&gt; What does the `m` stand for in `python3.6m`?

It signifies that Python was configured `--with-pymalloc` which enables a specialized implementation for allocating memory that&#39;s faster than the system `malloc`.

&gt; How does it differ to non `m` version?

The non `m` version is, obviously, not configured with it.

&gt; In which case would I prefer to use `python3.6m` rather than `python3.6`?

Probably most usefull when writing `C` extensions, in general it shouldn&#39;t be something you should worry about.

How can I bind an event listener in rendered elements in Angular 2?

I am using Dragula drag and drop library. It creates dynamic HTML but my event is not bound to dynamic HTML elements.


How to bind event listener for rendered elements in Angular 2?

I&#39;m trying to use axios for a GET request with an API which requires an `Authorization` header.

My current code:

&lt;!-- language: lang-js --&gt;

    const AuthStr = &#39;Bearer &#39; + USER_TOKEN;

where `USER_TOKEN` is the access token needed. This string concatenation may be the issue as if I post this as `AuthStr = &#39;Bearer 41839y750138-391&#39;`, the following GET request works and returns the data I&#39;m after.

&lt;!-- language: lang-js --&gt;

    axios.get(URL, { &#39;headers&#39;: { &#39;Authorization&#39;: AuthStr } })
      .then((response =&gt; {
        console.log(response.data);
      })
      .catch((error) =&gt; {
        console.log(error);
      });

I also tried setting this as a global header with no success.

Using Axios GET with Authorization Header in React-Native App


 - What does the **`m`** stand for in `python3.6m` ? 
 - How does it differ to non **`m`** version?
 - In which case would I prefer to use `python3.6m` rather than `python3.6`?


What&#39;s the difference between python3.&lt;x&gt; and python3.&lt;x&gt;m

<ul>
<li>What does the <strong><code>m</code></strong> stand for in <code>python3.6m</code> ?</li>
<li>How does it differ to non <strong><code>m</code></strong> version?</li>
<li>In which case would I prefer to use <code>python3.6m</code> rather than <code>python3.6</code>?</li>
</ul>


Right now, I catch the exception in the `except Exception:` clause, and do `print(exception)`. The result provides no information since it always prints `&lt;class &#39;Exception&#39;&gt;`. I knew this used to work in python 2, but how do I do it in python3?

How to print an exception in Python 3?

I trying to import the nltk package in python 2.7

      import nltk
      stopwords = nltk.corpus.stopwords.words(&#39;english&#39;)
      print(stopwords[:10])

Running this gives me the following error:

    LookupError: 
    **********************************************************************
    Resource &#39;corpora/stopwords&#39; not found.  Please use the NLTK
    Downloader to obtain the resource:  &gt;&gt;&gt; nltk.download()

So therefore I open my python termin and did the following:

    import nltk  
    nltk.download()

Which gives me:

    showing info https://raw.githubusercontent.com/nltk/nltk_data/gh-pages/index.xml


However this does not seem to stop. And running it again still gives me the same error. Any thoughts where this goes wrong?



Corpora/stopwords not found when import nltk library

I have `pandas` DataFrame which I have composed from `concat`. One row consists of 96 values, I would like to split the DataFrame from the value 72.

So that the first 72 values of a row are stored in Dataframe1, and the next 24 values of a row in Dataframe2.

I create my DF as follows:

    temps = DataFrame(myData)
    datasX = concat(
    [temps.shift(72), temps.shift(71), temps.shift(70), temps.shift(69), temps.shift(68), temps.shift(67),
     temps.shift(66), temps.shift(65), temps.shift(64), temps.shift(63), temps.shift(62), temps.shift(61),
     temps.shift(60), temps.shift(59), temps.shift(58), temps.shift(57), temps.shift(56), temps.shift(55),
     temps.shift(54), temps.shift(53), temps.shift(52), temps.shift(51), temps.shift(50), temps.shift(49),
     temps.shift(48), temps.shift(47), temps.shift(46), temps.shift(45), temps.shift(44), temps.shift(43),
     temps.shift(42), temps.shift(41), temps.shift(40), temps.shift(39), temps.shift(38), temps.shift(37),
     temps.shift(36), temps.shift(35), temps.shift(34), temps.shift(33), temps.shift(32), temps.shift(31),
     temps.shift(30), temps.shift(29), temps.shift(28), temps.shift(27), temps.shift(26), temps.shift(25),
     temps.shift(24), temps.shift(23), temps.shift(22), temps.shift(21), temps.shift(20), temps.shift(19),
     temps.shift(18), temps.shift(17), temps.shift(16), temps.shift(15), temps.shift(14), temps.shift(13),
     temps.shift(12), temps.shift(11), temps.shift(10), temps.shift(9), temps.shift(8), temps.shift(7),
     temps.shift(6), temps.shift(5), temps.shift(4), temps.shift(3), temps.shift(2), temps.shift(1), temps,
     temps.shift(-1), temps.shift(-2), temps.shift(-3), temps.shift(-4), temps.shift(-5), temps.shift(-6),
     temps.shift(-7), temps.shift(-8), temps.shift(-9), temps.shift(-10), temps.shift(-11), temps.shift(-12),
     temps.shift(-13), temps.shift(-14), temps.shift(-15), temps.shift(-16), temps.shift(-17), temps.shift(-18),
     temps.shift(-19), temps.shift(-20), temps.shift(-21), temps.shift(-22), temps.shift(-23)], axis=1)

Question is: How can split them? :)

Pandas Split Dataframe into two Dataframes at a specific row

How do I convert a human-readable time such as `20.12.2016 09:38:42,76` to a Unix timestamp in **milliseconds**?

Convert python datetime to timestamp in milliseconds

I want to annotate a type of a variable in a `for`-loop. I tried this but it didn&#39;t work:

```py
for i: int in range(5):
    pass
``` 

What I expect is working autocomplete in PyCharm 2016.3.2, but using
pre-annotation didn&#39;t work:

```py
i: int
for i in range(5):
    pass
```

P.S. Pre-annotation works for PyCharm &gt;= 2017.1.

How do I annotate types in a for-loop?

I am trying to use the betbrain.py from Github (https://github.com/gto76/betbrain-scraper) that has the following code:

    #!/usr/bin/python3
    #
    # Usage: betbrain.py [URL or FILE] [OUTPUT-FILE]
    # Scrapes odds from passed betbrain page and writes them to
    # stdout, or file if specified.
    
    import os
    import sys
    import urllib.request
    
    
    from bs4 import BeautifulSoup
    from http.cookiejar import CookieJar
    
    import parser_betbrain
    import printer
    
    DEFAULT_URL = &#39;https://www.betbrain.com/football/england/premier-league/#!/matches/&#39;
    
    
    # If no arguments are present, it parses the default page.
    # Argument can be an URL or a local file.
    def main():
      html = getHtml(sys.argv)
      soup = BeautifulSoup(html, &quot;html.parser&quot;)
      matches = parser_betbrain.getMatches(soup)
      string = printer.matchesToString(matches)
      output(string, sys.argv)
    
    def getHtml(argv):
      if len(argv) &lt;= 1:
        return scrape(DEFAULT_URL)
      elif argv[1].startswith(&quot;http&quot;):
        return scrape(argv[1])
      else:
        return readFile(argv[1])
    
    # Returns html file located at URL.
    def scrape(url):
      cj = CookieJar()
      opener = urllib.request.build_opener(urllib.request.HTTPCookieProcessor(cj))
      try:
        return opener.open(url)
      except ValueError:
        error(&quot;Invalid URL: &quot; + url)
    
    def readFile(path):
      try:
        return open(path, encoding=&#39;utf8&#39;)
      except IOError:
        error(&quot;Invalid input filename: &quot; + path)
    
    def output(string, argv):
      if len(argv) &lt;= 2:
        print(string)
      else:
        writeFile(argv[2], string)
    
    def writeFile(path, string):
      try:  
        fo = open(path, &quot;w&quot;, encoding=&#39;utf8&#39;)
        fo.write(string);
        fo.close()
      except IOError:
        error(&quot;Invalid output filename: &quot; + path)
    
    def error(msg):
      msg = os.path.basename(__file__)+&quot;: &quot;+msg
      print(msg, file=sys.stderr)
      sys.exit(1)
    
    if __name__ == &#39;__main__&#39;:
      main()

**However when run it comes back with this error**

    Traceback (most recent call last):
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py&quot;, line 1318, in do_open
        encode_chunked=req.has_header(&#39;Transfer-encoding&#39;))
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py&quot;, line 1239, in request
        self._send_request(method, url, body, headers, encode_chunked)
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py&quot;, line 1285, in _send_request
        self.endheaders(body, encode_chunked=encode_chunked)
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py&quot;, line 1234, in endheaders
        self._send_output(message_body, encode_chunked=encode_chunked)
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py&quot;, line 1026, in _send_output
        self.send(msg)
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py&quot;, line 964, in send
        self.connect()
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/http/client.py&quot;, line 1400, in connect
        server_hostname=server_hostname)
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/ssl.py&quot;, line 401, in wrap_socket
        _context=self, _session=session)
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/ssl.py&quot;, line 808, in __init__
        self.do_handshake()
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/ssl.py&quot;, line 1061, in do_handshake
        self._sslobj.do_handshake()
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/ssl.py&quot;, line 683, in do_handshake
        self._sslobj.do_handshake()
    ssl.SSLError: [SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:749)
    
    During handling of the above exception, another exception occurred:
    
    Traceback (most recent call last):
      File &quot;/Users/Daniel/Desktop/betbrain-scraper-master 2/betbrain.py&quot;, line 71, in &lt;module&gt;
        main()
      File &quot;/Users/Daniel/Desktop/betbrain-scraper-master 2/betbrain.py&quot;, line 22, in main
        html = getHtml(sys.argv)
      File &quot;/Users/Daniel/Desktop/betbrain-scraper-master 2/betbrain.py&quot;, line 30, in getHtml
        return scrape(DEFAULT_URL)
      File &quot;/Users/Daniel/Desktop/betbrain-scraper-master 2/betbrain.py&quot;, line 41, in scrape
        return opener.open(url)
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py&quot;, line 526, in open
        response = self._open(req, data)
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py&quot;, line 544, in _open
        &#39;_open&#39;, req)
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py&quot;, line 504, in _call_chain
        result = func(*args)
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py&quot;, line 1361, in https_open
        context=self._context, check_hostname=self._check_hostname)
      File &quot;/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/urllib/request.py&quot;, line 1320, in do_open
        raise URLError(err)
    urllib.error.URLError: &lt;urlopen error [SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:749)&gt;


**How can I fix this problem? I am running Python 3.6.0 on MacOS 10.12.1**

ssl.SSLError: [SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:749)

I am still learning and in response to one of my questions: [here][1], I was told to that it might be due because the element in question is not in view. 

I looked through the documentation and SO, here was the most relevant answer: [here][2]

You can use the &quot;org.openqa.selenium.interactions.Actions&quot; class to move to an element:

    WebElement element = driver.findElement(By.id(&quot;my-id&quot;));
    Actions actions = new Actions(driver);
    actions.moveToElement(element);
    ## actions.click();
    actions.perform();

When I try to use the above to scroll to the element:
It says WebElement not defined.

I think this is because I have not imported the relevant module. Can someone point out what I am supposed to import?

Edit:
As pointed out by alecxe, this was java code.

But in the meantime right after trying to figure it out for some time. I have found out the import method for WebElement:

    from selenium.webdriver.remote.webelement import WebElement

Might help someone like me.

The how of it is also a good lesson, IMO:

Went to: [Documentation][3]
The 

    class selenium.webdriver.remote.webelement.WebElement(parent, id_, w3c=False)

Need to be separated into the command form mentioned above.

  [1]: https://stackoverflow.com/questions/41737321/same-command-works-once-when-executed-but-throws-an-exception-when-executed-a-se?noredirect=1#comment70669855_41737321
  [2]: https://stackoverflow.com/questions/3401343/scroll-element-into-view-with-selenium
  [3]: http://selenium-python.readthedocs.io/api.html#module-selenium.webdriver.remote.webelement

Scrolling to element using webdriver?

How can I replace a character in a string from a certain index? For example, I want to get the middle character from a string, like abc, and if the character is not equal to the character the user specifies, then I want to replace it.

Something like this maybe?
    
    middle = ? # (I don&#39;t know how to get the middle of a string)

    if str[middle] != char:
        str[middle].replace(&#39;&#39;)
        

Replacing a character from a certain index

I am trying to join two pandas data frames using two columns:

    new_df = pd.merge(A_df, B_df,  how=&#39;left&#39;, left_on=&#39;[A_c1,c2]&#39;, right_on = &#39;[B_c1,c2]&#39;)

but got the following error:


    pandas/index.pyx in pandas.index.IndexEngine.get_loc (pandas/index.c:4164)()
    
    pandas/index.pyx in pandas.index.IndexEngine.get_loc (pandas/index.c:4028)()
    
    pandas/src/hashtable_class_helper.pxi in pandas.hashtable.PyObjectHashTable.get_item (pandas/hashtable.c:13166)()
    
    pandas/src/hashtable_class_helper.pxi in pandas.hashtable.PyObjectHashTable.get_item (pandas/hashtable.c:13120)()
    
    KeyError: &#39;[B_1, c2]&#39;

Any idea what should be the right way to do this? Thanks!

pandas: merge (join) two data frames on multiple columns

I am trying to run a module from the console. The structure of my directory is this:

[![enter image description here][1]][1]

I am trying to run the module `p_03_using_bisection_search.py`, from the `problem_set_02` directory using:

    $ python3 p_03_using_bisection_search.py

The code inside `p_03_using_bisection_search.py`is:

    __author__ = &#39;m&#39;
    
    
    from .p_02_paying_debt_off_in_a_year import compute_balance_after
    
    
    def compute_bounds(balance: float,
                       annual_interest_rate: float) -&gt; (float, float):

        # there is code here, but I have omitted it to save space
        pass
    
    
    def compute_lowest_payment(balance: float,
                               annual_interest_rate: float) -&gt; float:

        # there is code here, but I have omitted it to save space
        pass    
    
    def main():
        balance = eval(input(&#39;Enter the initial balance: &#39;))
        annual_interest_rate = eval(input(&#39;Enter the annual interest rate: &#39;))
    
        lowest_payment = compute_lowest_payment(balance, annual_interest_rate)
        print(&#39;Lowest Payment: &#39; + str(lowest_payment))
    
    
    if __name__ == &#39;__main__&#39;:
        main()

I am importing a function that is in `p_02_paying_debt_off_in_a_year.py` which code is:

    __author__ = &#39;m&#39;
    
    
    def compute_balance(balance: float,
                        fixed_payment: float,
                        annual_interest_rate: float) -&gt; float:

        # this is code that has been omitted
        pass
    
    
    def compute_balance_after(balance: float,
                              fixed_payment: float,
                              annual_interest_rate: float,
                              months: int=12) -&gt; float:

        # Omitted code
        pass
    
    
    def compute_fixed_monthly_payment(balance: float,
                                      annual_interest_rate: float) -&gt; float:

        # omitted code
        pass
    
    
    def main():
        balance = eval(input(&#39;Enter the initial balance: &#39;))
        annual_interest_rate = eval(
            input(&#39;Enter the annual interest rate as a decimal: &#39;))
        lowest_payment = compute_fixed_monthly_payment(balance,
                                                       annual_interest_rate)
        print(&#39;Lowest Payment: &#39; + str(lowest_payment))
    
    
    if __name__ == &#39;__main__&#39;:
        main()

I am getting the following error:

    ModuleNotFoundError: No module named &#39;__main__.p_02_paying_debt_off_in_a_year&#39;; &#39;__main__&#39; is not a package

I have no idea how to solve this issue. I have tried adding a `__init__.py` file, but it is still not working.

  [1]: https://i.stack.imgur.com/naRKa.png



ModuleNotFoundError: What does it mean __main__ is not a package?

I am using template strings to generate some files and I love the conciseness of the new f-strings for this purpose, for reducing my previous template code from something like this:
     
    template_a = &quot;The current name is {name}&quot;
    names = [&quot;foo&quot;, &quot;bar&quot;]
    for name in names:
        print (template_a.format(**locals()))

Now I can do this, directly replacing variables:

    names = [&quot;foo&quot;, &quot;bar&quot;]
    for name in names:
        print (f&quot;The current name is {name}&quot;)

However, sometimes it makes sense to have the template defined elsewhere — higher up in the code, or imported from a file or something. This means the template is a static string with formatting tags in it. Something would have to happen to the string to tell the interpreter to interpret the string as a new f-string, but I don&#39;t know if there is such a thing.

**Is there any way to bring in a string and have it interpreted as an f-string to avoid using the `.format(**locals())` call?**

Ideally I want to be able to code like this... (where `magic_fstring_function` is where the part I don&#39;t understand comes in):

    template_a = f&quot;The current name is {name}&quot;
    # OR [Ideal2] template_a = magic_fstring_function(open(&#39;template.txt&#39;).read())
    names = [&quot;foo&quot;, &quot;bar&quot;]
    for name in names:
        print (template_a)

...with this desired output (without reading the file twice):

&lt;!-- language: lang-none --&gt;

    The current name is foo
    The current name is bar

...but the actual output I get is:

&lt;!-- language: lang-none --&gt;

    The current name is {name}
    The current name is {name}

How to postpone/defer the evaluation of f-strings?

I have been examining some of my string format options using the new f-string format.  I routinely need to unpack lists and other iterables of unknown length. Currently I use the following...

    &gt;&gt;&gt; a = [1, &#39;a&#39;, 3, &#39;b&#39;]
    &gt;&gt;&gt; (&quot;unpack a list: &quot; + &quot; {} &quot;*len(a)).format(*a)
    &#39;unpack a list:  1  a  3  b &#39;
This, albeit a bit cumbersome, does the job using pre-3.6 .format notation.
The new f-string format option is interesting given runtime string concatenation.  It is the replication of the number of {} that I am having problems with.  In my previous example, I simply created the necessary structure and unpacked within the .format() section.

Attempts to do this yielded one variant that worked, however:

### 1) Both curly brackets together doesn&#39;t unpack...

    &gt;&gt;&gt; &#39;unpack a list&#39;  f&#39; {{*a}}&#39;
    &#39;unpack a list {*a}&#39;

### 2) Adding spaces around the interior {} pair:

This works but leaves opening and closing braces {, } present:

    &gt;&gt;&gt; &#39;unpack a list&#39;  f&#39; { {*a} }&#39;
    &quot;unpack a list {1, 3, &#39;a&#39;, &#39;b&#39;}&quot;

### 2b) Concatenating the variants into one f-string

This made the look and syntax better, since the evaluation, apparently, is from left to right.  This, however, still left the enclosing curly brackets present:

    &gt;&gt;&gt; f&#39;unpack a list { {*a} }&#39;
    &quot;unpack a list {1, 3, &#39;a&#39;, &#39;b&#39;}&quot;

### 3) Tried automatic unpacking with just `{a}`
Perhaps, I was overthinking the whole procedure and hoping for some form of automatic unpacking.  This simply yielded the list representation with the curly brackets being replaced with `[]` :

    &gt;&gt;&gt; f&#39;unpack a list {a}&#39;
    &quot;unpack a list [1, &#39;a&#39;, 3, &#39;b&#39;]&quot;
    
What is required to suppress the curly brackets in variant (2) above, or must I keep using the existing `.format()` method?  I want to keep it simple and use the new capabilities offered by the f-string and not revert back beyond the python versions which pre-date what I am currently comfortable with.  I am beginning to suspect that f&#39;strings&#39; do not offer a complete coverage of what is offered by its `.format()` sibling.  I will leave it at that for now, since I haven&#39;t even ventured into the escape encoding and the inability to use \ in an f-string.  I have read the PEP and search widely, however, I feel I am missing the obvious or what I wish for is currently not possible.

EDIT several hours later:

### 4) Use subscripting to manually slice off the brackets: `str(a)[1:-2]`

I did find this variant which will serve for some cases that I need

    f&#39;unpack a list: {str(a)[1:-2]}&#39;
    &quot;unpack a list: 1, &#39;a&#39;, 3, &#39;b&quot;

But the slicing is little more than a convenience and still leaves the string quotes around the resultant.

### 5)  and the final solution from @SenhorLucas

     a = np.arange(10)
    
    print(f&quot;{*a,}&quot;)
    (0, 1, 2, 3, 4, 5, 6, 7, 8, 9)

Unpacking with trailing comma.

f-string syntax for unpacking a list with brace suppression

I just installed Python 3.6.1 for MacOS X

When I attempt to run the Console(or run anything with Python3), this error is thrown:

      AttributeError: module &#39;enum&#39; has no attribute &#39;IntFlag&#39;

    $ /Library/Frameworks/Python.framework/Versions/3.6/bin/python3  
    Failed to import the site module  
    Traceback (most recent call last):  
      File &quot;/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site.py&quot;, line 544, in &lt;module&gt;  
        main()  
      File &quot;/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site.py&quot;, line 530, in main  
        known_paths = addusersitepackages(known_paths)  
      File &quot;/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site.py&quot;, line 282, in addusersitepackages  
        user_site = getusersitepackages()  
      File &quot;/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site.py&quot;, line 258, in getusersitepackages  
        user_base = getuserbase() # this will also set USER_BASE  
      File &quot;/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site.py&quot;, line 248, in getuserbase  
        USER_BASE = get_config_var(&#39;userbase&#39;)  
      File &quot;/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6/sysconfig.py&quot;, line 601, in get_config_var  
        return get_config_vars().get(name)  
      File &quot;/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6/sysconfig.py&quot;, line 580, in get_config_vars  
        import _osx_support  
      File &quot;/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6/_osx_support.py&quot;, line 4, in &lt;module&gt;  
        import re  
      File &quot;/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6/re.py&quot;, line 142, in &lt;module&gt;  
        class RegexFlag(enum.IntFlag):  
    AttributeError: module &#39;enum&#39; has no attribute &#39;IntFlag&#39;  

The class IntFlag exists within enum.py. So, why is the AttributeError being thrown?

Why Python 3.6.1 throws AttributeError: module &#39;enum&#39; has no attribute &#39;IntFlag&#39;?

I am getting an error while running this part of the code. I tried some of the existing solutions, but none of them helped.

    elec_and_weather = pd.read_csv(r&#39;C:\HOUR.csv&#39;, parse_dates=True,index_col=0)
    # Add historic DEMAND to each X vector
     for i in range(0,24):
        elec_and_weather[i] = np.zeros(len(elec_and_weather[&#39;DEMAND&#39;]))
        elec_and_weather[i][elec_and_weather.index.hour==i] = 1
    # Set number of hours prediction is in advance
    n_hours_advance = 24

    # Set number of historic hours used
    n_hours_window = 24

    for k in range(n_hours_advance,n_hours_advance+n_hours_window):
        elec_and_weather[&#39;DEMAND_t-%i&#39;% k] = np.zeros(len(elec_and_weather[&#39;DEMAND&#39;]))&#39;


 
I always get this error:

    for i in range(0,24):
    File &quot;&lt;ipython-input-29-db3022a769d1&gt;&quot;, line 1
    for i in range(0,24):
                         ^
    SyntaxError: unexpected EOF while parsing

    File &quot;&lt;ipython-input-25-df0a44131c36&gt;&quot;, line 1
        for k in range(n_hours_advance,n_hours_advance+n_hours_window):
                                                                       ^
    SyntaxError: unexpected EOF while parsing



Content Type	Original Author	Original Content on Stackoverflow
Question	Michael D.	View Question on Stackoverflow
Solution 1 - Python	Dimitris Fasarakis Hilliard	View Answer on Stackoverflow

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