Using Python and BeautifulSoup (saved webpage source codes into a local file)

I am using Python 2.7 + BeautifulSoup 4.3.2.

I am trying to use Python and BeautifulSoup to pick up information on a webpage. Because the webpage is in the company website and requires login and redirection, I copied the target page's source code page into a file and saved it as “example.html” in C:\ for the convenience of practicing.

This is a part of the original code:

<tr class="ghj">
	<td><span class="city-sh"><sh src="./citys/1.jpg" alt="boy" title="boy" /></span><a href="./membercity.php?mode=view&amp;u=12563">port_new_cape</a></td>
	<td class="position"><a href="./search.php?id=12563&amp;sr=positions" title="Search positions">452</a></td>
	<td class="details"><div>South</div></td>
	<td>May 09, 1997</td>
	<td>Jan 23, 2009 12:05 pm&nbsp;</td>
</tr>

The code I worked out so far is:

from bs4 import BeautifulSoup
import re
import urllib2

url = "C:\example.html"
page = urllib2.urlopen(url)
soup = BeautifulSoup(page.read())

cities = soup.find_all('span', {'class' : 'city-sh'})

for city in cities:
print city

This is just the first stage of testing, so it's somewhat incomplete.

However, when I run it, it gives an error message. Seems it’s improper to use urllib2.urlopen to open a local file.

 Traceback (most recent call last):
   File "C:\Python27\Testing.py", line 8, in <module>
     page = urllib2.urlopen(url)
   File "C:\Python27\lib\urllib2.py", line 127, in urlopen
     return _opener.open(url, data, timeout)
   File "C:\Python27\lib\urllib2.py", line 404, in open
     response = self._open(req, data)
   File "C:\Python27\lib\urllib2.py", line 427, in _open
     'unknown_open', req)
   File "C:\Python27\lib\urllib2.py", line 382, in _call_chain
     result = func(*args)
   File "C:\Python27\lib\urllib2.py", line 1247, in unknown_open
     raise URLError('unknown url type: %s' % type)
 URLError: <urlopen error unknown url type: c>

How can I practice using a local file?

The best way to open a local file with BeautifulSoup is to pass it a file handler directly. http://www.crummy.com/software/BeautifulSoup/bs4/doc/#making-the-soup

from bs4 import BeautifulSoup

with open("C:\\example.html") as fp:
    soup = BeautifulSoup(fp, 'html.parser')

for city in soup.find_all('span', {'class' : 'city-sh'}):
    print(city)

With Chandan's help, the problem has been solved. All the credits shall go to him. :)

the "urllib2.url" is useless here.

from bs4 import BeautifulSoup
import re
# import urllib2

url = "C:\example.html"
page = open(url)
soup = BeautifulSoup(page.read())

cities = soup.find_all('span', {'class' : 'city-sh'})

for city in cities:
    print city

You can try using lxml parser also. Here is an example for your html data.

from lxml.html import fromstring
import lxml.html as PARSER
    
data = open('example.html').read()
root = PARSER.fromstring(data)

for ele in root.getiterator():
	if ele.tag == "td":
		print ele.text_content()

o/p: port_new_cape 452 South May 09, 1997 Jan 23, 2009 12:05 pm