Why does csvwriter.writerow() put a comma after each character?

PythonCsv

Python Problem Overview


This code opens the URL and appends the /names at the end and opens the page and prints the string to test1.csv:

import urllib2
import re
import csv

url = ("http://www.example.com")
bios = [u'/name1', u'/name2', u'/name3']
csvwriter = csv.writer(open("/test1.csv", "a"))

for l in bios:
    OpenThisLink = url + l
    response = urllib2.urlopen(OpenThisLink)
    html = response.read()
    item = re.search('(JD)(.*?)(\d+)', html)
    if item:
        JD = item.group()
        csvwriter.writerow(JD)
    else:
        NoJD = "NoJD"
        csvwriter.writerow(NoJD)

But I get this result:

J,D,",", ,C,o,l,u,m,b,i,a, ,L,a,w, ,S,c,h,o,o,l,....

If I change the string to ("JD", "Columbia Law School" ....) then I get

JD, Columbia Law School...)

I couldn't find in the documentation how to specify the delimeter.

If I try to use delimeter I get this error:

TypeError: 'delimeter' is an invalid keyword argument for this function

Python Solutions


Solution 1 - Python

It expects a sequence (eg: a list or tuple) of strings. You're giving it a single string. A string happens to be a sequence of strings too, but it's a sequence of 1 character strings, which isn't what you want.

If you just want one string per row you could do something like this:

csvwriter.writerow([JD])

This wraps JD (a string) with a list.

Solution 2 - Python

The csv.writer class takes an iterable as it's argument to writerow; as strings in Python are iterable by character, they are an acceptable argument to writerow, but you get the above output.

To correct this, you could split the value based on whitespace (I'm assuming that's what you want)

csvwriter.writerow(JD.split())

Solution 3 - Python

This happens, because when group() method of a MatchObject instance returns only a single value, it returns it as a string. When there are multiple values, they are returned as a tuple of strings.

If you are writing a row, I guess, csv.writer iterates over the object you pass to it. If you pass a single string (which is an iterable), it iterates over its characters, producing the result you are observing. If you pass a tuple of strings, it gets an actual string, not a single character on every iteration.

Solution 4 - Python

To put it another way - if you add square brackets around the whole output, it will be treated as one item, so commas won't be added. e.g. instead of:

spamwriter.writerow(matrix[row]['id'],matrix[row]['value'])

use:

spamwriter.writerow([matrix[row]['id'] + ',' + matrix[row]['value']])

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Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionZeynelView Question on Stackoverflow
Solution 1 - PythonLaurence GonsalvesView Answer on Stackoverflow
Solution 2 - PythonGabriel ReidView Answer on Stackoverflow
Solution 3 - PythonshylentView Answer on Stackoverflow
Solution 4 - PythonDyonnView Answer on Stackoverflow