Why can a enum have a package-private constructor?

JavaEnumsPackage Private

Java Problem Overview


Since an enum constructor can only be invoked by its constants, why is it then allowed to be package-private?

Java Solutions


Solution 1 - Java

The constructor actually isn't package-private... it's implicitly private the way interface methods are implicitly public even if you don't add the keyword.

The relevant section of the JLS (§8.8.3) states:

> If no access modifier is specified for the constructor of a normal class, the constructor has default access. > > If no access modifier is specified for the constructor of an enum type, the constructor is private. > > It is a compile-time error if the constructor of an enum type (§8.9) is declared public or protected.

Solution 2 - Java

It's a quirk of the language: enum constructors are implicitly private.

Interestingly, if you declare a package-visible enum constructor, like this:

public enum MyEnum {
    A(0),
    B(1);

    private final int i;

    MyEnum(int i) {
        this.i = i;
    }

    public int getI() {
        return i;
    }
}

you can't refer to it from another class in the package. If you try, you get the compiler error:

> Cannot instantiate the type MyEnum

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionTobiasView Question on Stackoverflow
Solution 1 - JavaColinDView Answer on Stackoverflow
Solution 2 - JavaBohemianView Answer on Stackoverflow