Why is 08 not a valid integer literal in Java?

JavaNumbersInt

Java Problem Overview


Why is 08 considered an out of range int but 07 and below are not?

Java Solutions


Solution 1 - Java

In Java and several other languages, an integer literal beginning with 0 is interpreted as an octal (base 8) quantity.

For single-digit numbers (other than 08 and 09, which are not allowed), the result is the same, so you might not notice that they are being interpreted as octal. However, if you write numbers with more than one significant digit you might be confused by the result.

For example:

010 ==  8
024 == 20

Since octal literals are usually not what you want, you should always take care to never begin an integer literal with 0, unless of course you are actually trying to write zero by itself.

Solution 2 - Java

Any number prefixed with a 0 is considered octal. Octal numbers can only use digits 0-7, just like decimal can use 0-9, and binary can use 0-1.

// octal to decimal
01  // 1
02  // 2
07  // 7
010 // 8
020 // 16

// octal to binary (excluding most significant bit)
01  // 1 
02  // 10
07  // 111
010 // 1000 
020 // 10000

> There are 10 types of people, those who understand ternary, those who don't, and those who think this is a stupid joke.

Solution 3 - Java

From the Java specification:

> An octal numeral consists of an ASCII digit 0 followed by one or more of the ASCII digits 0 through 7 and can represent a positive, zero, or negative integer.

Solution 4 - Java

Leading zero means the value is in octal. 8 is not an octal digit, no more than 2 is valid in binary or G is valid in hexadecimal.

Solution 5 - Java

In Java, if you are defining an int with a leading '0' denotes that you are defining a number in Octal.

int a = 08 is giving out of range error because there is no any number '8' in Octal. Octal provides 0-7 numbers only.

If you define a = 07 then it's not giving out of range error because the numbers '0' and '7' are within the Octal's range.

Solution 6 - Java

In most of programming language like Java and C/C++, the number with leading zero are interpreted as octal number. As we know octal numbers are only represented within 0 to 7 digits only. Hence numbers like 05,03,054 are valid but the numbers like 078,0348,09,08 are tends to invalid.

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
Questionuser871303View Question on Stackoverflow
Solution 1 - JavaStuart CookView Answer on Stackoverflow
Solution 2 - JavacwallenpooleView Answer on Stackoverflow
Solution 3 - JavaMahmoud HanafyView Answer on Stackoverflow
Solution 4 - Javauser149341View Answer on Stackoverflow
Solution 5 - JavaAvijit KarmakarView Answer on Stackoverflow
Solution 6 - JavaAshwin JView Answer on Stackoverflow