updating table rows in postgres using subquery

SqlPostgresqlSubquerySql Update

Sql Problem Overview


Using postgres 8.4, My goal is to update existing table:

CREATE TABLE public.dummy
(
  address_id SERIAL,
  addr1 character(40),
  addr2 character(40),
  city character(25),
  state character(2),
  zip character(5),
  customer boolean,
  supplier boolean,
  partner boolean
  
)
WITH (
  OIDS=FALSE
);

Initially i tested my query using insert statement:

insert into address customer,supplier,partner
SELECT  
	case when cust.addr1 is not null then TRUE else FALSE end customer, 
	case when suppl.addr1 is not null then TRUE else FALSE end supplier,
	case when partn.addr1 is not null then TRUE else FALSE end partner
from (
	SELECT *
		from address) pa
	left outer join cust_original cust
		on (pa.addr1=cust.addr1 and pa.addr2=cust.addr2 and pa.city=cust.city 
			and pa.state=cust.state and substring(cust.zip,1,5) = pa.zip  )
	left outer join supp_original suppl 
		on (pa.addr1=suppl.addr1 and pa.addr2=suppl.addr2 and pa.city=suppl.city 
			    and pa.state=suppl.state and pa.zip = substring(suppl.zip,1,5))
	left outer join partner_original partn
		on (pa.addr1=partn.addr1 and pa.addr2=partn.addr2 and pa.city=partn.city
			      and pa.state=partn.state and pa.zip = substring(partn.zip,1,5) )
where pa.address_id = address_id

being Newbie I'm failing converting to update statement ie., updating existing rows with values returned by select statement. Any help is highly appreciated.

Sql Solutions


Solution 1 - Sql

Postgres allows:

UPDATE dummy
SET customer=subquery.customer,
    address=subquery.address,
    partn=subquery.partn
FROM (SELECT address_id, customer, address, partn
      FROM  /* big hairy SQL */ ...) AS subquery
WHERE dummy.address_id=subquery.address_id;

This syntax is not standard SQL, but it is much more convenient for this type of query than standard SQL. I believe Oracle (at least) accepts something similar.

Solution 2 - Sql

You're after the UPDATE FROM syntax.

UPDATE 
  table T1  
SET 
  column1 = T2.column1 
FROM 
  table T2 
  INNER JOIN table T3 USING (column2) 
WHERE 
  T1.column2 = T2.column2;

References

Solution 3 - Sql

If there are no performance gains using a join, then I prefer Common Table Expressions (CTEs) for readability:

WITH subquery AS (
    SELECT address_id, customer, address, partn
    FROM  /* big hairy SQL */ ...
)
UPDATE dummy
SET customer = subquery.customer,
    address  = subquery.address,
    partn    = subquery.partn
FROM subquery
WHERE dummy.address_id = subquery.address_id;

IMHO a bit more modern.

Solution 4 - Sql

There are many ways to update the rows.

When it comes to UPDATE the rows using subqueries, you can use any of these approaches.

  1. Approach-1 [Using direct table reference]
UPDATE
  <table1>
SET
  customer=<table2>.customer,
  address=<table2>.address,
  partn=<table2>.partn
FROM
  <table2>
WHERE
  <table1>.address_id=<table2>.address_i;

> Explanation: table1 is the table which we want to update, table2 > is the table, from which we'll get the value to be replaced/updated. > We are using FROM clause, to fetch the table2's data. WHERE > clause will help to set the proper data mapping.

  1. Approach-2 [Using SubQueries]
UPDATE
  <table1>
SET
  customer=subquery.customer,
  address=subquery.address,
  partn=subquery.partn
FROM
  (
    SELECT
      address_id, customer, address, partn
    FROM  /* big hairy SQL */ ...
  ) AS subquery
WHERE
  dummy.address_id=subquery.address_id;

> Explanation: Here we are using subquerie inside the FROM clause, > and giving an alias to it. So that it will act like the table.

  1. Approach-3 [Using multiple Joined tables]
UPDATE
  <table1>
SET
  customer=<table2>.customer,
  address=<table2>.address,
  partn=<table2>.partn
FROM
  <table2> as t2
  JOIN <table3> as t3
  ON
    t2.id = t3.id
WHERE
  <table1>.address_id=<table2>.address_i;

> Explanation: Sometimes we face the situation in that table join is so > important to get proper data for the update. To do so, Postgres allows > us to Join multiple tables inside the FROM clause.

  1. Approach-4 [Using WITH statement]
  • 4.1 [Using simple query]
WITH subquery AS (
    SELECT
      address_id,
      customer,
      address,
      partn
    FROM
      <table1>;
)
UPDATE <table-X>
SET customer = subquery.customer,
    address  = subquery.address,
    partn    = subquery.partn
FROM subquery
WHERE <table-X>.address_id = subquery.address_id;
  • 4.2 [Using query with complex JOIN]
WITH subquery AS (
    SELECT address_id, customer, address, partn
    FROM
      <table1> as t1
    JOIN
      <table2> as t2
    ON
      t1.id = t2.id;
    -- You can build as COMPLEX as this query as per your need.
)
UPDATE <table-X>
SET customer = subquery.customer,
    address  = subquery.address,
    partn    = subquery.partn
FROM subquery
WHERE <table-X>.address_id = subquery.address_id;

> Explanation: From Postgres 9.1, this(WITH) concept has been > introduces. Using that We can make any complex queries and generate > desire result. Here we are using this approach to update the table.

I hope, this would be helpful..

Solution 5 - Sql

@Mayur "4.2 [Using query with complex JOIN]" with Common Table Expressions (CTEs) did the trick for me.

WITH cte AS (
SELECT e.id, e.postcode
FROM employees e
LEFT JOIN locations lc ON lc.postcode=cte.postcode
WHERE e.id=1
)
UPDATE employee_location SET lat=lc.lat, longitude=lc.longi
FROM cte
WHERE employee_location.id=cte.id;

Hope this helps... :D

Solution 6 - Sql

update json_source_tabcol as d
set isnullable = a.is_Nullable
from information_schema.columns as a 
where a.table_name =d.table_name 
and a.table_schema = d.table_schema 
and a.column_name = d.column_name;

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
QuestionstackoverView Question on Stackoverflow
Solution 1 - SqlAndrew LazarusView Answer on Stackoverflow
Solution 2 - SqlBrian WebsterView Answer on Stackoverflow
Solution 3 - SqlsteeveeView Answer on Stackoverflow
Solution 4 - SqlMayurView Answer on Stackoverflow
Solution 5 - SqlFestus NgorView Answer on Stackoverflow
Solution 6 - SqlPugazendhi AsaimuthuView Answer on Stackoverflow