Trigger change event of dropdown

I want to trigger the change event of dropdown in $(document).ready using jquery.

I have a cascading dropdown for country and state in user details page. how can i set the value (which is taken from DB based on the user id) for country and state in MVC with C#.

I don't know that much JQuery but I've heard it allows to fire native events with this syntax.

$(document).ready(function(){

    $('#countrylist').change(function(e){
       // Your event handler
    });

    // And now fire change event when the DOM is ready
    $('#countrylist').trigger('change');
});

You must declare the change event handler before calling trigger() or change() otherwise it won't be fired. Thanks for the mention @LenielMacaferi.

More information here.

Try this:

$(document).ready(function(event) {
    $('#countrylist').change(function(e){
         // put code here
     }).change();
});

Define the change event, and trigger it immediately. This ensures the event handler is defined before calling it.

Might be late to answer the original poster, but someone else might benefit from the shorthand notation, and this follows jQuery's chaining, etc

jquery chaining

Try this:

$('#id').change();

Works for me.

On one line together with setting the value: $('#id').val(16).change();

If you are trying to have linked drop downs, the best way to do it is to have a script that returns the a prebuilt select box and an AJAX call that requests it.

Here is the documentation for jQuery's Ajax method if you need it.

$(document).ready(function(){

    $('#countrylist').change(function(e){
    	$this = $(e.target);
    	$.ajax({
	    	type: "POST",
	    	url: "scriptname.asp", // Don't know asp/asp.net at all so you will have to do this bit
	    	data: { country: $this.val() },
	    	success:function(data){
	    		$('#stateBoxHook').html(data);
		    }
	    });
    });

});

Then have a span around your state select box with the id of "stateBoxHook"

alternatively you can put onchange attribute on the dropdownlist itself, that onchange will call certain jquery function like this.

<input type="dropdownlist" onchange="jqueryFunc()">

<script type="text/javascript">
$(function(){
    jqueryFunc(){
        //something goes here
    }
});
</script>

hope this one helps you, and please note that this code is just a rough draft, not tested on any ide. thanks

For some reason, the other jQuery solutions provided here worked when running the script from console, however, it did not work for me when triggered from Chrome Bookmarklets.

Luckily, this Vanilla JS solution (the triggerChangeEvent function) did work:

/**
  * Trigger a `change` event on given drop down option element.
  * WARNING: only works if not already selected.
  * @see https://stackoverflow.com/questions/902212/trigger-change-event-of-dropdown/58579258#58579258
  */
function triggerChangeEvent(option) {
  // set selected property
  option.selected = true;
  
  // raise event on parent <select> element
  if ("createEvent" in document) {
    var evt = document.createEvent("HTMLEvents");
    evt.initEvent("change", false, true);
    option.parentNode.dispatchEvent(evt);
  }
  else {
    option.parentNode.fireEvent("onchange");
  }
}

// ################################################
// Setup our test case
// ################################################

(function setup() {
  const sel = document.querySelector('#fruit');
  sel.onchange = () => {
    document.querySelector('#result').textContent = sel.value;
  };
})();

function runTest() {
  const sel = document.querySelector('#selector').value;
  const optionEl = document.querySelector(sel);
  triggerChangeEvent(optionEl);
}

<select id="fruit">
  <option value="">(select a fruit)</option>
  <option value="apple">Apple</option>
  <option value="banana">Banana</option>
  <option value="pineapple">Pineapple</option>
</select>

<p>
  You have selected: <b id="result"></b>
</p>
<p>
  <input id="selector" placeholder="selector" value="option[value='banana']">
  <button onclick="runTest()">Trigger select!</button>
</p>