What is the Python 3 equivalent of "python -m SimpleHTTPServer"
PythonPython 3.xHttpserverSimplehttpserverPython Problem Overview
What is the Python 3 equivalent of python -m SimpleHTTPServer?
Python Solutions
Solution 1 - Python
From the docs:
> The SimpleHTTPServer module has been merged into http.server in Python 3.0. The 2to3 tool will automatically adapt imports when converting your sources to 3.0.
So, your command is python -m http.server, or depending on your installation, it can be:
python3 -m http.server
Solution 2 - Python
The equivalent is:
python3 -m http.server
Solution 3 - Python
Using 2to3 utility.
$ cat try.py
import SimpleHTTPServer
$ 2to3 try.py
RefactoringTool: Skipping implicit fixer: buffer
RefactoringTool: Skipping implicit fixer: idioms
RefactoringTool: Skipping implicit fixer: set_literal
RefactoringTool: Skipping implicit fixer: ws_comma
RefactoringTool: Refactored try.py
--- try.py (original)
+++ try.py (refactored)
@@ -1 +1 @@
-import SimpleHTTPServer
+import http.server
RefactoringTool: Files that need to be modified:
RefactoringTool: try.py
Like many *nix utils, 2to3 accepts stdin if the argument passed is -. Therefore, you can test without creating any files like so:
$ 2to3 - <<< "import SimpleHTTPServer"
Solution 4 - Python
In addition to Petr's answer, if you want to bind to a specific interface instead of all the interfaces you can use -b or --bind flag.
python -m http.server 8000 --bind 127.0.0.1
The above snippet should do the trick. 8000 is the port number. 80 is used as the standard port for HTTP communications.
Solution 5 - Python
As everyone has mentioned http.server module is equivalent to python -m SimpleHTTPServer.
But as a warning from https://docs.python.org/3/library/http.server.html#module-http.server
> Warning: http.server is not recommended for production. It only implements basic security checks.
Usage
http.server can also be invoked directly using the -m switch of the interpreter.
python -m http.server
The above command will run a server by default on port number 8000. You can also give the port number explicitly while running the server
python -m http.server 9000
The above command will run an HTTP server on port 9000 instead of 8000.
> By default, server binds itself to all interfaces. The option > -b/--bind specifies a specific address to which it should bind. Both IPv4 and IPv6 addresses are supported. For example, the following > command causes the server to bind to localhost only:
python -m http.server 8000 --bind 127.0.0.1
or
python -m http.server 8000 -b 127.0.0.1
Python 3.8 version also supports IPv6 in the bind argument.
Directory Binding
By default, server uses the current directory. The option -d/--directory specifies a directory to which it should serve the files. For example, the following command uses a specific directory:
python -m http.server --directory /tmp/
Directory binding is introduced in python 3.7
Solution 6 - Python
In one of my projects I run tests against Python 2 and 3. For that I wrote a small script which starts a local server independently:
$ python -m $(python -c 'import sys; print("http.server" if sys.version_info[:2] > (2,7) else "SimpleHTTPServer")')
Serving HTTP on 0.0.0.0 port 8000 ...
As an alias:
$ alias serve="python -m $(python -c 'import sys; print("http.server" if sys.version_info[:2] > (2,7) else "SimpleHTTPServer")')"
$ serve
Serving HTTP on 0.0.0.0 port 8000 ...
Please note that I control my Python version via conda environments, because of that I can use python instead of python3 for using Python 3.
Solution 7 - Python
Just wanted to add what worked for me:
python3 -m http.server 8000 (you can use any port number here except the ones which are currently in use)