Use a LIKE statement on SQL Server XML Datatype

SqlSql ServerXmlSql Server-2005

Sql Problem Overview


If you have a varchar field you can easily do SELECT * FROM TABLE WHERE ColumnA LIKE '%Test%' to see if that column contains a certain string.

How do you do that for XML Type?

I have the following which returns only rows that have a 'Text' node but I need to search within that node

select * from WebPageContent where data.exist('/PageContent/Text') = 1

Sql Solutions


Solution 1 - Sql

Yet another option is to cast the XML as nvarchar, and then search for the given string as if the XML vas a nvarchar field.

SELECT * 
FROM Table
WHERE CAST(Column as nvarchar(max)) LIKE '%TEST%'

I love this solution as it is clean, easy to remember, hard to mess up, and can be used as a part of a where clause.

This might not be the best performing solution, so think twice before deplying it to production. It is however very usefull for a quick debug session, which is where I mostly use it.

EDIT: As Cliff mentions it, you could use:

> ...nvarchar if there's characters that don't convert to varchar

Solution 2 - Sql

You should be able to do this quite easily:

SELECT * 
FROM WebPageContent 
WHERE data.value('(/PageContent/Text)[1]', 'varchar(100)') LIKE 'XYZ%'

The .value method gives you the actual value, and you can define that to be returned as a VARCHAR(), which you can then check with a LIKE statement.

Mind you, this isn't going to be awfully fast. So if you have certain fields in your XML that you need to inspect a lot, you could:

  • create a stored function which gets the XML and returns the value you're looking for as a VARCHAR()
  • define a new computed field on your table which calls this function, and make it a PERSISTED column

With this, you'd basically "extract" a certain portion of the XML into a computed field, make it persisted, and then you can search very efficiently on it (heck: you can even INDEX that field!).

Marc

Solution 3 - Sql

Another option is to search the XML as a string by converting it to a string and then using LIKE. However as a computed column can't be part of a WHERE clause you need to wrap it in another SELECT like this:

SELECT * FROM
    (SELECT *, CONVERT(varchar(MAX), [COLUMNA]) as [XMLDataString] FROM TABLE) x
WHERE [XMLDataString] like '%Test%'

Solution 4 - Sql

This is what I am going to use based on marc_s answer:

SELECT 
SUBSTRING(DATA.value('(/PAGECONTENT/TEXT)[1]', 'VARCHAR(100)'),PATINDEX('%NORTH%',DATA.value('(/PAGECONTENT/TEXT)[1]', 'VARCHAR(100)')) - 20,999)

FROM WEBPAGECONTENT 
WHERE COALESCE(PATINDEX('%NORTH%',DATA.value('(/PAGECONTENT/TEXT)[1]', 'VARCHAR(100)')),0) > 0

Return a substring on the search where the search criteria exists

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionJonView Question on Stackoverflow
Solution 1 - SqlSquazzView Answer on Stackoverflow
Solution 2 - Sqlmarc_sView Answer on Stackoverflow
Solution 3 - SqlCarl OnagerView Answer on Stackoverflow
Solution 4 - SqlJonView Answer on Stackoverflow