With the XML being

    &lt;x:html xmlns:x=&quot;http://www.w3.org/1999/xhtml&quot;/&gt;

the stylesheet

    &lt;xsl:stylesheet
      xmlns:xsl=&quot;http://www.w3.org/1999/XSL/Transform&quot;
      version=&quot;1.0&quot;&gt;
      
      &lt;xsl:output indent=&quot;yes&quot;/&gt;
      
      &lt;xsl:template match=&quot;*&quot;&gt;
        &lt;local-name&gt;&lt;xsl:value-of select=&quot;local-name()&quot;/&gt;&lt;/local-name&gt;
        &lt;name&gt;&lt;xsl:value-of select=&quot;name()&quot;/&gt;&lt;/name&gt;
      &lt;/xsl:template&gt;
    
    &lt;/xsl:stylesheet&gt;

outputs

    &lt;local-name&gt;html&lt;/local-name&gt;
    &lt;name&gt;x:html&lt;/name&gt;

So the `local-name()` result is without any prefix, `the name()` result might include a prefix.

In your sample with a default namespace declaration no prefix is present, therefore `name()` and `local-name()` give the same result.

I want to put all the requirements of a repoze Zope2 install in a pip [requirements file][1]. Most of the repoze packages don&#39;t seem to be on PyPi, but there&#39;s an alternative PyPi index for them [here][2]. But I can&#39;t figure out how to tell pip to use that index together with a requirements file. For single packages, it&#39;s easy

    pip install zopelib -i http://dist.repoze.org/zope2/2.10/simple/

I tried the following

    pip install -r requirements.txt -i http://dist.repoze.org/zope2/2.10/simple/

or in my requirements.txt all kind or permutations of these:

    zopelib -i http://dist.repoze.org/zope2/2.10/simple/
    zopelib --index http://dist.repoze.org/zope2/2.10/simple/
    -i http://dist.repoze.org/zope2/2.10/simple/ zopelib

or (because the [documentation][3] says &quot;Note that all these options must be on a line of their own.&quot;)

    --index http://dist.repoze.org/zope2/2.10/simple/
    zopelib

So, what&#39;s the correct way of telling pip to use http://dist.repoze.org/zope2/2.10/simple/ as index?


  [1]: http://pip.readthedocs.org/en/1.1/requirements.html#the-requirements-file-format
  [2]: http://dist.repoze.org/zope2/2.10/simple/
  [3]: https://pip.readthedocs.org/en/1.1/requirements.html#indexes-find-links

pip requirements.txt with alternative index

More specifically, how do you model a functional program, or one developed using the Functional Style (without classes) using a diagram, and not textual representation.

Can UML be used to model a Functional program?

I don&#39;t really understand the difference between the XPath functions [`name`](http://www.w3.org/TR/xpath/#function-name) and [`local-name`](http://www.w3.org/TR/xpath/#function-local-name).

Could you give an example of a situation where they would differ?

Edit
---

Given this example:

    &lt;?xml version=&quot;1.0&quot; ?&gt;
    &lt;html xmlns=&quot;http://www.w3.org/1999/xhtml&quot; xml:lang=&quot;en&quot; lang=&quot;en&quot;&gt;
      &lt;head&gt;&lt;/head&gt;
    &lt;/html&gt;

I get the same result with these two queries: `//*[local-name()=&quot;head&quot;]` and `//*[name()=&quot;head&quot;]`. Why is that?

What is the difference between name() and local-name()?

I don't really understand the difference between the XPath functions <a href="http://www.w3.org/TR/xpath/#function-name" target="_blank" rel="noopener noreferrer"><code>name</code></a> and <a href="http://www.w3.org/TR/xpath/#function-local-name" target="_blank" rel="noopener noreferrer"><code>local-name</code></a>.
Could you give an example of a situation where they would differ?
<h4 id="edit"><a aria-hidden="true" tabindex="-1" href="#edit"></a>Edit</h4>
Given this example:
<pre><code class="hljs language-xml">&#x3C;?xml version="1.0" ?>
&#x3C;html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
 &#x3C;head>&#x3C;/head>
&#x3C;/html>
</code></pre>
I get the same result with these two queries: <code>//*[local-name()="head"]</code> and <code>//*[name()="head"]</code>. Why is that?

I have made an XML Schema - all the code basically - and was wondering if there is a way that the code can generate something like this:

![enter image description here][1]

If so how can I do it?


  [1]: http://i.stack.imgur.com/54TGZ.gif

How to visualize an XML schema programatically?

I&#39;m getting the error:

`parser error : Input is not proper UTF-8, indicate encoding ! Bytes: 0xED 0x6E 0x2C 0x20`

When trying to process an XML response using `simplexml_load_string` from a 3rd party source. The raw XML response does declare the content type:

`&lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt; `

Yet it seems that the XML is not really UTF-8. The langauge of the XML content is Spanish and contain words like `Dubl&#237;n` in the XML.

I&#39;m unable to get the 3rd party to sort out their XML.

How can I pre-process the XML and fix the encoding incompatibilities?

Is there a way to detect the correct encoding for a XML file?

Error: &quot;Input is not proper UTF-8, indicate encoding !&quot; using PHP&#39;s simplexml_load_string

We are using a *PropertyPlaceholderConfigurer* to use java properties in our Spring configuration ([details here][1])

eg:

    &lt;foo name=&quot;port&quot;&gt;
      &lt;value&gt;${my.server.port}&lt;/value&gt;
    &lt;/foo&gt;

We would like to add an additional property, but have a distributed system where existing instances could all use a default value.  Is there a way to avoid updating all of our properties files, by indicating a default value in the Spring config for when there isn&#39;t an overriding property value defined?

  [1]: http://static.springsource.org/spring/docs/2.5.x/reference/beans.html#beans-factory-placeholderconfigurer

Is there a way to specify a default property value in Spring XML?

Is there a way that I can specify a triangle shape in an XML file?

    &lt;shape xmlns:android=&quot;http://schemas.android.com/apk/res/android&quot; android:shape=&quot;triangle&quot;&gt;
      &lt;stroke android:width=&quot;1dip&quot; android:color=&quot;#FFF&quot; /&gt;
      &lt;solid android:color=&quot;#FFF&quot; /&gt;
    &lt;/shape&gt;

Can we do this with a path shape or something? I just need an equilateral triangle.

Thanks

Making a triangle shape using XML definitions?

I&#39;d like to be able to read an XML file uploaded by the user (less than 100kb), but not have to first save that file to the database.  I don&#39;t need that file past the current action (its contents get parsed and added to the database; however, parsing the file is not the problem).  Since local files can be read with:

    File.read(&quot;export.opml&quot;)
I thought about just creating a file_field for :uploaded_file, then trying to read it with

    File.read(params[:uploaded_file])
but all that does is throw a TypeError (can&#39;t convert HashWithIndifferentAccess into String).  I really have tried a lot of various things (including reading from the /tmp directory as well), but could get none of them to work.  

I hope the brevity of my question doesn&#39;t mask the effort I&#39;ve given to try to solve this on my own, but I didn&#39;t want to pollute this question with a hundred ways of how NOT to get it done.  Big thanks to anyone who chimes in.


Here is my view:

    &lt;% form_for(:uploaded_file, @feed, :url =&gt; {:action=&gt;&#39;parse&#39;}, :html=&gt; {:multipart=&gt;true}) do |f| %&gt;  &lt;p&gt;
      	&lt;%= f.label :uploaded_file, &#39;Upload your file.&#39; %&gt;&lt;br /&gt;
      	&lt;%= f.file_field :uploaded_file %&gt;
      &lt;/p&gt;
      &lt;p&gt;&lt;%= f.submit &#39;upload&#39; %&gt;&lt;/p&gt;
    &lt;% end %&gt;

I set up a custom action (upload) which handles the file_field upload, which after submission, is passed off to another custom action (parse) for processing.  Could this be a part of my problem?

how to read a User uploaded file, without saving it to the database

I&#39;m trying to do a xpath lookup on nodes returned by xpath lookup, but it doesn&#39;t seem to work as I expected.XPaths executed on the child nodes of a document seem to be executd against hthe root node of the document (in the example, the inventory tag.), instead of the root of the provided node.

Am I missing something here? I&#39;m new to XPath.

Also, please don&#39;t answer &quot;just do //book[author=&#39;Neal Stephenson&#39;/title&quot;. I have a legitimate use case, and this is a simplified example.



Code snippet

    DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
    domFactory.setNamespaceAware(true);
    DocumentBuilder builder = domFactory.newDocumentBuilder();
    Document doc = builder.parse(&quot;src/main/java/books.xml&quot;);

    XPathFactory factory = XPathFactory.newInstance();
    XPath xpath = factory.newXPath();

    Node book = (Node) xpath.evaluate(&quot;//book[author=&#39;Neal Stephenson&#39;]&quot;, doc, XPathConstants.NODE);
    Node title = (Node) xpath.evaluate(&quot;/title&quot;, book, XPathConstants.NODE); // I get null here.
    Node inventory = (Node) xpath.evaluate(&quot;/inventory&quot;, book, XPathConstants.NODE); // this returns a node.


book.xml

	&lt;inventory&gt;
	&lt;book year=&quot;2000&quot;&gt;
		&lt;title&gt;Snow Crash&lt;/title&gt;
		&lt;author&gt;Neal Stephenson&lt;/author&gt;
		&lt;publisher&gt;Spectra&lt;/publisher&gt;
		&lt;isbn&gt;0553380958&lt;/isbn&gt;
		&lt;price&gt;14.95&lt;/price&gt;
	&lt;/book&gt;

	&lt;book year=&quot;2005&quot;&gt;
		&lt;title&gt;Burning Tower&lt;/title&gt;
		&lt;author&gt;Larry Niven&lt;/author&gt;
		&lt;author&gt;Jerry Pournelle&lt;/author&gt;
		&lt;publisher&gt;Pocket&lt;/publisher&gt;
		&lt;isbn&gt;0743416910&lt;/isbn&gt;
		&lt;price&gt;5.99&lt;/price&gt;
	&lt;/book&gt;

	&lt;book year=&quot;1995&quot;&gt;
		&lt;title&gt;Zodiac&lt;/title&gt;
		&lt;author&gt;Neal Stephenson&lt;/author&gt;
		&lt;publisher&gt;Spectra&lt;/publisher&gt;
		&lt;isbn&gt;0553573862&lt;/isbn&gt;
		&lt;price&gt;7.50&lt;/price&gt;
	&lt;/book&gt;

	&lt;!-- more books... --&gt;

	&lt;/inventory&gt;

Running XPath on child node

How can I ignore first element and get rest of the elements?

    &lt;ul&gt;
      &lt;li&gt;&lt;a href=&quot;#&quot;&gt;some link&lt;/a&gt;&lt;/li&gt;
      &lt;li&gt;&lt;a href=&quot;#&quot;&gt;some link 2&lt;/a&gt;&lt;/li&gt;
      &lt;li&gt;&lt;a href=&quot;#&quot;&gt;link i want to find&lt;/a&gt;&lt;/li&gt;
    &lt;/ul&gt;

Thanks

How to ignore first element in xpath

Is there anyway to return an XPath string of a DOM element in Javascript?

Javascript get XPath of a node

I want to read XML data using XPath in Java, so for the information I have gathered I am not able to parse XML according to my requirement.

here is what I want to do:

**Get XML file from online via its URL, then use XPath to parse it, I want to create two methods in it. One is in which I enter a specific node attribute id, and I get all the child nodes as result, and second is suppose I just want to get a specific child node value only**

    &lt;?xml version=&quot;1.0&quot;?&gt;
    &lt;howto&gt;
      &lt;topic name=&quot;Java&quot;&gt;
          &lt;url&gt;http://www.rgagnonjavahowto.htm&lt;/url&gt;
      &lt;car&gt;taxi&lt;/car&gt;
      &lt;/topic&gt;
      &lt;topic name=&quot;PowerBuilder&quot;&gt;
           &lt;url&gt;http://www.rgagnon/pbhowto.htm&lt;/url&gt;
           &lt;url&gt;http://www.rgagnon/pbhowtonew.htm&lt;/url&gt;
      &lt;/topic&gt;
      &lt;topic name=&quot;Javascript&quot;&gt;
            &lt;url&gt;http://www.rgagnon/jshowto.htm&lt;/url&gt;
      &lt;/topic&gt;
     &lt;topic name=&quot;VBScript&quot;&gt;
           &lt;url&gt;http://www.rgagnon/vbshowto.htm&lt;/url&gt;
     &lt;/topic&gt;
     &lt;/howto&gt;


In above example I want to read all the elements if I search via @name and also one function in which I just want the url from @name &#39;Javascript&#39; only return one node element.

How to read XML using XPath in Java

For example, for the XML below

    &lt;CATALOG&gt;
    	&lt;CD title=&quot;Empire Burlesque&quot;/&gt;
    	&lt;CD title=&quot;empire burlesque&quot;/&gt;
    	&lt;CD title=&quot;EMPIRE BURLESQUE&quot;/&gt;
    	&lt;CD title=&quot;EmPiRe BuRLeSQuE&quot;/&gt;
        &lt;CD title=&quot;Others&quot;/&gt;
    &lt;CATALOG&gt;
How to match the first 4 records with xpath like `//CD[@title=&#39;empire burlesque&#39;]`. Is there xpath function to do this? Other solutions like PHP function are also accepted.

Content Type	Original Author	Original Content on Stackoverflow
Question	troelskn	View Question on Stackoverflow
Solution 1 - Xml	Martin Honnen	View Answer on Stackoverflow

What is the difference between name() and local-name()?

Xml Problem Overview

Edit

Xml Solutions

Solution 1 - Xml

Can UML be used to model a Functional program?

pip requirements.txt with alternative index

Attributions