The Oracle/Sun guidelines (&quot;Code Conventions for the Java TM Programming Language&quot;) tell us to break before an operator.  And they give this example.

    if ((condition1 &amp;&amp; condition2)
            || (condition3 &amp;&amp; condition4)
            ||!(condition5 &amp;&amp; condition6)) {
        doSomethingAboutIt();
    } 

Many companies that I&#39;ve worked for adopt the Oracle/Sun guidelines as the standard for their own code.

Refer http://www.oracle.com/technetwork/java/javase/documentation/codeconventions-136091.html#248


I believe the correct answer is `&lt;CTRL&gt;+&lt;SHIFT&gt;+F` in Eclipse :)

This is completely subjective.  Coding standards vary from shop to shop.  To steal from yshavit&#39;s comment:  Do whatever you want unless you are working in a team environment, in which case you should follow the team standards. 

I&#39;m a fan of the second pattern.

This is a preference question. But usually you want to follow the style guidelines of either your company or whoever else is working on the codebase with you. As long as it&#39;s consistent, any style is fine.

Personally, I&#39;d keep everything on the same line. (ever dealt with tabs vs. spaces?)


However, if you have enough conditions to fill multiple lines, you should probably break your problem into smaller pieces.

I&#39;m new to the bootstrap framework.

**Logo Increasing Height of NavBar:**

In my navigation bar, I have inserted a logo that has a height of 50px. This obviously makes the navbar taller. I have not adjusted any CSS for this, it is simply the logo that is forcing the increased height.

**Problem:**

The links in the navbar are aligned to the top of the now taller navbar.

**Goal:**

I&#39;d like the links vertically centered in the navbar as that will look much better.


----------
My assumption was to play with line-height values or padding. However, that introduced the problem of still taking effect on mobile browsers (when it switches to the toggle menu) so my expanded menu ends up being way too tall that it looked silly.

Any insight is greatly appreciated?


My CSS is the default bootstrap CSS downloaded with the latest version 3.0.2.

Here is my HTML:

    &lt;!-- Begin NavBar --&gt;
    &lt;div class=&quot;navbar navbar-inverse navbar-static-top&quot; role=&quot;navigation&quot;&gt;
      &lt;div class=&quot;container&quot;&gt;
        &lt;div class=&quot;navbar-header&quot;&gt;
          &lt;button type=&quot;button&quot; class=&quot;navbar-toggle&quot; data-toggle=&quot;collapse&quot; data-target=&quot;.menu2&quot;&gt;
            &lt;span class=&quot;sr-only&quot;&gt;Toggle navigation&lt;/span&gt;
            &lt;span class=&quot;icon-bar&quot;&gt;&lt;/span&gt;
            &lt;span class=&quot;icon-bar&quot;&gt;&lt;/span&gt;
            &lt;span class=&quot;icon-bar&quot;&gt;&lt;/span&gt;
          &lt;/button&gt;
          &lt;span class=&quot;navbar-brand&quot; href=&quot;#&quot;&gt;&lt;img src=&quot;img/logo.png&quot; width=&quot;210&quot; height=&quot;50&quot; alt=&quot;My Logo&quot;&gt;&lt;/span&gt;
        &lt;/div&gt;
        		
        
        &lt;div class=&quot;navbar-collapse collapse menu2&quot;&gt;

          &lt;ul class=&quot;nav navbar-nav navbar-right&quot;&gt;
            &lt;li&gt;&lt;a href=&quot;#&quot;&gt;Link 1&lt;/a&gt;&lt;/li&gt;
            &lt;li&gt;&lt;a href=&quot;#&quot;&gt;Link 2&lt;/a&gt;&lt;/li&gt;
            &lt;li&gt;&lt;a href=&quot;#&quot;&gt;Link 3&lt;/a&gt;&lt;/li&gt;
            &lt;li&gt;&lt;a href=&quot;#&quot;&gt;Link 4&lt;/a&gt;&lt;/li&gt;
          &lt;/ul&gt;
         
        &lt;/div&gt;&lt;!--/.nav-collapse --&gt;
      &lt;/div&gt;
    &lt;/div&gt;

It is those &quot;Link 1&quot;, &quot;Link 2&quot;, &quot;Link 3&quot; and &quot;Link 4&quot; links that are aligning to the top, when I really want them to be aligned vertically in the center.

Bootstrap 3 : Vertically Center Navigation Links when Logo Increasing The Height of Navbar

I&#39;m trying to compile the Sam Hare&#39;s [Struck code][1].

I&#39;m using mac OSX10.9, opencv 2.4.6 and Eigen 2.0.17.

Eigen and opencv headers are stored in /opt/local/include while opencv dylib in /opt/local/lib.

I modified the Hare&#39;s Makefile to work on this folder. When I type make on the terminal:

    g++ -L/opt/local/lib -lopencv_core -lopencv_highgui -lopencv_imgproc src/Config.o src/Features.o src/HaarFeature.o src/HaarFeatures.o src/HistogramFeatures.o src/ImageRep.o src/LaRank.o src/MultiFeatures.o src/RawFeatures.o src/Sampler.o src/Tracker.o src/main.o src/GraphUtils/GraphUtils.o -o struck

I get these errors:

    Undefined symbols for architecture x86_64:  
    &quot;cv::namedWindow(std::__1::basic_string&lt;char,
    std::__1::char_traits&lt;char&gt;, std::__1::allocator&lt;char&gt; &gt; const&amp;,
    int)&quot;, referenced from:
          _main in main.o   &quot;cv::split(cv::Mat const&amp;, std::__1::vector&lt;cv::Mat, std::__1::allocator&lt;cv::Mat&gt; &gt;&amp;)&quot;,
    referenced from:
          ImageRep::ImageRep(cv::Mat const&amp;, bool, bool, bool) in ImageRep.o   &quot;cv::imread(std::__1::basic_string&lt;char,
    std::__1::char_traits&lt;char&gt;, std::__1::allocator&lt;char&gt; &gt; const&amp;,
    int)&quot;, referenced from:
          _main in main.o   &quot;cv::imshow(std::__1::basic_string&lt;char, std::__1::char_traits&lt;char&gt;, std::__1::allocator&lt;char&gt; &gt; const&amp;,
    cv::_InputArray const&amp;)&quot;, referenced from:
          LaRank::Debug() in LaRank.o
          Tracker::Debug() in Tracker.o
          _main in main.o ld: symbol(s) not found for architecture x86_64 clang: error: linker command failed with exit code 1 (use -v to see
    invocation)

Any ideas? Thanks!

  [1]: http://www.samhare.net/research/struck/code

g++ ld: symbol(s) not found for architecture x86_64

Apparently &quot;if&quot;, &quot;and&quot;, and &quot;or&quot; are such generic search parameters that I can&#39;t find the answer on google for my life.  Which of these is the correct format according to the Java standards?

**Option 1**:

    if (condition1
        &amp;&amp; condition2
        &amp;&amp; condition3) ...

or **Option 2**:

    if (condition1 &amp;&amp;
        condition2 &amp;&amp;
        condition3) ...

What&#39;s the proper way to format &quot;if&quot; statements in Java with multiline &quot;ands&quot; or &quot;ors&quot;?

Apparently "if", "and", and "or" are such generic search parameters that I can't find the answer on google for my life. Which of these is the correct format according to the Java standards?
Option 1:
<pre><code class="hljs language-markdown">if (condition1
 &#x26;&#x26; condition2
 &#x26;&#x26; condition3) ...
</code></pre>
or Option 2:
<pre><code class="hljs language-markdown">if (condition1 &#x26;&#x26;
 condition2 &#x26;&#x26;
 condition3) ...
</code></pre>

Is there any annotation for a `Filter` class (for web applications) in Spring Boot? Perhaps `@Filter`?

I want to add a custom filter in my project.

[The Spring Boot Reference Guide][0] mentioned about
`FilterRegistrationBean`, but I am not sure how to use it.

  [0]: http://docs.spring.io/spring-boot/docs/current-SNAPSHOT/reference/htmlsingle/



How can I add a filter class in Spring Boot?

 I&#39;m into a quite strange position (from my java-newbie point of view):

 1. using Eclipse I wrote a &quot;java program&quot; (some .java files with classes into) which essentially (batch) reads a text *.csv file, &quot;evaluates&quot; its contents, and writes out results into an *_out.csv text file. To locate the input file it uses a &quot;file chooser&quot; (got sample from here: http://docs.oracle.com/javase/tutorial/uiswing/components/filechooser.html)

 2. I debugged all the code and, using the debugger, **it works**.

 3. I ran the code (the main class, which calls all the other in sequence) and **it works**, *while in Eclipse*.

 4. I exported all the project&#39;s contents into a &quot;runnable jar&quot; file.

Notice that, file chooser apart, this is mainly a &quot;batch&quot; which reads and writes: nearly no User Interface at all. While into Eclipse I shown some internal results using something like &quot;*if(debug) System.out.print(&quot;something to print&quot;);*&quot; providing to set &quot;*debug*&quot; TRUE while debugging and FALSE while in production environment.

 ALL of the above **worked!**

 Now, starting the runnable jar (double-click on the jar file, in Win/XP), **I can see** the file chooser and I can use it but, after choosing the input file... *nothing more*: (having no user interface) I don&#39;t know if the file was read, I don&#39;t see any generated output file, and I&#39;ve even no &quot;console&quot; to list any intermediate debug message, to see if the jar is working, even if I re-export it with the debug variable set to TRUE.

 Is there a way to &quot;runtime debug&quot; the running jar (like VB&#39;s MsgBox, or something other)? some kind of &quot;log file&quot; I can &quot;enable&quot; or look into? (obviously, as my jar is not writing the result file, I just can&#39;t try writing a *.log too)
 I have also to say I just **can&#39;t** install other than Eclipse on my machine (and just been lucky it ran), so no usual developer&#39;s tools, utilities and other useful things.

how can I debug a jar at runtime?

I&#39;m adding three different objects to an ArrayList, but the list contains three copies of the last object I added. 

For example:

    for (Foo f : list) {
      System.out.println(f.getValue());
    }    

Expected:

    0
    1
    2

Actual:

    2
    2
    2


What mistake have I made?

&lt;sup&gt;Note: this is designed to be a canonical Q&amp;A for the numerous similar issues that arise on this site.&lt;/sup&gt;

Why does my ArrayList contain N copies of the last item added to the list?

I&#39;m running Windows 8.1 x64 with Java 7 update 45 x64 (no 32 bit Java installed) on a Surface Pro 2 tablet.

The code below takes 1688ms when the type of i is a long and 109ms when i is an int. Why is long (a 64 bit type) an order of magnitude slower than int on a 64 bit platform with a 64 bit JVM?

My only speculation is that the CPU takes longer to add a 64 bit integer than a 32 bit one, but that seems unlikely. I suspect Haswell doesn&#39;t use ripple-carry adders.

I&#39;m running this in Eclipse Kepler SR1, btw.


    public class Main {
    
        private static long i = Integer.MAX_VALUE;
    
        public static void main(String[] args) {	
            System.out.println(&quot;Starting the loop&quot;);
            long startTime = System.currentTimeMillis();
            while(!decrementAndCheck()){
            }
            long endTime = System.currentTimeMillis();
            System.out.println(&quot;Finished the loop in &quot; + (endTime - startTime) + &quot;ms&quot;);
        }

        private static boolean decrementAndCheck() {
            return --i &lt; 0;
        }

    }


Edit: Here are the results from equivalent C++ code compiled by VS 2013 (below), same system. &lt;del&gt;long: 72265ms int: 74656ms&lt;/del&gt;  Those results were in debug 32 bit mode.

In 64 bit release mode: &lt;del&gt;long: 875ms&lt;/del&gt; long long:  906ms int: 1047ms


This suggests that the result I observed is JVM optimization weirdness rather than CPU limitations.




    #include &quot;stdafx.h&quot;
    #include &quot;iostream&quot;
    #include &quot;windows.h&quot;
    #include &quot;limits.h&quot;

    long long i = INT_MAX;

    using namespace std;


    boolean decrementAndCheck() {
	return --i &lt; 0;
    }


    int _tmain(int argc, _TCHAR* argv[])
    {


	cout &lt;&lt; &quot;Starting the loop&quot; &lt;&lt; endl;

	unsigned long startTime = GetTickCount64();
	while (!decrementAndCheck()){
	}
	unsigned long endTime = GetTickCount64();

	cout &lt;&lt; &quot;Finished the loop in &quot; &lt;&lt; (endTime - startTime) &lt;&lt; &quot;ms&quot; &lt;&lt; endl;



    }


Edit: Just tried this again in Java 8 RTM, no significant change.

Why is long slower than int in x64 Java?

Please have a look at the following code:

    Method methodInfo = MyClass.class.getMethod(&quot;myMethod&quot;);

This works, but the method name is passed as a string, so this will compile even if myMethod does not exist.

On the other hand, Java 8 introduces a method reference feature. It is checked at compile time. It is possible to use this feature to get method info?

    printMethodName(MyClass::myMethod);

Full example:

    @FunctionalInterface
    private interface Action {
        
        void invoke();
    }
    
    private static class MyClass {
        
        public static void myMethod() {
        }
    }
    
    private static void printMethodName(Action action) {
    }

    public static void main(String[] args) throws NoSuchMethodException {
        // This works, but method name is passed as a string, so this will compile
        // even if myMethod does not exist
        Method methodInfo = MyClass.class.getMethod(&quot;myMethod&quot;);
        
        // Here we pass reference to a method. It is somehow possible to
        // obtain java.lang.reflect.Method for myMethod inside printMethodName?
        printMethodName(MyClass::myMethod);
    }

In other words I would like to have a code which is the equivalent of the following C# code:

        private static class InnerClass
        {
            public static void MyMethod()
            {
                Console.WriteLine(&quot;Hello&quot;);
            }
        }

        static void PrintMethodName(Action action)
        {
            // Can I get java.lang.reflect.Method in the same way?
            MethodInfo methodInfo = action.GetMethodInfo();
        }

        static void Main()
        {
            PrintMethodName(InnerClass.MyMethod);
        }


How to get the MethodInfo of a Java 8 method reference?

Current Codes:

    &lt;?php

      // See the AND operator; How do I simplify/shorten this line?
      if( $some_variable !== &#39;uk&#39; &amp;&amp; $some_variable !== &#39;in&#39; ) {
    
        // Do something
    
      }

    ?&gt;

And:

    &lt;?php
    
      // See the OR operator; How do I simplify/shorten this line?
      if( $some_variable !== &#39;uk&#39; || $some_variable !== &#39;in&#39; ) {
    
        // Do something else
    
      }
    
    ?&gt;

Is there a simpler (i.e. shorter) way to write the two conditions?

**NOTE:** Yes, they are different, and I am expecting different ways to shorten the codes.

Simpler way to check if variable is not equal to multiple string values?

So far from I have been searching through the net, the statement always have if and else condition such as `a ? b : c`. I would like to know whether the `if` ternary statement can be used without `else`. 
Assuming i have the following code, i wish to close the `PreparedStatement` if it is not null

(I am using Java programming language.)

    PreparedStatement pstmt;
 
    //.... 

    (pstmt!=null) ? pstmt.close : &lt;do nothing&gt;;

If without else ternary operator

I&#39;d like to to some thing similar to JavaScript&#39;s
      
    var foo = true;
    foo &amp;&amp; doSometing();

but this doesn&#39;t seem to work in PHP.

I&#39;m trying to add a class to a label if a condition is met and I&#39;d prefer to keep the embedded PHP down to a minimum for the sake of readability.

So far I&#39;ve got:

    &lt;?php $redText=&#39;redtext &#39;;?&gt;
    &lt;label class=&quot;&lt;?php if ($requestVars-&gt;_name==&#39;&#39;)echo $redText;?&gt;labellong&quot;&gt;_name*&lt;/label&gt;
    &lt;input name=&quot;_name&quot; value=&quot;&lt;?php echo $requestVars-&gt;_name; ?&gt;&quot;/&gt;

but even then the IDE is complaining that I have an if statement without braces.

One line if statement in PHP

How do I write this multi-line, complex condition if statement in Ruby?

      if ( (aa != nil &amp;&amp; self.prop1 == aa.decrypt)   
          || (bb != nil &amp;&amp; self.prop2 == bb.decrypt)  
        ) &amp;&amp; (self.id.nil? || self.id != id) 
        return true
      end

I&#39;m getting `Syntax error; unexpected tOROP`.


In Java, I could write

    if (
         ( (aa != null &amp;&amp; aa.prop1.equals(aa.decrypt()))
         || (bb != null &amp;&amp; bb.prop2.equals(bb.decrypt()))
         )
         &amp;&amp; (this.id != id)
       ) {
      
       return true;
    }



How do I write a complex multi-line if condition in Ruby?

I am trying to set the text color using css in a jinja2 template.  In the following code  I want to set the output string to print in a specific font color if the variable contains a string.  Everytime the template is generated though it prints in red due to the else statement, it never see the first two conditions even though the output should be matched, I can tell what the output from the variable is when the table generates and it is as expected.  I know my css is correct due to the printing of the string in red by default.

My first thought was to enclose the string I was checking for in quotes but that didn&#39;t work.  Next was that jinja was not expanding `RepoOutput[RepoName.index(repo)]` but the for loop above it works, `RepoName` is expanded upon properly.  I know if I add the braces it will print the variable which I am fairly certain will either break the template or just not work.

I tried looking at these sites and went through the list of global expressions as well but couldn&#39;t find any examples similar to mine or a direction in which to look further.

http://jinja.pocoo.org/docs/templates/#if

http://wsgiarea.pocoo.org/jinja/docs/conditions.html

   
       {% for repo in RepoName %}
           &lt;tr&gt;
              &lt;td&gt; &lt;a href=&quot;http://mongit201.be.monster.com/icinga/{{ repo }}&quot;&gt;{{ repo }}&lt;/a&gt; &lt;/td&gt;
           {% if error in RepoOutput[RepoName.index(repo)] %}
              &lt;td id=error&gt; {{ RepoOutput[RepoName.index(repo)] }} &lt;/td&gt; &lt;!-- I want this in green if it is up-to-date, otherwise I want it in red --&gt;
           {% elif Already in RepoOutput[RepoName.index(repo)] %}
              &lt;td id=good&gt; {{ RepoOutput[RepoName.index(repo)] }} &lt;/td&gt;   &lt;!-- I want this in green if it is up-to-date, otherwise I want it in red --&gt;
           {% else %}
                &lt;td id=error&gt; {{ RepoOutput[RepoName.index(repo)] }} &lt;/td&gt; &lt;!-- I want this in green if it is up-to-date, otherwise I want it in red --&gt;
           &lt;/tr&gt;

           {% endif %}
       {% endfor %}

Thanks

Jinja2 template not rendering if-elif-else statement properly

I&#39;m trying to format the current time using this format `yyyyMMddHHmmss`.

    t := time.Now()
    fmt.Println(t.Format(&quot;yyyyMMddHHmmss&quot;))

That is outputting:

    yyyyMMddHHmmss

Any suggestions?



How to format current time using a yyyyMMddHHmmss format?

I&#39;m sure this is covered in plenty of places, but I don&#39;t know the exact name of the action I&#39;m trying to do so I can&#39;t really look it up.  I&#39;ve been reading an official Python book for 30 minutes trying to find out how to do this. 

Problem: I need to put a string in a certain length &quot;field&quot;. 

For example, if the name field was 15 characters long, and my name was John, I would get &quot;John&quot; followed by 11 spaces to create the 15 character field.  

I need this to work for any string put in for the variable &quot;name&quot;.  

I know it will likely be some form of formatting, but I can&#39;t find the exact way to do this. Help would be appreciated.  

How to pad a string to a fixed length with spaces in Python?

I was reading up the difference between [Thread and Processes][1] and came across the comment left by users in the second answer which stated

&gt; As so long as you don&#39;t format a floppy at the same time.

It has 27 upvotes but no one has explained the reason behind it .

I would like to know what the commentor means when he said the above comment ??

Can someone suggest a more meaningful question name which reflects what the question is asking


  [1]: https://stackoverflow.com/questions/200469/what-is-the-difference-between-a-process-and-a-thread

Why was the comment that said &quot;Don&#39;t format a floppy at the same time&quot; funny when talking about threads and processes?

I want to format date as `mm/dd/yyyy`. I tried the following and none of it works for me.
Can anyone help me with this?

reference: [ui-date][1]

    &lt;input ui-date ui-date-format=&quot;mm/dd/yyyy&quot; ng-model=&quot;valueofdate&quot; /&gt; 

    &lt;input type=&quot;date&quot; ng-model=&quot;valueofdate&quot; /&gt;


  [1]: https://github.com/angular-ui/ui-date

How to format date in angularjs

I have three date formats: `YYYY-MM-DD`, `DD.MM.YYYY`, `DD/MM/YYYY`.

Is it possible to validate and parse strings such as `2014-05-18` or `18.5.2014` or `18/05/2019`?

Content Type	Original Author	Original Content on Stackoverflow
Question	Dasmowenator	View Question on Stackoverflow
Solution 1 - Java	Dawood ibn Kareem	View Answer on Stackoverflow
Solution 2 - Java	Xuan	View Answer on Stackoverflow
Solution 3 - Java	MadConan	View Answer on Stackoverflow
Solution 4 - Java	yamafontes	View Answer on Stackoverflow

What's the proper way to format "if" statements in Java with multiline "ands" or "ors"?

Java Problem Overview

Java Solutions

Solution 1 - Java

Solution 2 - Java

Solution 3 - Java

Solution 4 - Java

g++ ld: symbol(s) not found for architecture x86_64

Bootstrap 3 : Vertically Center Navigation Links when Logo Increasing The Height of Navbar

Attributions