A method to count occurrences in a list

C#.Net 3.5ListCountMatch

C# Problem Overview


Is there a simple way to count the number of occurrences of all elements of a list into that same list in C#?

Something like this:

using System;
using System.IO;
using System.Text.RegularExpressions;
using System.Collections.Generic;
using System.Linq;
    
string Occur;
List<string> Words = new List<string>();
List<string> Occurrences = new List<string>();

// ~170 elements added. . . 

for (int i = 0;i<Words.Count;i++){
    Words = Words.Distinct().ToList();
    for (int ii = 0;ii<Words.Count;ii++){Occur = new Regex(Words[ii]).Matches(Words[]).Count;}
         Occurrences.Add (Occur);
         Console.Write("{0} ({1}), ", Words[i], Occurrences[i]);
    }
}

C# Solutions


Solution 1 - C#

How about something like this ...

var l1 = new List<int>() { 1,2,3,4,5,2,2,2,4,4,4,1 };

var g = l1.GroupBy( i => i );

foreach( var grp in g )
{
  Console.WriteLine( "{0} {1}", grp.Key, grp.Count() );
}

Edit per comment: I will try and do this justice. :)

In my example, it's a Func<int, TKey> because my list is ints. So, I'm telling GroupBy how to group my items. The Func takes a int and returns the the key for my grouping. In this case, I will get an IGrouping<int,int> (a grouping of ints keyed by an int). If I changed it to (i => i.ToString() ) for example, I would be keying my grouping by a string. You can imagine a less trivial example than keying by "1", "2", "3" ... maybe I make a function that returns "one", "two", "three" to be my keys ...

private string SampleMethod( int i )
{
  // magically return "One" if i == 1, "Two" if i == 2, etc.
}

So, that's a Func that would take an int and return a string, just like ...

i =>  // magically return "One" if i == 1, "Two" if i == 2, etc. 

But, since the original question called for knowing the original list value and it's count, I just used an integer to key my integer grouping to make my example simpler.

Solution 2 - C#

You can do something like this to count from a list of things.

IList<String> names = new List<string>() { "ToString", "Format" };
IEnumerable<String> methodNames = typeof(String).GetMethods().Select(x => x.Name);

int count = methodNames.Where(x => names.Contains(x)).Count();

To count a single element

string occur = "Test1";
IList<String> words = new List<string>() {"Test1","Test2","Test3","Test1"};

int count = words.Where(x => x.Equals(occur)).Count();

Solution 3 - C#

var wordCount =
	from word in words
	group word by word into g
	select new { g.Key, Count = g.Count() };	

This is taken from one of the examples in the linqpad

Solution 4 - C#

public void printsOccurences(List<String> words)
{
    var selectQuery =
        from word in words
        group word by word into g
        select new {Word = g.Key, Count = g.Count()};
    foreach(var word in selectQuery)
        Console.WriteLine($"{word.Word}: {word.Count}");*emphasized text*
}

Solution 5 - C#

This is a version which avoids Linq but uses only slightly more code.

// using System.Collections.Generic;

Dictionary<int, int> oGroups = new Dictionary<int, int>();
List<int> oList = new List<int>() { 1, 2, 3, 4, 5, 2, 2, 2, 4, 4, 4, 1 };

foreach (int iCurrentValue in oList)
{
    if (oGroups.ContainsKey(iCurrentValue))
        oGroups[iCurrentValue]++;
    else
        oGroups.Add(iCurrentValue, 1);
}

foreach (KeyValuePair<int, int> oGroup in oGroups)
{
    Console.WriteLine($"Value {oGroup.Key} appears {oGroup.Value} times.");
}

Solution 6 - C#

this code returns a dictionary that contain the world and the occurrence:

            var wordsDic = Words
            .GroupBy(p => p)
            .ToDictionary(p => p.Key, q => q.Count());

Solution 7 - C#

Your outer loop is looping over all the words in the list. It's unnecessary and will cause you problems. Remove it and it should work properly.

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionNona UrbizView Question on Stackoverflow
Solution 1 - C#JP AliotoView Answer on Stackoverflow
Solution 2 - C#Stan R.View Answer on Stackoverflow
Solution 3 - C#Steve MitchamView Answer on Stackoverflow
Solution 4 - C#The ArtistView Answer on Stackoverflow
Solution 5 - C#Ed HView Answer on Stackoverflow
Solution 6 - C#mojtaba karimiView Answer on Stackoverflow
Solution 7 - C#Paul SonierView Answer on Stackoverflow