Android : How to read file in bytes?

JavaAndroidFile

Java Problem Overview


I am trying to get file content in bytes in Android application. I have get the file in SD card now want to get the selected file in bytes. I googled but no such success. Please help

Below is the code to get files with extension. Through this i get files and show in spinner. On file selection I want to get file in bytes.

private List<String> getListOfFiles(String path) {
 
   File files = new File(path);
 
   FileFilter filter = new FileFilter() {
 
      private final List<String> exts = Arrays.asList("jpeg", "jpg", "png", "bmp", "gif","mp3");
 
      public boolean accept(File pathname) {
         String ext;
         String path = pathname.getPath();
         ext = path.substring(path.lastIndexOf(".") + 1);
         return exts.contains(ext);
      }
   };
 
   final File [] filesFound = files.listFiles(filter);
   List<String> list = new ArrayList<String>();
   if (filesFound != null && filesFound.length > 0) {
      for (File file : filesFound) {
         list.add(file.getName());
      }
   }
   return list;
}

Java Solutions


Solution 1 - Java

here it's a simple:

File file = new File(path);
int size = (int) file.length();
byte[] bytes = new byte[size];
try {
    BufferedInputStream buf = new BufferedInputStream(new FileInputStream(file));
    buf.read(bytes, 0, bytes.length);
    buf.close();
} catch (FileNotFoundException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
} catch (IOException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

Add permission in manifest.xml:

 <uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" />

Solution 2 - Java

The easiest solution today is to used Apache common io :

http://commons.apache.org/proper/commons-io/javadocs/api-release/org/apache/commons/io/FileUtils.html#readFileToByteArray(java.io.File)

byte bytes[] = FileUtils.readFileToByteArray(photoFile)

The only drawback is to add this dependency in your build.gradle app :

implementation 'commons-io:commons-io:2.5'

+ 1562 Methods count

Solution 3 - Java

Since the accepted BufferedInputStream#read isn't guaranteed to read everything, rather than keeping track of the buffer sizes myself, I used this approach:

    byte bytes[] = new byte[(int) file.length()];
    BufferedInputStream bis = new BufferedInputStream(new FileInputStream(file));
    DataInputStream dis = new DataInputStream(bis);
    dis.readFully(bytes);

Blocks until a full read is complete, and doesn't require extra imports.

Solution 4 - Java

Here is a solution that guarantees entire file will be read, that requires no libraries and is efficient:

byte[] fullyReadFileToBytes(File f) throws IOException {
    int size = (int) f.length();
    byte bytes[] = new byte[size];
    byte tmpBuff[] = new byte[size];
    FileInputStream fis= new FileInputStream(f);;
    try {
         
        int read = fis.read(bytes, 0, size);
        if (read < size) {
            int remain = size - read;
            while (remain > 0) {
                read = fis.read(tmpBuff, 0, remain);
                System.arraycopy(tmpBuff, 0, bytes, size - remain, read);
                remain -= read;
            }
        }
    }  catch (IOException e){
        throw e;
    } finally {
        fis.close();
    }

    return bytes;
}

NOTE: it assumes file size is less than MAX_INT bytes, you can add handling for that if you want.

Solution 5 - Java

If you want to use a the openFileInput method from a Context for this, you can use the following code.

This will create a BufferArrayOutputStream and append each byte as it's read from the file to it.

/**
 * <p>
 *     Creates a InputStream for a file using the specified Context
 *     and returns the Bytes read from the file.
 * </p>
 *
 * @param context The context to use.
 * @param file The file to read from.
 * @return The array of bytes read from the file, or null if no file was found.
 */
public static byte[] read(Context context, String file) throws IOException {
    byte[] ret = null;

    if (context != null) {
        try {
            InputStream inputStream = context.openFileInput(file);
            ByteArrayOutputStream outputStream = new ByteArrayOutputStream();

            int nextByte = inputStream.read();
            while (nextByte != -1) {
                outputStream.write(nextByte);
                nextByte = inputStream.read();
            }

            ret = outputStream.toByteArray();

        } catch (FileNotFoundException ignored) { }
    }

    return ret;
}

Solution 6 - Java

In Kotlin you can simply use:

File(path).readBytes()

Solution 7 - Java

You can also do it this way:

byte[] getBytes (File file)
{
    FileInputStream input = null;
    if (file.exists()) try
    {
        input = new FileInputStream (file);
        int len = (int) file.length();
        byte[] data = new byte[len];
        int count, total = 0;
        while ((count = input.read (data, total, len - total)) > 0) total += count;
        return data;
    }
    catch (Exception ex)
    {
        ex.printStackTrace();
    }
    finally
    {
        if (input != null) try
        {
            input.close();
        }
        catch (Exception ex)
        {
            ex.printStackTrace();
        }
    }
    return null;
}

Solution 8 - Java

A simple InputStream will do

byte[] fileToBytes(File file){
    byte[] bytes = new byte[0];
    try(FileInputStream inputStream = new FileInputStream(file)) {
        bytes = new byte[inputStream.available()];
        //noinspection ResultOfMethodCallIgnored
        inputStream.read(bytes);
    } catch (IOException e) {
        e.printStackTrace();
    }
    return bytes;
}

Solution 9 - Java

Following is the working solution to read the entire file in chunks and its efficient solution to read the large files using a scanner class.

   try {
        FileInputStream fiStream = new FileInputStream(inputFile_name);
        Scanner sc = null;
        try {
            sc = new Scanner(fiStream);
            while (sc.hasNextLine()) {
                String line = sc.nextLine();
                byte[] buf = line.getBytes();
            }
        } finally {
            if (fiStream != null) {
                fiStream.close();
            }

            if (sc != null) {
                sc.close();
            }
        }
    }catch (Exception e){
        Log.e(TAG, "Exception: " + e.toString());
    }

Solution 10 - Java

To read a file in bytes, often used to read binary files, such as pictures, sounds, images, etc. Use the method below.

 public static byte[] readFileByBytes(File file) {

        byte[] tempBuf = new byte[100];
        int byteRead;
        ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();

        try {
            BufferedInputStream bufferedInputStream = new BufferedInputStream(new FileInputStream(file));
            while ((byteRead = bufferedInputStream.read(tempBuf)) != -1) {
                byteArrayOutputStream.write(tempBuf, 0, byteRead);
            }
            bufferedInputStream.close();
            return byteArrayOutputStream.toByteArray();
        } catch (Exception e) {
            e.printStackTrace();
            return null;
        }
    }

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionAzharView Question on Stackoverflow
Solution 1 - JavaidiottigerView Answer on Stackoverflow
Solution 2 - JavaRenaud BoulardView Answer on Stackoverflow
Solution 3 - JavalaseView Answer on Stackoverflow
Solution 4 - JavaSiavashView Answer on Stackoverflow
Solution 5 - JavaNathan F.View Answer on Stackoverflow
Solution 6 - JavaNesyouView Answer on Stackoverflow
Solution 7 - JavarazzView Answer on Stackoverflow
Solution 8 - JavaIlya GazmanView Answer on Stackoverflow
Solution 9 - JavaPrasanth.NVSView Answer on Stackoverflow
Solution 10 - JavaRichard KamereView Answer on Stackoverflow