UIView's border color in Interface builder doesn't work?

IosObjective CSwiftCocoa TouchUiview

Ios Problem Overview


I am trying to set up a view's layer properties via IB. Everything works except for color of the border (property layer.borderColor):

enter image description here

I remember running into this problem a year ago and I ended up doing it programatically. And still, I can do this programmatically, but I am curious why the layer.borderColorproperty never works via interface builder. I don't want to import QuartzCore, and then write extra line of code just because of this, seems like an overkill.

Ios Solutions


Solution 1 - Ios

It's possible to do this, but it's not a built-in feature. This is because the Color type in the User Defined Runtime Attributes panel creates a UIColor, but layer.borderColor holds a CGColorRef type. Unfortunately, there's no way to assign a CGColorRef type in Interface Builder.

However, this is possible through a proxy property. See Peter DeWeese's answer to a different question for a possible solution to this problem. His answer defines a category that allows a proxy color to be set through Interface Builder.

Solution 2 - Ios

You have to create Category for CALayer:

CALayer+UIColor.h

#import <QuartzCore/QuartzCore.h>
#import <UIKit/UIKit.h>

@interface CALayer(UIColor)

// This assigns a CGColor to borderColor.
@property(nonatomic, assign) UIColor* borderUIColor;

@end

CALayer+UIColor.m

#import "CALayer+UIColor.h"

@implementation CALayer(UIColor)

- (void)setBorderUIColor:(UIColor*)color {
    self.borderColor = color.CGColor;
}

- (UIColor*)borderUIColor {
    return [UIColor colorWithCGColor:self.borderColor];
}

@end

And then in User Defined Runtime attributes You can use it as it is on image below:

enter image description here

For Swift it is much more simple:

import QuartzCore

extension CALayer {
    @IBInspectable var borderUIColor: UIColor? {
        get {
            guard let borderColor = borderColor else { return nil }
            return UIColor(cgColor: borderColor)
        }
        
        set {
            borderColor = newValue?.cgColor
        }
    }
}

Then in Xcode you can use it like this:

enter image description here

Once you choose sth it is automatically added to your runtime attributes:

Solution 3 - Ios

Copy and paste this class:

import UIKit

@IBDesignable class BorderView : UIView {
    @IBInspectable var borderColor: UIColor = .clear {
        didSet {
        layer.borderColor = borderColor.cgColor
        }
    }

    @IBInspectable var borderWidth: CGFloat = 0 {
        didSet {
            layer.borderWidth = borderWidth
        }
    }

    @IBInspectable var cornerRadius: CGFloat = 0 {
        didSet {
            layer.cornerRadius = cornerRadius
        }
    }
}

Now in Interface Builder, go to the Identity inspector and set your view as a CustomView class.

After that, check out your Attributes Inspector:

Attributes inspector with the new IBInspectable options

No need to mess around with user defined runtime attributes anymore. And your changes will also show up on the canvas!

Solution 4 - Ios

My two cents for porting Bartłomiej Semańczyk's answer to Swift:

Create an extension for CALayer in your view controller:

import UIKit

extension CALayer {
    func borderUIColor() -> UIColor? {
        return borderColor != nil ? UIColor(CGColor: borderColor!) : nil
    }

    func setBorderUIColor(color: UIColor) {
        borderColor = color.CGColor
    }
}

Solution 5 - Ios

Use IBDesignable instead of Runtime Attributes it is more clear.

Put this code in any class and edit the properties direct on the storyboard.

import UIKit

@IBDesignable extension UIView {
    @IBInspectable var borderColor:UIColor? {
        set {
            layer.borderColor = newValue!.CGColor
        }
        get {
            if let color = layer.borderColor {
                return UIColor(CGColor:color)
            }
            else {
                return nil
            }
        }
    }
    @IBInspectable var borderWidth:CGFloat {
        set {
            layer.borderWidth = newValue
        }
        get {
            return layer.borderWidth
        }
    }
    @IBInspectable var cornerRadius:CGFloat {
        set {
            layer.cornerRadius = newValue
            clipsToBounds = newValue > 0
        }
        get {
            return layer.cornerRadius
        }
    }
}

Solution 6 - Ios

Here's a quick way to overcome this. Categories...

@interface UIView (IBAppearance)

@property (nonatomic, strong) UIColor *borderColor;

@end

You don't have to store it, it's just nice so you can query later. The important thing is taking the value and assigning the UIColor's CGColor to the layer.

#import <objc/runtime.h>

#define BORDER_COLOR_KEYPATH @"borderColor"

@implementation UIView (IBAppearance)

- (void)setBorderColor:(UIColor *)borderColor {
    UIColor *bc = objc_getAssociatedObject(self, BORDER_COLOR_KEYPATH);
    if(bc == borderColor) return;
    else {
        objc_setAssociatedObject(self, BORDER_COLOR_KEYPATH, borderColor, OBJC_ASSOCIATION_RETAIN_NONATOMIC);
        self.layer.borderColor = [borderColor CGColor];
    }
}

- (UIColor *)borderColor {
    return objc_getAssociatedObject(self, BORDER_COLOR_KEYPATH);
}

@end

Of course, in the Interface Builder you're not setting the value on layer.borderColor, rather just on borderColor.

Solution 7 - Ios

In Swift, you can extend the UIButton class and add an @IBInspectable that will enable you to select a color from storyboard and set it's color (with width of 1 which can be changed). Add this at the end of your view controller:

extension UIButton{
    @IBInspectable var borderColor: UIColor? {
        get {
            return UIColor(CGColor: layer.borderColor!)
        }
        set {
            layer.borderColor = newValue?.CGColor
            layer.borderWidth = 1
        }
    }
}

Solution 8 - Ios

In order to make CALayer KVC-compliant for the property borderColorFromUIColor, simply implement the

layer.borderColorFromUIColor=[UIColor red];

This link have awnser

Solution 9 - Ios

I met the same issue, I worked around it by creating a custom button class:

class UIButtonWithRoundBorder: UIButton {

required init?(coder aDecoder: NSCoder) {
    super.init(coder: aDecoder)
    self.layer.cornerRadius = 6
    self.layer.borderWidth = 1
    self.layer.borderColor = UIColor.whiteColor().CGColor
    self.clipsToBounds = true
}

}

Then in IB, change the type from "UIButton" to "UIButtonWithRoundBorder".

Simple and handy too. :)

Solution 10 - Ios

swift4

extension CALayer {

  open override func setValue(_ value: Any?, forKey key: String) {
   
    /// If key is borderColor, and the value is the type of a UIColor.
     if key == "borderColor" , let color = value as? UIColor {
     
        /// After converting UIColor to CGColor, call the system method.
        return super.setValue(color.cgColor, forKey: key)
     }
    
     super.setValue(value, forKey: key)
   }
}

Solution 11 - Ios

borderColor will not work UNLESS the borderWidth property of the layer is set to a value greater than 0.

Swift 3:

button.layer.borderColor = UIColor.white.cgColor
button.layer.borderWidth = 1.0 // Default value is 0, that's why omitting this line will not make the border color show.

Solution 12 - Ios

I think it may be because you have masksToBounds set to YES. I don't think the border is drawn within the bounds of the layer, so it won't be drawn since you're hiding everything outside of its bounds.

Solution 13 - Ios

You can set a value for the "borderColor" key in the XIB and use:

extension UIView {

    open override func setValue(_ value: Any?, forKey key: String) {
        guard key == "borderColor", let color = value as? UIColor else {
            super.setValue(value, forKey: key)
            return
        }

        layer.borderColor = color.cgColor
    }
}

Solution 14 - Ios

You can customise border with 2 methods. First one is this. Just click on the object go to the identity inspector and set the attributes.

enter image description here

Second one is this. make an IBOutlet of required object and put this code in view did load.

@IBOutlet weak var uploadView: UIView!
    
    override func viewDidLoad() {
        super.viewDidLoad()

        uploadView.layer.cornerRadius = 10
        uploadView.layer.borderWidth = 1.0
        uploadView.layer.borderColor = #colorLiteral(red: 0.08235294118, green: 0.5058823529, blue: 0.9450980392, alpha: 1)
    }

Solution 15 - Ios

Swift 5.2 - Answer of Fede Henze's

@IBDesignable extension UIView {

@IBInspectable var borderColor:UIColor? {
    set {
        layer.borderColor = newValue!.cgColor
    }
    get {
        if let color = layer.borderColor {
            return UIColor(cgColor:color)
        }
        else {
            return nil
        }
    }
}
@IBInspectable var borderWidth:CGFloat {
    set {
        layer.borderWidth = newValue
    }
    get {
        return layer.borderWidth
    }
}
@IBInspectable var cornerRadius:CGFloat {
    set {
        layer.cornerRadius = newValue
        clipsToBounds = newValue > 0
    }
    get {
        return layer.cornerRadius
    }
}
}

Solution 16 - Ios

try this in User Defined Runtime attribute:

  1. Key Path: layer.borderUIColor
  2. type: Color
  3. Value: --you prefered color--

Attributions

All content for this solution is sourced from the original question on Stackoverflow.

The content on this page is licensed under the Attribution-ShareAlike 4.0 International (CC BY-SA 4.0) license.

Content TypeOriginal AuthorOriginal Content on Stackoverflow
Question0xSinaView Question on Stackoverflow
Solution 1 - IosmopsledView Answer on Stackoverflow
Solution 2 - IosBartłomiej SemańczykView Answer on Stackoverflow
Solution 3 - IosetayluzView Answer on Stackoverflow
Solution 4 - IosEduardoView Answer on Stackoverflow
Solution 5 - IosFedeHView Answer on Stackoverflow
Solution 6 - IosbainfuView Answer on Stackoverflow
Solution 7 - IosHusseinBView Answer on Stackoverflow
Solution 8 - IosMohitView Answer on Stackoverflow
Solution 9 - IosRainCastView Answer on Stackoverflow
Solution 10 - IoszhengView Answer on Stackoverflow
Solution 11 - IosMallocView Answer on Stackoverflow
Solution 12 - IosChris CView Answer on Stackoverflow
Solution 13 - IosŁukasz KalbarczykView Answer on Stackoverflow
Solution 14 - IosAkbar KhanView Answer on Stackoverflow
Solution 15 - IosPrakashView Answer on Stackoverflow
Solution 16 - IosDilip MView Answer on Stackoverflow