Two arrays in foreach loop

PhpArraysForeach

Php Problem Overview

I want to generate a selectbox using two arrays, one containing the country codes and another containing the country names.

This is an example:

<?php
    $codes = array('tn','us','fr');
    $names = array('Tunisia','United States','France');

    foreach( $codes as $code and $names as $name ) {
        echo '<option value="' . $code . '">' . $name . '</option>';
    }
?>

This method didn't work for me. Any suggestions?

Php Solutions

Solution 1 - Php

foreach( $codes as $code and $names as $name ) { }

That is not valid.

You probably want something like this...

foreach( $codes as $index => $code ) {
   echo '<option value="' . $code . '">' . $names[$index] . '</option>';
}

Alternatively, it'd be much easier to make the codes the key of your $names array...

$names = array(
   'tn' => 'Tunisia',
   'us' => 'United States',
   ...
);

Solution 2 - Php

foreach operates on only one array at a time.

The way your array is structured, you can array_combine() them into an array of key-value pairs then foreach that single array:

foreach (array_combine($codes, $names) as $code => $name) {
    echo '<option value="' . $code . '">' . $name . '</option>';
}

Or as seen in the other answers, you can hardcode an associative array instead.

Solution 3 - Php

Use http://php.net/manual/en/function.array-combine.php">`array_combine()`</a> to fuse the arrays together and iterate over the result.

$countries = array_combine($codes, $names);

Solution 4 - Php

Use an associative array:

$code_names = array(
                    'tn' => 'Tunisia',
                    'us' => 'United States',
                    'fr' => 'France');

foreach($code_names as $code => $name) {
   //...
}

I believe that using an associative array is the most sensible approach as opposed to using array_combine() because once you have an associative array, you can simply use array_keys() or array_values() to get exactly the same array you had before.

Solution 5 - Php

array_map seems good for this too

$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');

array_map(function ($code, $name) {
    echo '<option value="' . $code . '">' . $name . '</option>';
}, $codes, $names);

Other benefits are:

  • If one array is shorter than the other, the callback receive null values to fill in the gap.

  • You can use more than 2 arrays to iterate through.

Solution 6 - Php

This worked for me:

$codes = array('tn', 'us', 'fr');
$names = array('Tunisia', 'United States', 'France');
foreach($codes as $key => $value) {
    echo "Code is: " . $codes[$key] . " - " . "and Name: " . $names[$key] . "<br>";
}

Solution 7 - Php

Your code like this is incorrect as foreach only for single array:

<?php
        $codes = array('tn','us','fr');
        $names = array('Tunisia','United States','France');
    
        foreach( $codes as $code and $names as $name ) {
            echo '<option value="' . $code . '">' . $name . '</option>';
            }
?>

Alternative, Change to this:

<?php
        $codes = array('tn','us','fr');
        $names = array('Tunisia','United States','France');
        $count = 0;

        foreach($codes as $code) {
	         echo '<option value="' . $code . '">' . $names[count] . '</option>';
	         $count++;
        }

?>

Solution 8 - Php

Why not just consolidate into a multi-dimensional associative array? Seems like you are going about this wrong:

$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');

becomes:

$dropdown = array('tn' => 'Tunisia', 'us' => 'United States', 'fr' => 'France');

Solution 9 - Php

You can use array_merge to combine two arrays and then iterate over them.

$array1 = array("foo" => "bar");
$array2 = array("hello" => "world");
$both_arrays = array_merge((array)$array1, (array)$array2);
print_r($both_arrays);

Solution 10 - Php

All fully tested

3 ways to create a dynamic dropdown from an array.

This will create a dropdown menu from an array and automatically assign its respective value.

Method #1 (Normal Array)
<?php

$names = array('tn'=>'Tunisia','us'=>'United States','fr'=>'France');

echo '<select name="countries">';

foreach($names AS $let=>$word){
    echo '<option value="'.$let.'">'.$word.'</option>';
}
echo '</select>';
 
?>
Method #2 (Normal Array)
<select name="countries">

<?php

$countries = array('tn'=> "Tunisia", "us"=>'United States',"fr"=>'France');
foreach($countries as $select=>$country_name){
echo '<option value="' . $select . '">' . $country_name . '</option>';
}
?>

</select>
Method #3 (Associative Array)
<?php

$my_array = array(
     'tn' => 'Tunisia',
     'us' => 'United States',
     'fr' => 'France'
);

echo '<select name="countries">';
echo '<option value="none">Select...</option>';
foreach ($my_array as $k => $v) {
    echo '<option value="' . $k . '">' . $v . '</option>';
}
echo '</select>';
?>

Solution 11 - Php

Walk it out...

$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');

  • PHP 5.3+

     array_walk($codes, function ($code,$key) use ($names) { 
     echo '<option value="' . $code . '">' . $names[$key] . '</option>';
 });

  • Before PHP 5.3

     array_walk($codes, function ($code,$key,$names){ 
     echo '<option value="' . $code . '">' . $names[$key] . '</option>';
 },$names);

  • or combine

     array_walk(array_combine($codes,$names), function ($name,$code){ 
     echo '<option value="' . $code . '">' . $name . '</option>';
 })

  • in select

     array_walk(array_combine($codes,$names), function ($name,$code){ 
     @$opts = '<option value="' . $code . '">' . $name . '</option>';
 })
 echo "<select>$opts</select>";

[demo][1]

[1]: http://www.tehplayground.com/#Bvp1GQRbS "demo"

Solution 12 - Php

<?php

$codes = array ('tn','us','fr');
$names = array ('Tunisia','United States','France');

echo '<table>';

foreach(array_keys($codes) as $i) {

     echo '<tr><td>';
     echo ($i + 1);
     echo '</td><td>';
     echo $codes[$i];
     echo '</td><td>';
     echo $names[$i];
     echo '</td></tr>';
}

echo '</table>';

?>

Solution 13 - Php

foreach only works with a single array. To step through multiple arrays, it's better to use the each() function in a while loop:

while(($code = each($codes)) && ($name = each($names))) {
    echo '<option value="' . $code['value'] . '">' . $name['value'] . '</option>';
}

each() returns information about the current key and value of the array and increments the internal pointer by one, or returns false if it has reached the end of the array. This code would not be dependent upon the two arrays having identical keys or having the same sort of elements. The loop terminates when one of the two arrays is finished.

Solution 14 - Php

Instead of foreach loop, try this (only when your arrays have same length).

$number = COUNT($_POST["codes "]);//count how many arrays available
if($number > 0)  
{  
  for($i=0; $i<$number; $i++)//loop thru each arrays
  {
    $codes =$_POST['codes'][$i];
    $names =$_POST['names'][$i];
    //ur code in here
  }
}

Solution 15 - Php

array_combine() worked great for me while combining $_POST multiple values from multiple form inputs in an attempt to update products quantities in a shopping cart.

Solution 16 - Php

I think that you can do something like:

$codes = array('tn','us','fr');

$names = array('Tunisia','United States','France');

foreach ($codes as $key => $code) {
    echo '<option value="' . $code . '">' . $names[$key] . '</option>';
}

It should also work for associative arrays.

Solution 17 - Php

I think the simplest way is just to use the for loop this way:

$codes = array('tn','us','fr');
$names = array('Tunisia','United States','France');

for($i = 0; $i < sizeof($codes); $i++){
    echo '<option value="' . $codes[$i] . '">' . $names[$i] . '</option>';
}

Solution 18 - Php

if(isset($_POST['doors'])=== true){
$doors = $_POST['doors'];
}else{$doors = 0;}

if(isset($_POST['windows'])=== true){
$windows = $_POST['windows'];
}else{$windows = 0;}

foreach($doors as $a => $b){

Now you can use $a for each array....

$doors[$a]
$windows[$a]
....
}

Solution 19 - Php

I solved a problem like yours by this way:

foreach(array_keys($idarr) as $i) {
 echo "Student ID: ".$idarr[$i]."<br />";
 echo "Present: ".$presentarr[$i]."<br />";
 echo "Reason: ".$reasonarr[$i]."<br />";
 echo "Mark: ".$markarr[$i]."<br />";
}

Solution 20 - Php

You should try this for the putting 2 array in singlr foreach loop Suppose i have 2 Array 1.$item_nm 2.$item_qty

 `<?php $i=1; ?>
<table><tr><td>Sr.No</td> <td>item_nm</td>  <td>item_qty</td>    </tr>
 
  @foreach (array_combine($item_nm, $item_qty) as $item_nm => $item_qty)
<tr> 
        <td> $i++  </td>
        <td>  $item_nm  </td>
        <td> $item_qty  </td>
   </tr></table>

@endforeach `

Solution 21 - Php

Few arrays can also be iterated like this:

foreach($array1 as $key=>$val){ // Loop though one array
    $val2 = $array2[$key]; // Get the values from the other arrays
    $val3 = $array3[$key];
    $result[] = array( //Save result in third array
      'id' => $val,
      'quant' => $val2,
      'name' => $val3,
    );
  }

Solution 22 - Php

This will only work if the both array have same count.I try in laravel, for inserting both array in mysql db

$answer = {"0":"0","1":"1","2":"0","3":"0","4":"1"};
$reason_id = {"0":"17","1":"19","2":"15","3":"19","4":"18"};

        $k= (array)json_decode($answer);
        $x =(array)json_decode($reason_id);
        $number = COUNT(json_decode($reason_id, true));
        if($number > 0)  
        {  
        for($i=0; $i<$number; $i++)
        {
            $val = new ModelName();
            $val->reason_id  = $x[$i];
            $val->answer  =$k[$i];
            $val->save();
        }
        }

Solution 23 - Php

it works for me

$counter = 0;
foreach($codes as $code)
{
$codes_array[$counter]=$code;
$counter++;
}
$counter = 0;
foreach($names as $name)
{
echo $codes_array[$counter]."and".$name;
$counter++;
}
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