Boolean.parseBoolean("1") = false...?
JavaJava Problem Overview
sorry to be a pain... I have: HashMap<String, String> o
o.get('uses_votes'); // "1"
Yet...
Boolean.parseBoolean(o.get('uses_votes')); // "false"
I'm guessing that ....parseBoolean
doesn't accept the standard 0 = false
1 = true
?
Am I doing something wrong or will I have to wrap my code in:
boolean uses_votes = false;
if(o.get('uses_votes').equals("1")) {
uses_votes = true;
}
Thanks
Java Solutions
Solution 1 - Java
It accepts only a string value of "true"
to represent boolean true
. Best what you can do is
boolean uses_votes = "1".equals(o.get("uses_votes"));
Or if the Map
actually represents an "entitiy", I think a Javabean is way much better. Or if it represents configuration settings, you may want to take a look into Apache Commons Configuration.
Solution 2 - Java
I have a small utility function to convert all possible values into Boolean.
private boolean convertToBoolean(String value) {
boolean returnValue = false;
if ("1".equalsIgnoreCase(value) || "yes".equalsIgnoreCase(value) ||
"true".equalsIgnoreCase(value) || "on".equalsIgnoreCase(value))
returnValue = true;
return returnValue;
}
Solution 3 - Java
According to the documentation (emphasis mine):
> Parses the string argument as a boolean. The boolean returned > represents the value true if the string argument is not null and is > equal, ignoring case, to the string "true".
Solution 4 - Java
If you're trying to get C's behavior (0 == false
and everything else is true
), you could do this:
boolean uses_votes = Integer.parseInt(o.get("uses_votes")) != 0;
Solution 5 - Java
Thomas, I think your wrapper code, or just the condition itself, is the cleanest way to do what you want to do in java, which is convert "1" to the Boolean True value. Actually, comparing to "0" and taking the inverse would match the C behavior of treating 0 as false and everything else as true.
Boolean intStringToBoolean(numericBooleanValueString) {
return !"0".equals(numericBooleanValueString);
}
Solution 6 - Java
I know this is an old thread, but what about borrowing from C syntax:
(o.get('uses_votes')).equals("1") ? true : false;
Solution 7 - Java
As a note ,
for those who need to have null value for things other than "true" or "false" strings , you can use the function below
public Boolean tryParseBoolean(String inputBoolean)
{
if(!inputBoolean.equals("true")&&!inputBoolean.equals("false")) return null;
return Boolean.valueOf(inputBoolean);
}
Solution 8 - Java
Returns true if comes 'y', '1', 'true', 'on'or whatever you add in similar way
boolean getValue(String value) {
return ("Y".equals(value.toUpperCase())
|| "1".equals(value.toUpperCase())
|| "TRUE".equals(value.toUpperCase())
|| "ON".equals(value.toUpperCase())
);
}
Solution 9 - Java
Java is strongly typed. 0 and 1 are numbers, which is a different type than a boolean. A number will never be equal to a boolean.
Solution 10 - Java
How about this?
boolean uses_votes =
( "|1|yes|on|true|"
.indexOf("|"+o.get("uses_votes").toLowerCase()+"|")
> -1
);
Solution 11 - Java
I had the same question and i solved it with that:
Boolean use_vote = o.get('uses_votes').equals("1") ? true : false;