Find oldest/youngest datetime object in a list
PythonDatetimeComparePython Problem Overview
I've got a list of datetime objects, and I want to find the oldest or youngest one. Some of these dates might be in the future.
from datetime import datetime
datetime_list = [
datetime(2009, 10, 12, 10, 10),
datetime(2010, 10, 12, 10, 10),
datetime(2010, 10, 12, 10, 10),
datetime(2011, 10, 12, 10, 10), #future
datetime(2012, 10, 12, 10, 10), #future
]
What's the most optimal way to do so? I was thinking of comparing datetime.now() to each one of those.
Python Solutions
Solution 1 - Python
Oldest:
oldest = min(datetimes)
Youngest before now:
now = datetime.datetime.now(pytz.utc)
youngest = max(dt for dt in datetimes if dt < now)
Solution 2 - Python
Given a list of dates dates:
Max date is max(dates)
Min date is min(dates)
Solution 3 - Python
Datetimes are comparable; so you can use max(datetimes_list) and min(datetimes_list)
Solution 4 - Python
have u tried this :
>>> from datetime import datetime as DT
>>> l =[]
>>> l.append(DT(1988,12,12))
>>> l.append(DT(1979,12,12))
>>> l.append(DT(1979,12,11))
>>> l.append(DT(2011,12,11))
>>> l.append(DT(2022,12,11))
>>> min(l)
datetime.datetime(1979, 12, 11, 0, 0)
>>> max(l)
datetime.datetime(2022, 12, 11, 0, 0)
Solution 5 - Python
The datetime module has its own versions of min and max as available methods. https://docs.python.org/2/library/datetime.html