Using NSPredicate to filter an NSArray based on NSDictionary keys

I have an array of dictionaries.

I want to filter the array based on a key.

I tried this:

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(SPORT ==  %@)", @"Football"];

NSArray *filteredArray = [data filteredArrayUsingPredicate:predicate];

This doesn't work, I get no results. I think I'm doing something wrong. I know this is the method if "SPORT" was an ivar. I think it is probably different if it is a key.

I haven't been able to find an example however.

Thanks

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Update

I added quotes around the string I am searching for.

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(SPORT ==  '%@')", @"Football"];

It still does not work.

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Update 2

Solved it. I actually had to remove the single quotes, which seems to go against what the guide says.

My real problem is I had a nested array and I wasn't actually evaluating the dictionaries. Bone head move.

It should work - as long as the data variable is actually an array containing a dictionary with the key SPORT

NSArray *data = [NSArray arrayWithObject:[NSMutableDictionary dictionaryWithObject:@"foo" forKey:@"BAR"]];    
NSArray *filtered = [data filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(BAR == %@)", @"foo"]];

Filtered in this case contains the dictionary.

(the %@ does not have to be quoted, this is done when NSPredicate creates the object.)

I know it's old news but to add my two cents. By default I use the commands LIKE[cd] rather than just [c]. The [d] compares letters with accent symbols. This works especially well in my Warcraft App where people spell their name "Vòódòó" making it nearly impossible to search for their name in a tableview. The [d] strips their accent symbols during the predicate. So a predicate of @"name LIKE[CD] %@", object.name where object.name == @"voodoo" will return the object containing the name Vòódòó.

From the Apple documentation: like[cd] means “case- and diacritic-insensitive like.”) For a complete description of the string syntax and a list of all the operators available, see Predicate Format String Syntax.

#import <Foundation/Foundation.h>
// clang -framework Foundation Siegfried.m 
	int
main() {
	NSArray *arr = @[
		@{@"1" : @"Fafner"},
		@{@"1" : @"Fasolt"}
	];
	NSPredicate *p = [NSPredicate predicateWithFormat:
		@"SELF['1'] CONTAINS 'e'"];
	NSArray *res = [arr filteredArrayUsingPredicate:p];
	NSLog(@"Siegfried %@", res);
	return 0;
}

NSPredicate is only available in iPhone 3.0.

You won't notice that until try to run on device.

With Swift 3, when you want to filter an array of dictionaries with a predicate based on dictionary keys and values, you may choose one of the following patterns.

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#1. Using NSPredicate init(format:arguments:) initializer

If you come from Objective-C, init(format:arguments:) offers a key-value coding style to evaluate your predicate.

Usage:

import Foundation

let array = [["key1": "value1", "key2": "value2"], ["key1": "value3"], ["key3": "value4"]]

let predicate = NSPredicate(format: "key1 == %@", "value1")
//let predicate = NSPredicate(format: "self['key1'] == %@", "value1") // also works
let filteredArray = array.filter(predicate.evaluate)

print(filteredArray) // prints: [["key2": "value2", "key1": "value1"]]

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#2. Using NSPredicate init(block:) initializer

As an alternative if you prefer strongly typed APIs over stringly typed APIs, you can use init(block:) initializer.

Usage:

import Foundation

let array = [["key1": "value1", "key2": "value2"], ["key1": "value3"], ["key3": "value4"]]

let dictPredicate = NSPredicate(block: { (obj, _) in
    guard let dict = obj as? [String: String], let value = dict["key1"] else { return false }
    return value == "value1"
})

let filteredArray = array.filter(dictPredicate.evaluate)
print(filteredArray) // prints: [["key2": "value2", "key1": "value1"]]

Looking at the NSPredicate reference, it looks like you need to surround your substitution character with quotes. For example, your current predicate reads: (SPORT == Football) You want it to read (SPORT == 'Football'), so your format string needs to be @"(SPORT == '%@')".