Adding click event listener to elements with the same class

Javascript

Javascript Problem Overview


I have a list view for delete id. I'd like to add a listener to all elements with a particular class and do a confirm alert.

My problem is that this seems to only add the listener to the first element with the class it finds. I tried to use querySelectorAll but it didn't work.

var deleteLink = document.querySelector('.delete');

deleteLink.addEventListener('click', function(event) {
    event.preventDefault();

    var choice = confirm("sure u want to delete?");
    if (choice) {
        return true;
    }
});

List:

<?php 
    while($obj=$result->fetch_object())
    {
        echo '<li><a class="delete" href="removeTruck.php?tid='.$obj->id.'">'.$obj->id.'</a>'
            . '<a href="#" class="delete"></a>
                      </li>'."\n";
    }
    /* free result set */
    $result->close();       
    $mysqli->close();
?>

Javascript Solutions


Solution 1 - Javascript

You should use querySelectorAll. It returns NodeList, however querySelector returns only the first found element:

var deleteLink = document.querySelectorAll('.delete');

Then you would loop:

for (var i = 0; i < deleteLink.length; i++) {
    deleteLink[i].addEventListener('click', function(event) {
        if (!confirm("sure u want to delete " + this.title)) {
            event.preventDefault();
        }
    });
}

Also you should preventDefault only if confirm === false.

It's also worth noting that return false/true is only useful for event handlers bound with onclick = function() {...}. For addEventListening you should use event.preventDefault().

Demo: http://jsfiddle.net/Rc7jL/3/


ES6 version

You can make it a little cleaner (and safer closure-in-loop wise) by using Array.prototype.forEach iteration instead of for-loop:

var deleteLinks = document.querySelectorAll('.delete');

Array.from(deleteLinks).forEach(link => {
    link.addEventListener('click', function(event) {
        if (!confirm(`sure u want to delete ${this.title}`)) {
            event.preventDefault();
        }
    });
});

Example above uses Array.from and template strings from ES2015 standard.

Solution 2 - Javascript

The problem with using querySelectorAll and a for loop is that it creates a whole new event handler for each element in the array.

Sometimes that is exactly what you want. But if you have many elements, it may be more efficient to create a single event handler and attach it to a container element. You can then use event.target to refer to the specific element which triggered the event:

document.body.addEventListener("click", function (event) {
  if (event.target.classList.contains("delete")) {
    var title = event.target.getAttribute("title");

    if (!confirm("sure u want to delete " + title)) {
      event.preventDefault();
    }
  }
});

In this example we only create one event handler which is attached to the body element. Whenever an element inside the body is clicked, the click event bubbles up to our event handler.

Solution 3 - Javascript

A short and sweet solution, using ES6:

document.querySelectorAll('.input')
      .forEach(input => input.addEventListener('focus', this.onInputFocus));

Solution 4 - Javascript

You have to use querySelectorAll as you need to select all elements with the said class, again since querySelectorAll is an array you need to iterate it and add the event handlers

var deleteLinks = document.querySelectorAll('.delete');
for (var i = 0; i < deleteLinks.length; i++) {
    deleteLinks[i].addEventListener('click', function (event) {
        event.preventDefault();

        var choice = confirm("sure u want to delete?");
        if (choice) {
            return true;
        }
    });
}

Solution 5 - Javascript

(ES5) I use forEach to iterate on the collection returned by querySelectorAll and it works well :

document.querySelectorAll('your_selector').forEach(item => { /* do the job with item element */ });

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionuser1246950View Question on Stackoverflow
Solution 1 - JavascriptdfsqView Answer on Stackoverflow
Solution 2 - JavascriptjackvsworldView Answer on Stackoverflow
Solution 3 - JavascriptFrancisco HodgeView Answer on Stackoverflow
Solution 4 - JavascriptArun P JohnyView Answer on Stackoverflow
Solution 5 - JavascriptFoxlabView Answer on Stackoverflow