What happens if a Android Service is started multiple times?
AndroidAndroid Problem Overview
If I have the following code:
Intent intent = new Intent(this,DownloadService.class);
for(int i=0;i<filesArray.length;i++){
startService(intent);
}
In this code DownloadService
extends IntentService
.
So now when I'm calling startService(intent)
does that mean that I'm starting a new service every time startService(intent)
is called or does that mean that DownloadService
is run once and then each time I call startService(intent)
it will just pass a different intent with a different startId.
Does this make sense, and which one of these is the case ?
Android Solutions
Solution 1 - Android
The Service will only run in one instance. However, everytime you start the service, the onStartCommand()
method is called.
This is documented here
Solution 2 - Android
Absolutely Correct.
Only one instance of Service is created for an application process.
And when you call StartService();
again, then only onStartCommand()
gets called and new Intent is passed to onStartCommand()
method.
Note: onCreate()
is not called again.
About calling bindService()
multiple times:
When you call bindService()
multiple times, then again only one instance is used for Service and Android Runtime returns same IBinder object to client.
Means, onBind()
is not called multiple times. And just cached IBinder object is returned.
Solution 3 - Android
Adding some more information to the above answers which may be helpful for others is that, startId
that the onStartCommand()
method receives is different for every startService()
call.
Also if we write in for loop as mentioned above, code written in onHandleIntent()
would execute so many times as defined by the for loop frequency, but in sequence and not in parallel.
The concept is IntentService
creates a work queue and each request to startService()
trigger onStartCommand()
which in turn stores the intent in work queue and then pass the intent one by one to onHandleIntent()
.
Solution 4 - Android
According to the doc: > The startService() method returns immediately, and the Android system calls the service's onStartCommand() method. If the service isn't already running, the system first calls onCreate(), and then it calls onStartCommand().
and > Multiple requests to start the service result in multiple corresponding calls to the service's onStartCommand(). However, only one request to stop the service (with stopSelf() or stopService()) is required to stop it.
Solution 5 - Android
Very helpful comments from Android official docs:
(highlighted by me)
> If your service handles multiple requests to onStartCommand()
concurrently, you shouldn't stop the service when you're done processing a start request, as you might have received a new start request (stopping at the end of the first request would terminate the second one). To avoid this problem, you can use stopSelf(int)
to ensure that your request to stop the service is always based on the most recent start request. That is, when you call stopSelf(int)
, you pass the ID of the start request (the startId delivered to onStartCommand()
) to which your stop request corresponds. Then, if the service receives a new start request before you are able to call stopSelf(int), the ID doesn't match and the service doesn't stop.