conversion from derived * to base * exists but is inaccessible
C++InheritanceC++ Problem Overview
Why does the follwing code produce this error even though c is a struct and has a public inheritance by default??
struct c
{
protected:
int i;
public:
c(int ii=0):i(ii){}
virtual c *fun();
};
c* c::fun(){
cout<<"in c";
return &c();
}
class d : c
{
public:
d(){}
d* fun()
{
i = 9;
cout<<"in d"<<'\t'<<i;
return &d();
}
};
int main()
{
c *cc;
d dd;
cc = ⅆ
cc->fun();
}
C++ Solutions
Solution 1 - C++
You need:
class d : public c
class
inheritance is private
by default.
When you privately inherit from a class
or a struct
, you explicitly say, among other things, that direct conversion from a derived type to a base type isn't possible.