Why is division in Ruby returning an integer instead of decimal value?
RubyMathFloating PointDivisionInteger DivisionRuby Problem Overview
For example:
9 / 5 #=> 1
but I expected 1.8
. How can I get the correct decimal (non-integer) result? Why is it returning 1
at all?
Ruby Solutions
Solution 1 - Ruby
It’s doing integer division. You can use to_f
to force things into floating-point mode:
9.to_f / 5 #=> 1.8
9 / 5.to_f #=> 1.8
This also works if your values are variables instead of literals. Converting one value to a float is sufficient to coerce the whole expression to floating point arithmetic.
Solution 2 - Ruby
It’s doing integer division. You can make one of the numbers a Float
by adding .0
:
9.0 / 5 #=> 1.8
9 / 5.0 #=> 1.8
Solution 3 - Ruby
There is also the Numeric#fdiv
method which you can use instead:
9.fdiv(5) #=> 1.8
Solution 4 - Ruby
You can check it with irb:
$ irb
>> 2 / 3
=> 0
>> 2.to_f / 3
=> 0.666666666666667
>> 2 / 3.to_f
=> 0.666666666666667
Solution 5 - Ruby
You can include the ruby mathn
module.
require 'mathn'
This way, you are going to be able to make the division normally.
1/2 #=> (1/2)
(1/2) ** 3 #=> (1/8)
1/3*3 #=> 1
Math.sin(1/2) #=> 0.479425538604203
This way, you get exact division (class Rational) until you decide to apply an operation that cannot be expressed as a rational, for example Math.sin
.
Solution 6 - Ruby
Change the 5
to 5.0
. You're getting integer division.
Solution 7 - Ruby
Fixnum#to_r is not mentioned here, it was introduced since ruby 1.9. It converts Fixnum into rational form. Below are examples of its uses. This also can give exact division as long as all the numbers used are Fixnum.
a = 1.to_r #=> (1/1)
a = 10.to_r #=> (10/1)
a = a / 3 #=> (10/3)
a = a * 3 #=> (10/1)
a.to_f #=> 10.0
Example where a float operated on a rational number coverts the result to float.
a = 5.to_r #=> (5/1)
a = a * 5.0 #=> 25.0