I have RAML schema which contains       `&quot;javaType&quot;: &quot;java.util.Map&lt;String, java.util.List&lt;Employee&gt;&gt;&quot;`

I have separate schema (employee.schema) available which represent class Employee.

But as I have not used employee.schema in RAML so it is not generating class Employee and throws an Error while converting RAML to Java.

    {
      &quot;$schema&quot;: &quot;http://json-schema.org/schema#&quot;,
      &quot;type&quot;: &quot;object&quot;,
      &quot;description&quot;: &quot;Desc&quot;,
      &quot;properties&quot;: {
        &quot;employeeGroups&quot;: {
          &quot;type&quot;: &quot;object&quot;,
          &quot;javaType&quot;: &quot;java.util.Map&lt;String, java.util.List&lt;Employee&gt;&gt;&quot;
        }
      },
      &quot;additionalProperties&quot;: false
    }

Can anybody share comments how to represent `&quot;javaType&quot;: &quot;java.util.Map&lt;String, java.util.List&lt;Employee&gt;&gt;&quot;` in RAML ?


    RAML Version: 1.0


All Raml 1.0 Solutions on Gang of Coders

Total of 1 Raml 1.0 Solutions

RAML 1.0 representation of Java Map