Which is a better way to check if an array has more than one element?
PhpArraysPhp Problem Overview
I just need to check if an array has more than one element. I am trying to do it this way :
if (isset($arr['1']))
the other traditional way is
if (sizeof($arr)>1)
Which of the two is better? In such situaions, how should I judge between two alternate methods? Is there any performance check meter available to measure which is better?
Php Solutions
Solution 1 - Php
Use this
if (sizeof($arr) > 1) {
....
}
Or
if (count($arr) > 1) {
....
}
sizeof() is an alias for count(), they work the same.
Edit:
Answering the second part of the question:
The two lines of codes in the question are not alternative methods, they perform different functions. The first checks if the value at $arr['1'] is set, while the second returns the number of elements in the array.
Solution 2 - Php
if(is_array($arr) && count($arr) > 1)
Just to be sure that $arr is indeed an array.
sizeof is an alias of count, I prefer to use count because:
- 1 less character to type
- sizeof at a quick glance might mean a size of an array in terms of memory, too technical :(
Solution 3 - Php
if (count($arr) >= 2)
{
// array has at least 2 elements
}
sizeof() is an alias for count(). Both work with non-arrays too, but they will only return values greater than 1 if the argument is either an array or a Countable object, so you're pretty safe with this.
Solution 4 - Php
Obviously using count($arr) > 1 (sizeof is just an alias for count) is the best solution.
Depending on the structure of your array, there might be tons of elements but no $array['1'] element.
Solution 5 - Php
Use count()
if (count($my_array) > 1) {
// do
}
this page explains it pretty well http://phparraylength.com/
Solution 6 - Php
I prefer the count() function instead of sizeOf() as sizeOf() is only an alias of count() and does not mean the same in many other languages. Many programmers expect sizeof() to return the amount of memory allocated.
Solution 7 - Php
For checking an array empty() is better than sizeof().
If the array contains huge amount of data. It will takes more times for counting the size of the array. But checking empty is always easy.
//for empty
if(!empty($array))
echo 'Data exist';
else
echo 'No data';
//for sizeof
if(sizeof($array)>1)
echo 'Data exist';
else
echo 'No data';
Solution 8 - Php
isset() only checks if a variable is set.. Has got nothing to do with size or what the array contains
Solution 9 - Php
I assume $arr is an array then this is what you are looking for
if ( sizeof($arr) > 1) ...
Solution 10 - Php
The first method
if (isset($arr['1']))
will not work on an associative array.
For example, the following code displays "Nope, not more than one."
$arr = array(
'a' => 'apple',
'b' => 'banana',
);
if (isset($arr['1'])) {
echo "Yup, more than one.";
} else {
echo "Nope, not more than one.";
}
Solution 11 - Php
I do my array looping and getting filled defaults accordingly in Swift 4/5
for index in 0..<3
{
let isIndexValid = allObjects.indices.contains(index)
var yourObject:Class = Class()
if isIndexValid { yourObject = allObjects[index]}
resultArray.append(yourObject)
}