What's the difference between `raw_input()` and `input()` in Python 3?

PythonPython 3.xInput

Python Problem Overview


What is the difference between raw_input() and input() in Python 3?

Python Solutions


Solution 1 - Python

The difference is that raw_input() does not exist in Python 3.x, while input() does. Actually, the old raw_input() has been renamed to input(), and the old input() is gone, but can easily be simulated by using eval(input()). (Remember that eval() is evil. Try to use safer ways of parsing your input if possible.)

Solution 2 - Python

In Python 2, raw_input() returns a string, and input() tries to run the input as a Python expression.

Since getting a string was almost always what you wanted, Python 3 does that with input(). As Sven says, if you ever want the old behaviour, eval(input()) works.

Solution 3 - Python

Python 2:

  • raw_input() takes exactly what the user typed and passes it back as a string.

  • input() first takes the raw_input() and then performs an eval() on it as well.

The main difference is that input() expects a syntactically correct python statement where raw_input() does not.

Python 3:

  • raw_input() was renamed to input() so now input() returns the exact string.
  • Old input() was removed.

If you want to use the old input(), meaning you need to evaluate a user input as a python statement, you have to do it manually by using eval(input()).

Solution 4 - Python

In Python 3, raw_input() doesn't exist which was already mentioned by Sven.

In Python 2, the input() function evaluates your input.

Example:

name = input("what is your name ?")
what is your name ?harsha

Traceback (most recent call last):
  File "<pyshell#0>", line 1, in <module>
    name = input("what is your name ?")
  File "<string>", line 1, in <module>
NameError: name 'harsha' is not defined

In the example above, Python 2.x is trying to evaluate harsha as a variable rather than a string. To avoid that, we can use double quotes around our input like "harsha":

>>> name = input("what is your name?")
what is your name?"harsha"
>>> print(name)
harsha

raw_input()

The raw_input()` function doesn't evaluate, it will just read whatever you enter.

Example:

name = raw_input("what is your name ?")
what is your name ?harsha
>>> name
'harsha'

Example:

 name = eval(raw_input("what is your name?"))
what is your name?harsha

Traceback (most recent call last):
  File "<pyshell#11>", line 1, in <module>
    name = eval(raw_input("what is your name?"))
  File "<string>", line 1, in <module>
NameError: name 'harsha' is not defined

In example above, I was just trying to evaluate the user input with the eval function.

Solution 5 - Python

I'd like to add a little more detail to the explanation provided by everyone for the python 2 users. raw_input(), which, by now, you know that evaluates what ever data the user enters as a string. This means that python doesn't try to even understand the entered data again. All it will consider is that the entered data will be string, whether or not it is an actual string or int or anything.

While input() on the other hand tries to understand the data entered by the user. So the input like helloworld would even show the error as 'helloworld is undefined'.

In conclusion, for python 2, to enter a string too you need to enter it like 'helloworld' which is the common structure used in python to use strings.

Solution 6 - Python

If You want to ensure, that your code is running with python2 and python3, add input() function at the beginning of your script:

from sys import version_info
if version_info.major == 3:
    pass
elif version_info.major == 2:
    try:
        input = raw_input
    except NameError:
        pass
else:
    print ("Unknown python version - input function not safe")

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionpkumarView Question on Stackoverflow
Solution 1 - PythonSven MarnachView Answer on Stackoverflow
Solution 2 - PythonThomas KView Answer on Stackoverflow
Solution 3 - PythonscreenglowView Answer on Stackoverflow
Solution 4 - PythonhackwithharshaView Answer on Stackoverflow
Solution 5 - PythonRubalView Answer on Stackoverflow
Solution 6 - PythonJosef KlotznerView Answer on Stackoverflow