Check if a file was included or loaded

Is there any elegant way to check if a file was included by using include/include_once/require/require_once or if the page was actually loaded directly? I'm trying to set up a testing file inside class files while I'm creating them.

I'm looking for something similar to Python's if __name__ == "__main__": technique. Without setting globals or constants.

Quoted from: https://stackoverflow.com/questions/4545878/how-to-know-if-php-script-is-called-via-require-once

> I was looking for a way to determine if a file have been included or called directly, all from within the file. At some point in my quest I passed through this thread. Checking various other threads on this and other sites and pages from the PHP manual I got enlightened and came up with this piece of code:

if (basename(__FILE__) == basename($_SERVER["SCRIPT_FILENAME"])) {
  echo "called directly";
} else {
  echo "included/required";
}

> In essence it compares if the name of the current file (the one that > could be included) is the same as the file that is beeing executed.

Credit: @Interwebs Cowboy

you can do this by get_included_files — Returns an array with the names of included or required files and validate against __FILE__

I appreciate all the answers, but I didn't want to use any one's solution here, so I combined your ideas and got this:

<?php
    // place this at the top of the file
    if (count(get_included_files()) == 1) define ('TEST_SUITE', __FILE__);

    // now I can even include bootstrap which will include other
    // files with similar setups
    require_once '../bootstrap.php'

    // code ...
    class Bar {
        ...
    }
    // code ...

    if (defined('TEST_SUITE') && TEST_SUITE == __FILE__) {
        // run test suite here	
    }
?>

if (defined('FLAG_FROM_A_PARENT'))
// Works in all scenarios but I personally dislike this

if (__FILE__ == get_included_files()[0])
// Doesn't work with PHP prepend unless calling [1] instead.

if (__FILE__ == $_SERVER['SCRIPT_FILENAME'])
// May break on Windows due to mixed DIRECTORY_SEPARATOR

if (basename(__FILE__) == basename($_SERVER['SCRIPT_FILENAME']))
// Doesn't work with files with the same basename but different paths

if (realpath(__FILE__) == realpath($_SERVER['SCRIPT_FILENAME']))
// Seems to do the trick as long as document root is properly configured

Note: On WAMP Servers virtual-hosts sometimes inherit the default document root setting, causing $_SERVER['DOCUMENT_ROOT'] to display wrong path.

<?php
    if (__FILE__ == $_SERVER['SCRIPT_FILENAME'])
    {
        //file was navigated to directly
    }
?>

Taken from mgutt's answer to a slightly different question here. It's important to note this doesn't work if the script is run from command line but other than that it functions exactly like python's

if __name__ == '__main__':

as far as I can tell

They is no way to separate them as include/include_once/require/require_once but php has get_included_files and get_required_files which is the same thing and only returns array of all included files. Its does not separate it if its required or included.

Example a.php

include 'b.php';
include_once 'c.php';
require 'd.php';
var_dump(get_required_files());

Output

array
  0 => string '..\lab\stockoverflow\a.php' (length=46) <---- Returns current file
  1 => string '..\lab\stockoverflow\b.php' (length=46)
  2 => string '..\lab\stockoverflow\c.php' (length=46)
  3 => string '..\lab\stockoverflow\d.php' (length=46)

But you can do something like

$inc = new IncludeManager($file);
var_dump($inc->find("b.php")); // Check if a file is included
var_dump($inc->getFiles("require_once")); // Get All  Required Once 

Class Used

class IncludeManager {
	private $list = array();
	private $tokens = array();
	private $find;
	private $file;
	private $type = array(262 => "include",261 => "include_once",259 => "reguire",258 => "require_once");

	function __construct($file) {
		$this->file = $file;
		$this->_parse();
	}

	private function _parse() {
		$tokens = token_get_all(file_get_contents($this->file));
		for($i = 0; $i < count($tokens); $i ++) {
			if (count($tokens[$i]) == 3) {
				if (array_key_exists($tokens[$i][0], $this->type)) {
					$f = $tokens[$i + 1][0] == 371 ? $tokens[$i + 2][1] : $tokens[$i + 1][1];
					$this->list[] = array("pos" => $i,"type" => $this->type[$tokens[$i][0]],"file" => trim($f, "\"\'"));
				}
			}
		}
	}

	public function find($find) {
		$finds = array_filter($this->list, function ($v) use($find) {
			return $v['file'] == $find;
		});
		
		return empty($finds) ? false : $finds;
	}

	public function getList() {
		return $this->list;
	}

	public function getFiles($type = null) {
		$finds = array_filter($this->list, function ($v) use($type) {
			return is_null($type) ? true : $type == $v['type'];
		});
		return empty($finds) ? false : $finds;
	}
}

get_included_files() return array where 0 index mean first "included" file. Because direct run mean "include" in this terms, you can simple check first index for equality for __FILE__:

if(get_included_files()[0] == __FILE__){
    do_stuff();
}

This can not work on PHP 4, because PHP 4 not add run file in this array.

Here's a different idea. Just include the file whenever you need it. Inside the include file you can decide whether it needs to include the contents:

<?php
if (defined("SOME_UNIQUE_IDENTIFIER_FOR_THIS_FILE"))
    return;
define("SOME_UNIQUE_IDENTIFIER_FOR_THIS_FILE", 1);

// Rest of code goes here

Working solution:

$target_file = '/home/path/folder/file.php'; // or use __FILE__

if ($x=function($e){return str_replace(array('\\'), '/', $e);}) if(in_array( $x($target_file), array_map( $x ,  get_included_files() ) ) )
{
	exit("Hello, already included !");
}

I don't think get_included_files is the perfect solution, what if your main script included some other scripts before the check? My suggestion is to check whether __FILE__ equals realpath($argv[1]):

<?php
require('phpunit/Autoload.php');

class MyTests extends PHPUnit_Framework_TestCase
{
	// blabla...
}

if (__FILE__ == realpath($argv[0])) {
	// run tests.
}

I took a similar approach to this issue when I cam across it. The solution I found was to load each file as needed in an include_once method. Hope this helps.

$FILES = get_included_files();  // Retrieves files included as array($FILE)
$FILE = __FILE__;               // Set value of current file with absolute path
if(!in_array($FILE, $FILES)){   // Checks if file $FILE is in $FILES
  include_once "PATH_TO_FILE";  // Includes file with include_once if $FILE is not found.
}

I have the following function established to check files loaded:

ARRAY_DUMP($FILES);

function ARRAY_DUMP($array){
  echo "
    <span style='font-size:12px;'>".date('h:i:s').":</span>
    <pre style='font-size:12px;'>", print_r($array, 1), "</pre>
  ";
}

Output:

currentArray
(
  [0] => /home/MY_DOMAIN/hardeen/index.php
  [1] => /home/MY_DOMAIN/hardeen/core/construct.php
  [2] => /home/MY_DOMAIN/hardeen/core/template.php
  [3] => /home/MY_DOMAIN/hardeen/bin/tags.php
  [4] => /home/MY_DOMAIN/hardeen/bin/systemFunction.php
)

It's sooo simple.. I have made something like this:

//code for file.php
if (!isset($file_included)){
   echo "It was loaded!";
} else {
  echo "It was included!";
}

//code for loader.php
//proves that atleast loader.php has loaded,
//not the file we targeted first..
$file_included = true;
include("../file.php");

And that's it.. as simple as in python.