()
    def __str__(self):
        return str(self.url)
    def getrequests(self):
        g=requests.get(self.url,proxies=self.proxyDict)
        print g.status_code
        print g.content
        print self.url
        stemps['init']['end'] = time.time()
        #print stemps['init']['end'] - stemps['init']['start']
        x= stemps['init']['end'] - stemps['init']['start']
        print x


test=BaseCheck(url='http://google.com')
test.getrequests()

Solution 10 - Python

It’s a bit late but here is a wrapper class that simplifies scraping proxies and then making an http POST or GET:

ProxyRequests

https://github.com/rootVIII/proxy_requests

Solution 11 - Python

Already tested, the following code works. Need to use HTTPProxyAuth.

import requests
from requests.auth import HTTPProxyAuth


USE_PROXY = True
proxy_user = "aaa"
proxy_password = "bbb"
http_proxy = "http://your_proxy_server:8080"
https_proxy = "http://your_proxy_server:8080"
proxies = {
    "http": http_proxy,
    "https": https_proxy
}

def test(name):
    print(f'Hi, {name}')  # Press Ctrl+F8 to toggle the breakpoint.
    # Create the session and set the proxies.
    session = requests.Session()
    if USE_PROXY:
        session.trust_env = False
        session.proxies = proxies
        session.auth = HTTPProxyAuth(proxy_user, proxy_password)

    r = session.get('https://www.stackoverflow.com')
    print(r.status_code)

if __name__ == '__main__':
    test('aaa')

Solution 12 - Python

I share some code how to fetch proxies from the site "https://free-proxy-list.net" and store data to a file compatible with tools like "Elite Proxy Switcher"(format IP:PORT):

##PROXY_UPDATER - get free proxies from https://free-proxy-list.net/

from lxml.html import fromstring
import requests
from itertools import cycle
import traceback
import re

######################FIND PROXIES#########################################
def get_proxies():
    url = 'https://free-proxy-list.net/'
    response = requests.get(url)
    parser = fromstring(response.text)
    proxies = set()
    for i in parser.xpath('//tbody/tr')[:299]:   #299 proxies max
        proxy = ":".join([i.xpath('.//td[1]/text()') 
        [0],i.xpath('.//td[2]/text()')[0]])
        proxies.add(proxy)
    return proxies



######################write to file in format   IP:PORT######################
try:
    proxies = get_proxies()
    f=open('proxy_list.txt','w')
    for proxy in proxies:
        f.write(proxy+'\n')
    f.close()
    print ("DONE")
except:
    print ("MAJOR ERROR")

Content Type	Original Author	Original Content on Stackoverflow
Question	user1064306	View Question on Stackoverflow
Solution 1 - Python	chown	View Answer on Stackoverflow
Solution 2 - Python	Zhifeng Hu	View Answer on Stackoverflow
Solution 3 - Python	Ben Golding	View Answer on Stackoverflow
Solution 4 - Python	Owen B	View Answer on Stackoverflow
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