C++ create string of text and variables
C++StringVariablesStdC++ Problem Overview
I'm trying to do something very simple and yet, after an hour of so of searching a I can't find a suitable answer so I must be missing something fairly obvious.
I'm trying to dynamically create filenames for use with ifstream. Whilst I understand various methods are available of doing this, I have settled on creating a std::string, and the using stringname.c_str to convert to const.
The problem is however that I need to create the string with a mix of variables and predefined text values. I'm getting compiler errors, so this must be a syntax issue.
Pseudo
std::string var = "sometext" + somevar + "sometext" + somevar;
Thanks!
C++ Solutions
Solution 1 - C++
Have you considered using stringstreams?
#include <string>
#include <sstream>
std::ostringstream oss;
oss << "sometext" << somevar << "sometext" << somevar;
std::string var = oss.str();
Solution 2 - C++
In C++11 you can use std::to_string:
std::string var = "sometext" + std::to_string(somevar) + "sometext" + std::to_string(somevar);
Solution 3 - C++
std::string var = "sometext" + somevar + "sometext" + somevar;
This doesn't work because the additions are performed left-to-right and "sometext"
(the first one) is just a const char *
. It has no operator+
to call. The simplest fix is this:
std::string var = std::string("sometext") + somevar + "sometext" + somevar;
Now, the first parameter in the left-to-right list of +
operations is a std::string
, which has an operator+(const char *)
. That operator produces a string, which makes the rest of the chain work.
You can also make all the operations be on var
, which is a std::string
and so has all the necessary operators:
var = "sometext";
var += somevar;
var += "sometext";
var += somevar;
Solution 4 - C++
The new way to do with c++20 is using format.
#include <format>
auto var = std::format("sometext {} sometext {}", somevar, somevar);
Solution 5 - C++
You can also use sprintf:
char str[1024];
sprintf(str, "somtext %s sometext %s", somevar, somevar);
Solution 6 - C++
See also boost::format:
#include <boost/format.hpp>
std::string var = (boost::format("somtext %s sometext %s") % somevar % somevar).str();
Solution 7 - C++
You could have something like:
#define Compose(...) ComposeFn({ __VA_ARGS__ })
std::string ComposeFn(std::initializer_list<std::string> strList) {
std::ostringstream ss;
for(std::string str : strList) {
ss << str;
}
return ss.str();
}
And then use it like:
int errcode = 404;
std::cout << Compose("[ERROR]: (", errcode, ") doesn't exist") << std::endl;
The Compose
macro is just to avoid using the curly brackets. You could also use a variadic function, but eh
Solution 8 - C++
Since c++14 you can use the std::string operator""s from std::string_literals
#include <string>
using namespace std::string_literals;
std::string var = "sometext"s + somevar + "sometext"s + somevar;
The compiler will add a std::string in place of the literal, and as such you can use the "+" operator with it.