Means that these numbers are doubles and floats, respectively. Assume you have

    void foo(int x);
    void foo(float x);
    void foo(double x);

and then you call

    foo(5)

the compiler might be stumped. That&#39;s why you can say `5`, `5f`, or `5.0` to specify the type.



D stands for double 

F for float 

you can read up on the basic primitive types of java here 

http://download.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html

I would like to point out that writing

5.1D or 5.1 : if you don&#39;t specify a type letter for a comma number then by default it is double

5 : without the period, by default it is an int

They&#39;re format specifiers for float and double literals.  When you write `1.0`, it&#39;s ambiguous as to whether you intend the literal to be a float or double.  By writing `1.0f`, you&#39;re telling Java that you intend the literal to be a float, while using `1.0d` specifies that it should be a double.  There&#39;s also `L`, which represents long (e.g., `1L` is a `long` 1, as opposed to an `int` 1)

D stands for double and F stands for float.  You will occasionally need to add these modifiers, as 5 is considered an integer in this case, and 3.0 is a double.

As others have mentioned they are the Type definitions, however you will less likely see i or d mentioned as these are the defaults.

    float myfloat = 0.5; 

will error as the 0.5 is a double as default and you cannot autobox down from double to float (64 -&gt; 32 bits) but

    double mydouble = 0.5;

will have no problem

It defines the datatype for the constants 5 and 3.0.   

**Working of foreach:**
As I know, 

&gt; **foreach is a loop which iterates through a collection or array one by
&gt; one, starting from 0 index till the
&gt; last item of the collection.**
  
So, if I have n items in an array.

    foreach (var item in arr)
    {

    }  
then, 
In, 1st iteration, **item=arr[0];**  
then, in 2nd,      **item=arr[1];**  
.  
.  
.  
in last (nth),  **item=arr[n-1];**

**Conclusion:** from working it seems that at each iteration it knows that which value to be taken from array or it knows the index of the item to be taken from array.

**Now my question:** How can I get index of an item without using a new variable?

    foreach (string item in mylist)
    {
       if (item == &quot;myitem&quot;)
       {
           // get index of item
           break;
       }
    }


Counter in foreach loop in C#

What can a `DockPanel` do that a `StackPanel` cannot? If anyone has an image of something that can be achieved with a `StackPanel`, but not a `DockPanel`, than that would be great.

What is the difference between a StackPanel and DockPanel in WPF?

I&#39;ve seen some of this symbols, but I cannot find anything strange with it,

    double d = 5D;
    float f = 3.0F;

What does the D and F behind 5 exactly means?

What do F and D mean at the end of numeric literals?

I've seen some of this symbols, but I cannot find anything strange with it,
<pre><code class="hljs language-ini">double d = 5D;
float f = 3.0F;
</code></pre>
What does the D and F behind 5 exactly means?

I have a method that takes an InputStream and reads data from it. I would like to use this method with a ByteBuffer also. Is there a way to wrap a ByteBuffer so it can be accessed as a stream?

Wrapping a ByteBuffer with an InputStream

Is there a way to tell what is the current Eclipse workspace you are currently working on?

How to tell Eclipse Workspace?

Hibernate throws this exception during SessionFactory creation:

&gt; org.hibernate.loader.MultipleBagFetchException: cannot simultaneously fetch multiple bags

This is my test case:

**Parent.java**

    @Entity
    public Parent {
     
     @Id
     @GeneratedValue(strategy=GenerationType.IDENTITY)
     private Long id;
    
     @OneToMany(mappedBy=&quot;parent&quot;, fetch=FetchType.EAGER)
     // @IndexColumn(name=&quot;INDEX_COL&quot;) if I had this the problem solve but I retrieve more children than I have, one child is null.
     private List&lt;Child&gt; children;
    
    }
    

**Child.java**

    @Entity
    public Child {
     
     @Id
     @GeneratedValue(strategy=GenerationType.IDENTITY)
     private Long id;
    
     @ManyToOne
     private Parent parent;
    
    }

How about this problem? What can I do?


----------


**EDIT**

OK, the problem I have is that another &quot;parent&quot; entity is inside my parent, my real behavior is this:

**Parent.java**

    @Entity
    public Parent {
     
     @Id
     @GeneratedValue(strategy=GenerationType.IDENTITY)
     private Long id;

     @ManyToOne
     private AnotherParent anotherParent;
    
     @OneToMany(mappedBy=&quot;parent&quot;, fetch=FetchType.EAGER)
     private List&lt;Child&gt; children;
    
    }

**AnotherParent.java**

    @Entity
    public AnotherParent {
     
     @Id
     @GeneratedValue(strategy=GenerationType.IDENTITY)
     private Long id;
    
     @OneToMany(mappedBy=&quot;parent&quot;, fetch=FetchType.EAGER)
     private List&lt;AnotherChild&gt; anotherChildren;
    
    }

Hibernate doesn&#39;t like two collections with `FetchType.EAGER`, but this seems to be a bug, I&#39;m not doing unusual things...

Removing `FetchType.EAGER` from `Parent` or `AnotherParent` solves the problem, but I need it, so real solution is to use `@LazyCollection(LazyCollectionOption.FALSE)` instead of `FetchType` (thanks to [Bozho][1] for the solution).


  [1]: https://stackoverflow.com/users/203907/bozho

Hibernate throws MultipleBagFetchException - cannot simultaneously fetch multiple bags

As we know, Android apps are written in Java. In Java, no matter [what you do][1], it is impossible to protect compiled code from decompilation or reverse-engineering, as the Stack Overflow question *[How to lock compiled Java classes to prevent decompilation?][2]* suggests.

How would one go about protecting an app that contains algorithmic trade secrets from reverse-engineering?

By &quot;how&quot; I mean not only software techniques, but also other **creative** approaches.

  [1]: http://www.galkonline.com/2010/09/15/how-to-prevent-java-from-being-decompiled/
  [2]: https://stackoverflow.com/questions/49379/how-to-lock-compiled-java-classes-to-prevent-decompilation


Is it really impossible to protect Android apps from reverse engineering?

I&#39;ve got a file in my war/WEB-INF folder of my app engine project. I read in the FAQs that you can read a file from there in a servlet context. I don&#39;t know how to form the path to the resource though:

    /war/WEB-INF/test/foo.txt

How would I construct my path to that resource to use with File(), just as it looks above?

Thanks

File path to resource in our war/WEB-INF folder?

I have two integers `x` and `y`. I need to calculate `x/y` and as outcome I would like to get float. For example as an outcome of `3/2` I would like to have 1.5. I thought that easiest (or the only) way to do it is to convert `x` and `y` into float type. Unfortunately, I cannot find an easy way to do it. Could you please help me with that?

How can I convert integer into float in Java?

I have the following code. I would like to have it such that if price_result equals an integer, let&#39;s say 10, then I would like to add two decimal places. So 10 would be 10.00.
Or if it equals 10.6 would be 10.60. Not sure how to do this.

    price_result = parseFloat(test_var.split(&#39;$&#39;)[1].slice(0,-1));



How to parse float with two decimal places in javascript?

I have float numbers like `3.2` and `1.6`.

I need to separate the number into the integer and decimal part. For example, a value of `3.2` would be split into two numbers, i.e. `3` and `0.2`

Getting the integer portion is easy:

    n = Math.floor(n);

But I am having trouble getting the decimal portion.
I have tried this:

    remainder = n % 2; //obtem a parte decimal do rating

But it does not always work correctly.

The previous code has the following output:

    n = 3.1 // gives remainder = 1.1

What I am missing here?

Get decimal portion of a number with JavaScript

Suppose I have `8.8333333333333339`, and I want to convert it to `8.84`. How can I accomplish this in Python?

`round(8.8333333333333339, 2)` gives `8.83` and not `8.84`. I am new to Python or programming in general.

I don&#39;t want to print it as a string, and the result will be further used. For more information on the problem, please check *[Tim Wilson&#39;s Python Programming Tips: Loan and payment calculator][1]*.

  [1]: http://openbookproject.net/pybiblio/practice/wilson/loan.php




How to round a floating point number up to a certain decimal place?

I am reading &quot;accelerated C++&quot;. I found one sentence which states &quot;sometimes `double` is faster in execution than `float` in C++&quot;. After reading sentence I got confused about `float` and `double` working. Please explain this point to me. 

double or float, which is faster?

What are the values of a double/float on iOS, or the file that they&#39;re defined in? Or a macro, like INT_MAX?


What is the max. value of a double/float on iOS?

Usually when I write anything in C++ and I need to convert a `char` into an `int` I simply make a new `int` equal to the char. 

I used the code(snippet) 


     string word;  
     openfile &gt;&gt; word;
     double lol=word;


I receive the error that 

    Code1.cpp cannot convert `std::string&#39; to `double&#39; in initialization 

What does the error mean exactly? The first word is the number 50. Thanks :)

C++ string to double conversion

So I have a double set to equal 1234, I want to move a decimal place over to make it 12.34

So to do this I multiply .1 to 1234 two times, kinda like this

    double x = 1234;
    for(int i=1;i&lt;=2;i++)
    {
      x = x*.1;
    }
    System.out.println(x);

This will print the result, &quot;12.340000000000002&quot;

Is there a way, without simply formatting it to two decimal places, to have the double store 12.34 correctly?


Moving decimal places over in a double

How do I format a Double with `String.format` to String with a dot between the integer and decimal part?

    String s = String.format(&quot;%.2f&quot;, price);

The above formats only with a comma: &quot;,&quot;.

Content Type	Original Author	Original Content on Stackoverflow
Question	Ben C.	View Question on Stackoverflow
Solution 1 - Java	EboMike	View Answer on Stackoverflow
Solution 2 - Java	Jason Rogers	View Answer on Stackoverflow
Solution 3 - Java	Jeff	View Answer on Stackoverflow
Solution 4 - Java	Ronnie Howell	View Answer on Stackoverflow
Solution 5 - Java	Theresa Forster	View Answer on Stackoverflow
Solution 6 - Java	Joshua Martell	View Answer on Stackoverflow

What do F and D mean at the end of numeric literals?

Java Problem Overview

Java Solutions

Solution 1 - Java

Solution 2 - Java

Solution 3 - Java

Solution 4 - Java

Solution 5 - Java

Solution 6 - Java

What is the difference between a StackPanel and DockPanel in WPF?

Counter in foreach loop in C#

Attributions