Why does datetime->days always returns a positive number
PhpDatetimePhp Problem Overview
// Difference from a date in the future:
$a = new DateTime('2000-01-01');
$b = new DateTime('2000-01-05');
$interval = $b->diff($a);
return $interval->days; // Returns 4
// Difference from a date in the past:
$a = new DateTime('2000-01-01');
$b = new DateTime('1999-12-28');
$interval = $a->diff($b); // Arguments swapped
return $interval->days; // Returns 4
Why do both of these functions return positive 4? How do I return a negative number if a date is in the past?
Php Solutions
Solution 1 - Php
You could use DateInterval::format
.
return $interval->format("%r%a");
Cast to int if needed:
return (int)$interval->format("%r%a");
Solution 2 - Php
If Date is in past then invert will 1.
If Date is in future then invert will 0.
$invert = $interval->invert;
Solution 3 - Php
Here is your answer:
$today = new DateTime();
$date = new DateTime('2013-03-10');
$interval = $today->diff($date);
echo $interval->format("%r%a");
Solution 4 - Php
When you are diffing two DateTime objects, the following rule applies:
$objA->diff($objB) == $objB - $objA
As an example:
$todayDateObj = new \DateTime('2016/5/26');
$foundedDateObj = new \DateTime('1773/7/4');
$interval = $todayDateObj->diff($foundedDateObj);
echo $interval->format('%r%a') . "\n\n";
// -88714
$interval2 = $foundedDateObj->diff($todayDateObj);
echo $interval2->format('%r%a');
// 88714
Solution 5 - Php
you can use timestamp like this.
<?php
$date1 = '2015-01-02';
$date2 = '2015-01-05';
$diff = strtotime($date1, 'Y-m-d') - strtotime($date2, 'Y-m-d');
?>
$diff will return negative or positive.