Convert Object to JSON string

JqueryJson

Jquery Problem Overview

jQuery.parseJSON('{"name":"John"}') converts string representation to object but I want the reverse. Object is to be converted to JSON string I got a link http://www.devcurry.com/2010/03/convert-javascript-object-to-json.html but it need to have json2.js do jQuery has a native method to do this?

Jquery Solutions

Solution 1 - Jquery

jQuery does only make some regexp checking before calling the native browser method window.JSON.parse(). If that is not available, it uses eval() or more exactly new Function() to create a Javascript object.

The opposite of JSON.parse() is JSON.stringify() which serializes a Javascript object into a string. jQuery does not have functionality of its own for that, you have to use the browser built-in version or json2.js from http://www.json.org

JSON.stringify() is available in all major browsers, but to be compatible with older browsers you still need that fallback.

Solution 2 - Jquery

Also useful is Object.toSource() for debugging purposes, where you want to show the object and its properties for debugging purposes. This is a generic Javascript (not jQuery) function, however it only works in "modern" browsers.

Solution 3 - Jquery

Convert JavaScript object to json data

$("form").submit(function(event){
  event.preventDefault();
  var formData = $("form").serializeArray(); // Create array of object
  var jsonConvertedData = JSON.stringify(formData);  // Convert to json
  consol.log(jsonConvertedData);
});

You can validate json data using http://jsonlint.com

Solution 4 - Jquery

You can use the excellent jquery-Json plugin:

http://code.google.com/p/jquery-json/

Makes it easy to convert to and from Json objects.

Categories
Recommended Jquery Solutions
Recommended Json Solutions

Previous Solution:

Using a strategy pattern and a command pattern

Design PatternsEncapsulationStrategy PatternCommand Pattern

Next Solution:

Find oldest/youngest datetime object in a list

PythonDatetimeCompare

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionKuttan SujithView Question on Stackoverflow
Solution 1 - JqueryjAndyView Answer on Stackoverflow
Solution 2 - JqueryExcaliburView Answer on Stackoverflow
Solution 3 - JquerySubroto BiswasView Answer on Stackoverflow
Solution 4 - JqueryGeorge FilippakosView Answer on Stackoverflow