what shebang to use for python scripts run under a pyenv virtualenv

PythonPython 2.7Pyenv

Python Problem Overview


When a python script is supposed to be run from a pyenv virtualenv what is the correct shebang for the file?

As an example test case, the default python on my system (OSX) does not have pandas installed. The pyenv virtualenv venv_name does. I tried getting the path of the python executable from the virtualenv.

$ pyenv activate venv_name
(venv_name)$ which python
/Users/username/.pyenv/shims/python


So I made my example script.py:

#!/Users/username/.pyenv/shims/python
import pandas as pd
print 'success'


But when I tried running the script, I got an error:

(venv_name) $ ./script.py
./script.py: line 2: import: command not found
./script.py: line 3: print: command not found


Although running that path on the command line works fine:

(venv_name) $ /Users/username/.pyenv/shims/python script.py
success

(venv_name) $ python script.py # also works
success

What is the proper shebang for this? Ideally, I want something generic so that it will point at the python of whatever my current venv is.

Python Solutions


Solution 1 - Python

I don't really know why calling the interpreter with the full path wouldn't work for you, I use it all the time, but if you want to use the python interpreter that is in your environment you should do:

#!/usr/bin/env python

That way you search your environment for the python interpreter to use.

Solution 2 - Python

As you expected, you should be able to use the full path to the virtual environment's python in the shebang to choose/control the environment the script runs in regardless of the environment of the controlling script.

In the comments on your question, VPfB & you find that the /Users/username/.pyenv/shims/python is a shell script that does an exec $pyenv_python. You should be able to echo $pyenv_python to determine the real python and use that as your shebang.

See also: https://unix.stackexchange.com/questions/209646/how-to-activate-virtualenv-when-a-python-script-starts

Try pyenv virtualenvs to find a list of virtual environment directories.

And then you might find a using shebang something like this:

#!/Users/username/.pyenv/python/versions/venv_name/bin/python
import pandas as pd
print 'success'

... will enable the script to work using the chosen virtual environment in other (virtual or not) environments:

(venv_name) $ ./script.py 
success
(venv_name) $ pyenv activate non_pandas_venv 
(non_pandas_venv) $ ./script.py
success
(non_pandas_venv) $ . deactivate
$ ./script.py
success
$

The trick is that if you call out the virtual environment's python binary specifically, python looks around that binary's path location for the supporting files and ends up using the surrounding virtual environment. (See per https://stackoverflow.com/questions/8427709/how-does-virtualenv-work )

Solution 3 - Python

If you need to use more shell than you can put in the #! shebang line, you can start the file with a simple shell script which launches Python on the same file.

#!/bin/bash
"exec" "pyenv" "exec" "python" "$0" "$@"
# the rest of your Python script can be written below

Because of the quoting, Python doesn't execute the first line, and instead joins the strings together for the module docstring... which effectively ignores it.

You can see more here.

Solution 4 - Python

It's not exactly answering the Q, but this suggestion by ephiement I think is a much better way to do what you want. I've elaborated a bit and added some more of an explanation as to how this works and how you can dynamically select the python to use:

#!/bin/sh
#
# Choose the python we need. Explanation:
# a) '''\' translates to \ in shell, and starts a python multi-line string
# b) "" strings are treated as string concat by python, shell ignores them
# c) "true" command ignores its arguments
# c) exit before the ending ''' so the shell reads no further
# d) reset set docstrings to ignore the multiline comment code
#
"true" '''\'
PREFERRED_PYTHON=/Library/Frameworks/Python.framework/Versions/2.7/bin/python
ALTERNATIVE_PYTHON=/Library/Frameworks/Python.framework/Versions/3.6/bin/python3
FALLBACK_PYTHON=python3

if [ -x $PREFERRED_PYTHON ]; then
    echo Using preferred python $ALTERNATIVE_PYTHON
    exec $PREFERRED_PYTHON "$0" "$@"
elif [ -x $ALTERNATIVE_PYTHON ]; then
    echo Using alternative python $ALTERNATIVE_PYTHON
    exec $ALTERNATIVE_PYTHON "$0" "$@"
else
    echo Using fallback python $FALLBACK_PYTHON
    exec python3 "$0" "$@"
fi
exit 127
'''

__doc__ = """What this file does"""
print(__doc__)
import platform
print(platform.python_version())

Solution 5 - Python

To expand to this answer, yes in 99% of case if you have a python in your environment you can just use:

#!/usr/bin/env python

However for a custom venv on linux following the same syntax did not work for me since the venv created a link to the python interpreter which the venv was created from so I had to do the following:

#!/path/to/the/venv/bin/python

Essentially however you are able to call python on your terminal is what you would put after #!.

Solution 6 - Python

if you want just a single script with a simple selection of your pyenv virtualenv you may use a bash script with your source as 'here document' as follows:

#!/bin/bash
PYENV_VERSION=<your_pyenv_virtualenv_name> python - $@ <<EOF
import sys
print(sys.argv)
exit
EOF

I did some additional testing. The following works too:

#!/usr/bin/env -S PYENV_VERSION=<virtual_env_name> python

Solution 7 - Python

maybe you need to check the file privileges:

sudo chmod +x script.py

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