Why XML-Serializable class need a parameterless constructor

C#.NetXml Serialization

C# Problem Overview


I'm writing code to do Xml serialization. With below function.

public static string SerializeToXml(object obj)
{
    XmlSerializer serializer = new XmlSerializer(obj.GetType());
    using (StringWriter writer = new StringWriter())
    {
        serializer.Serialize(writer, obj);
        return writer.ToString();
    }
}

If the argument is a instance of class without parameterless constructor, it will throw a exception.

> Unhandled Exception: > System.InvalidOperationException: > CSharpConsole.Foo cannot be serialized > because it does not have a > parameterless constructor. at > System.Xml.Serialization.TypeDesc.CheckSupported() > at > System.Xml.Serialization.TypeScope.GetTypeDesc(Type > type, MemberInfo sourc e, Boolean > directReference, Boolean throwOnError) > at > System.Xml.Serialization.ModelScope.GetTypeModel(Type > type, Boolean direct Reference) at > System.Xml.Serialization.XmlReflectionImporter.ImportTypeMapping(Type > type , XmlRootAttribute root, String > defaultNamespace) at > System.Xml.Serialization.XmlSerializer..ctor(Type > type, String defaultName space) at > System.Xml.Serialization.XmlSerializer..ctor(Type > type)

Why must there be a parameterless constructor in order to allow xml serialization to succeed?

EDIT: thanks for cfeduke's answer. The parameterless constructor can be private or internal.

C# Solutions


Solution 1 - C#

During an object's de-serialization, the class responsible for de-serializing an object creates an instance of the serialized class and then proceeds to populate the serialized fields and properties only after acquiring an instance to populate.

You can make your constructor private or internal if you want, just so long as it's parameterless.

Solution 2 - C#

This is a limitation of XmlSerializer. Note that BinaryFormatter and DataContractSerializer do not require this - they can create an uninitialized object out of the ether and initialize it during deserialization.

Since you are using xml, you might consider using DataContractSerializer and marking your class with [DataContract]/[DataMember], but note that this changes the schema (for example, there is no equivalent of [XmlAttribute] - everything becomes elements).

Update: if you really want to know, BinaryFormatter et al use FormatterServices.GetUninitializedObject() to create the object without invoking the constructor. Probably dangerous; I don't recommend using it too often ;-p See also the remarks on MSDN:

> Because the new instance of the object > is initialized to zero and no > constructors are run, the object might > not represent a state that is regarded > as valid by that object. The current > method should only be used for > deserialization when the user intends > to immediately populate all fields. It > does not create an uninitialized > string, since creating an empty > instance of an immutable type serves > no purpose.

I have my own serialization engine, but I don't intend making it use FormatterServices; I quite like knowing that a constructor (any constructor) has actually executed.

Solution 3 - C#

The answer is: for no good reason whatsoever.

Contrary to its name, the XmlSerializer class is used not only for serialization, but also for deserialization. It performs certain checks on your class to make sure that it will work, and some of those checks are only pertinent to deserialization, but it performs them all anyway, because it does not know what you intend to do later on.

The check that your class fails to pass is one of the checks that are only pertinent to deserialization. Here is what happens:

  • During deserialization, the XmlSerializer class will need to create instances of your type.

  • In order to create an instance of a type, a constructor of that type needs to be invoked.

  • If you did not declare a constructor, the compiler has already supplied a default parameterless constructor, but if you did declare a constructor, then that's the only constructor available.

  • So, if the constructor that you declared accepts parameters, then the only way to instantiate your class is by invoking that constructor which accepts parameters.

  • However, XmlSerializer is not capable of invoking any constructor except a parameterless constructor, because it does not know what parameters to pass to constructors that accept parameters. So, it checks to see if your class has a parameterless constructor, and since it does not, it fails.

So, if the XmlSerializer class had been written in such a way as to only perform the checks pertinent to serialization, then your class would pass, because there is absolutely nothing about serialization that makes it necessary to have a parameterless constructor.

As others have already pointed out, the quick solution to your problem is to simply add a parameterless constructor. Unfortunately, it is also a dirty solution, because it means that you cannot have any readonly members initialized from constructor parameters.

In addition to all this, the XmlSerializer class could have been written in such a way as to allow even deserialization of classes without parameterless constructors. All it would take would be to make use of "The Factory Method Design Pattern" (Wikipedia). From the looks of it, Microsoft decided that this design pattern is far too advanced for DotNet programmers, who apparently should not be unnecessarily confused with such things. So, DotNet programmers should better stick to parameterless constructors, according to Microsoft.

Solution 4 - C#

First of all, this what is written in documentation. I think it is one of your class fields, not the main one - and how you want deserialiser to construct it back w/o parameterless construction ?

I think there is a workaround to make constructor private.

Attributions

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionMorgan ChengView Question on Stackoverflow
Solution 1 - C#cfedukeView Answer on Stackoverflow
Solution 2 - C#Marc GravellView Answer on Stackoverflow
Solution 3 - C#Mike NakisView Answer on Stackoverflow
Solution 4 - C#Dmitry KhalatovView Answer on Stackoverflow