Why can't I forward-declare a class in a namespace using double colons?

class Namespace::Class;

Why do I have to do this?:

namespace Namespace {
    class Class;
}

Using VC++ 8.0, the compiler issues:

> error C2653: 'Namespace' : is not a class or namespace name

I assume that the problem here is that the compiler cannot tell whether Namespace is a class or a namespace? But why does this matter since it's just a forward declaration?

Is there another way to forward-declare a class defined in some namespace? The syntax above feels like I'm "reopening" the namespace and extending its definition. What if Class were not actually defined in Namespace? Would this result in an error at some point?

You're getting correct answers, let me just try re-wording:

class Namespace::Class; > Why do I have to do this?

You have to do this because the term Namespace::Class is telling the compiler:

> ...OK, compiler. Go find the > namespace named Namespace, and within > that refer to the class named Class.

But the compiler doesn't know what you're talking about because it doesn't know any namespace named Namespace. Even if there were a namespace named Namespace, as in:

namespace Namespace
{
};

class Namespace::Class;

it still wouldn't work, because you can't declare a class within a namespace from outside that namespace. You have to be in the namespace.

So, you can in fact forward declare a class within a namespace. Just do this:

namespace Namespace
{
	class Class;
};

Because you can't. In C++ language fully-qualified names are only used to refer to existing (i.e. previously declared) entities. They can't be used to introduce new entities.

And you are in fact "reopening" the namespace to declare new entities. If the class Class is later defined as a member of different namespace - it is a completely different class that has nothing to do with the one you declared here.

Once you get to the point of defining the pre-declared class, you don't need to "reopen" the namespace again. You can define it in the global namespace (or any namespace enclosing your Namespace) as

class Namespace::Class {
  /* whatever */
};

Since you are referring to an entity that has already been declared in namespace Namespace, you can use qualified name Namespace::Class.

I suppose it's for the same reason you cannot declare nested namespaces in one go like this:

namespace Company::Communications::Sockets {
}

and you have to do this:

namespace Company {
  namespace Communications {
    namespace Sockets {
    }
  }
}

It would not be clear what a forward declared variable's type actually is. The forward declaration class Namespace::Class; could mean

namespace Namespace {
  class Class;
}

or

class Namespace {
public:
  class Class;
};

There's a lot of excellent answers about the rationale involved in disallowing it. I just want to provide the boring standardese clause the specifically prohibits it. This holds true for C++17 (n4659).

The paragraph in question is [class.name]/2:

> A declaration consisting solely of class-key identifier; is either a > redeclaration of the name in the current scope or a forward > declaration of the identifier as a class name. It introduces the class > name into the current scope.

The above defines what constitutes a forward declaration (or redclaration of a class). Essentially, it must be one of class identifier;, struct identifier; or union identifier; where identifer is the common lexical definition in [lex.name]:

> identifier: > identifier-nondigit > identifier identifier-nondigit > identifier digit > identifier-nondigit: > nondigit > universal-character-name > nondigit: one of > a b c d e f g h i j k l m > n o p q r s t u v w x y z > A B C D E F G H I J K L M > N O P Q R S T U V W X Y Z _ > digit: one of > 0 1 2 3 4 5 6 7 8 9

Which is the production of the common scheme [a-zA-Z_][a-zA-Z0-9_]* we are all familiar with. As you can see, this precludes class foo::bar; from being a valid forward declaration, because foo::bar is not an identifier. It's a fully qualified name, something different.