Use the &#39;call&#39; command when activating/deactivating the environment.

    call activate [my_env]
    python my_script.py
    call conda deactivate

See https://github.com/conda/conda/issues/794

 Are you sure you need a batch file? I think this should work. 

    cmd &quot;/c activate [my_env] &amp;&amp; python my_script.py &amp;&amp; deactivate&quot;

When I made a simple file containing

    print(&quot;Hello&quot;)
Which I called myprint.py and ran

    cmd &quot;/c activate anaconda33 &amp;&amp; python myprint.py &amp;&amp; deactivate&quot;

This worked for me. You could also put this in a one line batch file. 

All activate does is put the environment in the front of the PATH. You can just call the absolute path to the `python` in the environment you want, like `C:\Anaconda\python my-script.py`.

Does anyone know if there a way to increase the size of the logcat history/buffer in Android Studio? I remember there was a way to do it in Eclipse and was hoping Android Studio had a similar setting.

Android Studio logcat history/buffer size

I am trying to get the max value from a panda dataframe as whole. I am not interested in what row or column it came from. I am just interested in a single max value within the DataFrame.

Here is my DataFrame:

    df = pd.DataFrame({&#39;group1&#39;: [&#39;a&#39;,&#39;a&#39;,&#39;a&#39;,&#39;b&#39;,&#39;b&#39;,&#39;b&#39;,&#39;c&#39;,&#39;c&#39;,&#39;d&#39;,&#39;d&#39;,&#39;d&#39;,&#39;d&#39;,&#39;d&#39;],
                            &#39;group2&#39;: [&#39;c&#39;,&#39;c&#39;,&#39;d&#39;,&#39;d&#39;,&#39;d&#39;,&#39;e&#39;,&#39;f&#39;,&#39;f&#39;,&#39;e&#39;,&#39;d&#39;,&#39;d&#39;,&#39;d&#39;,&#39;e&#39;],
                            &#39;value1&#39;: [1.1,2,3,4,5,6,7,8,9,1,2,3,4],
                            &#39;value2&#39;: [7.1,8,9,10,11,12,43,12,34,5,6,2,3]})

This is what it looks like:

       group1 group2  value1  value2
    0       a      c     1.1     7.1
    1       a      c     2.0     8.0
    2       a      d     3.0     9.0
    3       b      d     4.0    10.0
    4       b      d     5.0    11.0
    5       b      e     6.0    12.0
    6       c      f     7.0    43.0
    7       c      f     8.0    12.0
    8       d      e     9.0    34.0
    9       d      d     1.0     5.0
    10      d      d     2.0     6.0
    11      d      d     3.0     2.0
    12      d      e     4.0     3.0

Expected output:

    43.0

I was under the assumption that df.max() would do this job but it returns a max value for each column but I am not interested in that. I need the max from an entire dataframe. 

return max value from pandas dataframe as a whole, not based on column or rows

I am setting up calls to python (Anaconda distribution) via BAT files and the windows task scheduler. 

I&#39;ve now used environments for the first time and was trying to set a `.bat` file up as below: 

    activate [my_env]
    python my_script.py
    deactivate

Unfortunately it appears that the second command does not get executed.

Conda environments and .BAT files

I am setting up calls to python (Anaconda distribution) via BAT files and the windows task scheduler.
I've now used environments for the first time and was trying to set a <code>.bat</code> file up as below:
<pre><code class="hljs language-css">activate [my_env]
python my_script.py
deactivate
</code></pre>
Unfortunately it appears that the second command does not get executed.

I currently am plotting a stacked bar graph of a large amount of taxonomic data, and only wish to show significant species in the legend (out of ~500 I wish to show ~25). Is there a simple way to do this? Below is the code I have:


    labels=[&#39;0&#39;,&#39;20&#39;,&#39;40&#39;,&#39;60&#39;,&#39;80&#39;,&#39;100&#39;,&#39;120&#39;]
    ax1=subj1df.plot(kind=&#39;barh&#39;, stacked=True,legend=True,cmap=&#39;Paired&#39;, grid=False)
    legend(ncol=2,loc=2, bbox_to_anchor=(1.05, 1), borderaxespad=0.)
    label1=[&#39;Baseline&#39;,&#39;8h&#39;,&#39;24h&#39;,&#39;48h&#39;,&#39;96h&#39;,&#39;120h&#39;]
    ax1.set_yticklabels(label1, fontdict=None, minor=False)
    plt.title(&#39;Subject 1 Phyla&#39;,fontweight=&#39;bold&#39;)
    plt.savefig(&#39;Subject1Phyla.eps&#39;, format=&#39;eps&#39;, dpi=1000)
    ax1.set_xticklabels(labels)


Edit: tried adding this to show only one legend entry, however only returns an empty legend:


    h, l = ax1.get_legend_handles_labels()
    legend(l[4],h[4],ncol=2,loc=2, bbox_to_anchor=(1.05, 1), borderaxespad=0.)

Show only certain items in legend Python Matplotlib

This is more of a conceptual question. I recently saw a piece of code in Python (it worked in 2.7, and it might also have been run in 2.5 as well) in which a `for` loop used the same name for both the list that was being iterated over and the item in the list, which strikes me as both bad practice and something that should not work at all.

For example:

    x = [1,2,3,4,5]
    for x in x:
        print x
    print x
Yields:

    1
    2
    3
    4
    5
    5

Now, it makes sense to me that the last value printed would be the last value assigned to x from the loop, but I fail to understand why you&#39;d be able to use the same variable name for both your parts of the `for` loop and have it function as intended. Are they in different scopes? What&#39;s going on under the hood that allows something like this to work?


Why can I use the same name for iterator and sequence in a Python for loop?

Python has an interesting `for` statement which lets you specify an `else` clause.

In a construct like this one:

    for i in foo:
      if bar(i):
        break
    else:
      baz()

the `else` clause is executed after the `for`, but only if the `for` terminates normally (not by a `break`).

I wondered if there was an equivalent in C++? Can I use `for ... else`?

Is there an equivalent to the &quot;for ... else&quot; Python loop in C++?

I&#39;m making some scatter plots and I want to set the size of the points in the legend to a fixed, equal value.

Right now I have this:

    import matplotlib.pyplot as plt
    import numpy as np
    
    def rand_data():
        return np.random.uniform(low=0., high=1., size=(100,))
    
    # Generate data.
    x1, y1 = [rand_data() for i in range(2)]
    x2, y2 = [rand_data() for i in range(2)]
    
    
    plt.figure()
    plt.scatter(x1, y1, marker=&#39;o&#39;, label=&#39;first&#39;, s=20., c=&#39;b&#39;)
    plt.scatter(x2, y2, marker=&#39;o&#39;, label=&#39;second&#39;, s=35., c=&#39;r&#39;)
    # Plot legend.
    plt.legend(loc=&quot;lower left&quot;, markerscale=2., scatterpoints=1, fontsize=10)
    plt.show()

which produces this:

![enter image description here][1]

The sizes of the points in the legend are scaled but not the same. How can I fix the sizes of the points in the legend to an equal value without affecting the sizes in the `scatter` plot?


  [1]: http://i.stack.imgur.com/fAGgh.png

Setting a fixed size for points in legend

Say I have a categorical feature, color, which takes the values

[&#39;red&#39;, &#39;blue&#39;, &#39;green&#39;, &#39;orange&#39;],

and I want to use it to predict something in a random forest.  If I one-hot encode it (i.e. I change it to four dummy variables), how do I tell sklearn that the four dummy variables are really one variable?  Specifically, when sklearn is randomly selecting features to use at different nodes, it should either include the red, blue, green and orange dummies together, or it shouldn&#39;t include any of them.

I&#39;ve heard that there&#39;s no way to do this, but I&#39;d imagine there must be a way to deal with categorical variables without arbitrarily coding them as numbers or something like that.

Can sklearn random forest directly handle categorical features?

Is there a way (using conda update) that I can list outdated packages and select or bulk update (compatible) packages in Anaconda?

It doesn&#39;t make much sense updating the packages individually as there are hundreds of them.

Bulk package updates using Conda

I changed from Win XP 32bit to Win7 64bit and reinstalled Python 2.7
and the Anaconda package. 

However, it seems like it isn&#39;t properly installed.
When I do 

    import enum 

There is the error:

    ImportError: No module named enum

However, when I try import pandas it works.

When typing help() and modules within Ipython nothing happens.

Any idea how to go from here?

ImportError: No module named enum

[Anaconda python distribution][1] is very convenient to deploy scientific computing env (SCE) and switch python versions as you want. By default, the installation will locate python into `~/anaconda` and the SCE can only benefit the local user.

But what I need is to provide a complete SCE wit Anaconda while masking the system-wide python version, because my cluster is running Spark and provides services for multiple users in our team. Is it possible with current Anaconda version?

Xiaming


  [1]: https://store.continuum.io/cshop/anaconda/

How to install Anaconda python for all users?

I&#39;ve got Pycharm 4 running on my Linux (Ubuntu 14.04) machine.  In addition to the system python, I&#39;ve also got Anaconda installed.  Getting the two to play nicely together seems to be a bit of a problem... PyCharm provides some interesting integration for `virtualenv`s and `pip`, but the Anaconda Python distribution seems to prefer using its own `conda` tool for both activities.

Is there a relatively simple/painless way to be able to use `conda` in conjunction with PyCharm?  Not just as an alternative interpreter i.e. point PyCharm at the Anaconda Python binary for a project interpreter, but to be able to create, source/activate and deactivate virtual envs, add/remove packages in those virtual envs, etc. 

Or am I going to have to choose between using Anaconda (and having a more recent and up-to-date python than may come with the system), and being able to use PyCharm&#39;s features to their fullest extent?

Using (Ana)conda within PyCharm

I&#39;ve installed Anaconda and created two extra environments: py3k (which holds Python 3.3) and py34 (which holds Python 3.4). Besides those, I have a default environment named &#39;root&#39; which the Anaconda installer created by default and which holds Python 2.7. This last one is the default, whenever I launch &#39;ipython&#39; from the terminal it gives me version 2.7. In order to work with Python 3.4, I need to issue the commands (in the shell)

    source activate py34
    ipython

which change the default environment to Python 3.4. This works fine, but it&#39;s annoying since most of the time I work on Python 3.4, instead of Python 2.7 (which I hold for teaching purposes, it&#39;s a rather long story). Anyway, I&#39;ll like to know how to change the default environment to Python 3.4, bearing in mind that I don&#39;t want to reinstall everything from scratch.  



How to change default Anaconda python environment

I installed the latest version of Anaconda.
Now I want to install OpenCV within it. When I type:

    conda install -c https://conda.binstar.org/anaconda opencv

I get this message error: &quot;*conda is not recognized as internal command ...*&quot; (sorry, I try to translate from French because my OS is in French) 

The problem is that conda comes with Anaconda, so I wonder why lauching Anaconda and type the above command does not work ?

Why Anaconda does not recognize conda command?

When using the Anacoda Python distribution, what is the best way to install a PyPi package that isn&#39;t available directly through Anaconda?  For now I&#39;m using:

    conda pipbuild [pypi_name]
    conda install --use-local [package_spec]

But I&#39;m unclear if this is the best way and if `conda update --all` will update these packages when updates are made available.  I&#39;m also unclear what the point of binstar is when PyPi already exists.

Content Type	Original Author	Original Content on Stackoverflow
Question	Hans	View Question on Stackoverflow
Solution 1 - Python	Chris Burgoyne	View Answer on Stackoverflow
Solution 2 - Python	BKay	View Answer on Stackoverflow
Solution 3 - Python	asmeurer	View Answer on Stackoverflow

Conda environments and .BAT files

Python Problem Overview

Python Solutions

Solution 1 - Python

Solution 2 - Python

Solution 3 - Python

return max value from pandas dataframe as a whole, not based on column or rows

Android Studio logcat history/buffer size

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