What's the difference between `useRef` and `createRef`?

JavascriptReactjsReact Hooks

Javascript Problem Overview


I was going through the hooks documentation when I stumbled upon useRef.

Looking at their example…

function TextInputWithFocusButton() {
  const inputEl = useRef(null);
  const onButtonClick = () => {
    // `current` points to the mounted text input element
    inputEl.current.focus();
  };
  return (
    <>
      <input ref={inputEl} type="text" />
      <button onClick={onButtonClick}>Focus the input</button>
    </>
  );
}

…it seems like useRef can be replaced with createRef.

function TextInputWithFocusButton() {
  const inputRef = createRef(); // what's the diff?
  const onButtonClick = () => {
    // `current` points to the mounted text input element
    inputRef.current.focus();
  };
  return (
    <>
      <input ref={inputRef} type="text" />
      <button onClick={onButtonClick}>Focus the input</button>
    </>
  );
}

Why do I need a hook for refs? Why does useRef exist?

Javascript Solutions


Solution 1 - Javascript

The difference is that createRef will always create a new ref. In a class-based component, you would typically put the ref in an instance property during construction (e.g. this.input = createRef()). You don't have this option in a function component. useRef takes care of returning the same ref each time as on the initial rendering.

Here's an example app demonstrating the difference in the behavior of these two functions:

import React, { useRef, createRef, useState } from "react";
import ReactDOM from "react-dom";

function App() {
  const [renderIndex, setRenderIndex] = useState(1);
  const refFromUseRef = useRef();
  const refFromCreateRef = createRef();
  if (!refFromUseRef.current) {
    refFromUseRef.current = renderIndex;
  }
  if (!refFromCreateRef.current) {
    refFromCreateRef.current = renderIndex;
  }
  return (
    <div className="App">
      Current render index: {renderIndex}
      <br />
      First render index remembered within refFromUseRef.current:
      {refFromUseRef.current}
      <br />
      First render index unsuccessfully remembered within
      refFromCreateRef.current:
      {refFromCreateRef.current}
      <br />
      <button onClick={() => setRenderIndex(prev => prev + 1)}>
        Cause re-render
      </button>
    </div>
  );
}

const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);

Edit 1rvwnj71x3

Solution 2 - Javascript

tldr

A ref is a plain JS object { current: <some value> }.

React.createRef() is a factory returning a ref { current: null } - no magic involved.

useRef(initValue) also returns a ref { current: initValue } akin to React.createRef(). Besides, it memoizes this ref to be persistent across multiple renders in a function component.

It is sufficient to use React.createRef in class components, as the ref object is assigned to an instance variable, hence accessible throughout the component and its lifecyle:

this.myRef = React.createRef(); // stores ref in "mutable" this context (class)

useRef(null) basically is equivalent to useState(React.createRef())[0] 1.


1 Replace useRef with useState + createRef

Following tweet has been enlightening for me:

> useRef() is basically useState({current: initialValue })[0].

With insights from the tldr section, we now can further conclude:

> useRef(null) is basically useState(React.createRef())[0].

Above code "abuses" useState to persist the returned ref from React.createRef(). [0] just selects the value part of useState - [1] would be the setter.

useState causes a re-render in contrast to useRef. More formally, React compares the old and new object reference for useState, when a new value is set via its setter method. If we mutate the state of useState directly (opposed to setter invocation), its behavior more or less becomes equivalent to useRef, as no re-render is triggered anymore:

// Example of mutating object contained in useState directly
const [ref] = useState({ current: null })
ref.current = 42; // doesn't cause re-render

Note: Don't do this! Use the optimized useRef API instead of reinventing the wheel. Above is for illustration purposes.

Solution 3 - Javascript

createRef always returns a new ref, which you'd generally store as a field on a class component's instance. useRef returns the same ref upon every render of a functional component's instance. This is what allows the state of the ref to persist between renders, despite you not explictly storing it anywhere.

In your second example, the ref would be re-created upon every render.

Solution 4 - Javascript

Just to highlight a purpose:

createRef is as simple as return {current: null}. It's a way to handle ref= prop in most modern way and that's it(while string-based is toooo way magic and callback-based looks too verboose).

useRef keeps some data before renders and changing it does not cause re-render(as useState does). They are rarely related. Everything you expect for class-based component go to instance fields(this.* = ) looks like candidate to be implemented with useRef in functional components.

Say useCallback works as bounded class methods(this.handleClick = .....bind(this)) and may be re-implemented(but we should not re-invent the wheel for sure) with useRef.

Another examples are DOM refs, timeout/interval IDs, any 3rd party libraries' identifiers or references.

PS I believe React team better chose different naming for useRef to avoid confusion with createRef. Maybe useAndKeep or even usePermanent.

Solution 5 - Javascript

A ref is a plain JS object { current: }.

React.useRef(initValue) return a ref { current: initValue }
	it is remember ref value across multiple render of function component.
It is advise to use in Function component
	
React.createRef(initValue) also return a ref  { current: initValue }
	it is not remember ref value across multiple render of function components.	It is advise to use in class based component

Solution 6 - Javascript

Yet another but important addition to other's answers.

You can't set a new value for createRef. But you can for useRef.

const ur = useRef();
const cr = createRef();

ur.current = 10; // you can do it, and value is set
cr.current = 10; // you can, but it's no good, it will not change it

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionRico KahlerView Question on Stackoverflow
Solution 1 - JavascriptRyan CogswellView Answer on Stackoverflow
Solution 2 - Javascriptford04View Answer on Stackoverflow
Solution 3 - JavascriptJoe ClayView Answer on Stackoverflow
Solution 4 - JavascriptskyboyerView Answer on Stackoverflow
Solution 5 - JavascriptNirav PatelView Answer on Stackoverflow
Solution 6 - JavascriptGreenView Answer on Stackoverflow